Constructions and Tilings | FIO

Question 18

Make your own arch designs.

Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution
Understand the Question
  • Arches are strong curved structures constructed using geometry and circular arcs.
  • We can design three classic types of arches:
    • Semicircular Arch: A half-circle where the radius is half the span.
    • Pointed (Gothic) Arch: Two intersecting circular arcs where each arc's radius equals the full span.
    • Segmental Arch: A flatter arch forming a circular segment with its center located below the base line.

Step 1 · Design a Semicircular Arch

A semicircular arch is shaped like half a circle.Diagram 1

Let the span be 8 units8\text{ units}. The radius is half the span:

Radius=Span2=82=4 units\begin{aligned} \text{Radius} &= \dfrac{\text{Span}}{2} \\[0.6em] &= \dfrac{8}{2} \\[0.6em] &= 4\text{ units} \end{aligned}

The center is at the midpoint of the span.

Step 2 · Design a Pointed (Gothic) Arch

A pointed arch consists of two curved sides meeting at a point at the top.Diagram 2

Let the span be 8 units8\text{ units}. The radius of each arc is equal to the span:

Radius=Span=8 units\begin{aligned} \text{Radius} &= \text{Span} \\ &= 8\text{ units} \end{aligned}

The centers of the two arcs are located at the opposite ends of the span.

Step 3 · Design a Segmental Arch

A segmental arch is a flatter arch that forms part of a circle.Diagram 3

Let the radius be 5 units5\text{ units} and the center be 3 units3\text{ units} below the midpoint of the span.

Let half the span be xx. By Pythagoras theorem:

x2+32=52x2+9=25x2=259x2=16x=16x=4 units\begin{aligned} x^2 + 3^2 &= 5^2 \\ x^2 + 9 &= 25 \\ x^2 &= 25 - 9 \\ x^2 &= 16 \\ x &= \sqrt{16} \\ x &= 4\text{ units} \end{aligned} Total Span=2×x=2×4=8 units\begin{aligned} \text{Total Span} &= 2 \times x \\ &= 2 \times 4 \\ &= 8\text{ units} \end{aligned}
Answer

Three basic arch designs:

  • Semicircular Arch: Half of a circle with Radius=4 units\text{Radius} = 4\text{ units} for a span of 8 units8\text{ units}.
  • Pointed Arch: Two intersecting arcs of Radius=8 units\text{Radius} = 8\text{ units}.
  • Segmental Arch: A flatter circular arc with Radius=5 units\text{Radius} = 5\text{ units} and Span=8 units\text{Span} = 8\text{ units}.
Common Mistakes
  • Radius vs. Span Confusion: For a semicircular arch, Radius=Span2\text{Radius} = \dfrac{\text{Span}}{2}, whereas for a pointed Gothic arch, Radius=Span\text{Radius} = \text{Span}.
  • Center Placement for Segmental Arch: Placing the center on the span line instead of below it produces a semicircle instead of a flatter segmental arch.

More questions in FIO

Q1

When constructing the perpendicular bisector, is it necessary to have the same radius for the arcs above and below XYXY? Explore this through construction, and then justify your answer.

[Hint 1: Any point that is of the same distance from XX and YY lies on the perpendicular bisector.

Hint 2: We can draw the whole line if any two of its points are known.]

Q2

Is it necessary to construct the pairs of arcs above and below XYXY? Instead, can we construct both the pairs of arcs on the same side of XYXY? Explore this through construction, and then justify your answer.

Q3

While constructing one pair of intersecting arcs, is it necessary that we use the same radii for both of them ? Explore this through construction, and then justify your answer.

Q4

Recreate this design using only a ruler and compass —

Q5

Justify why AB\text{AB} in Fig. 6.4 is the perpendicular bisector.

Q6

Can you think of different methods to construct a 9090^\circ angle at a given point on a line using a rope?

Q7

Construct at least 4 different angles. Draw their bisectors.

Q8

Construct the 8-petalled figure shown in Fig. 6.5.

Q9

In Step 2 of angle bisection, if arcs of equal radius are drawn on the other side, as shown in the figure, will the line OCOC still be an angle bisector? Explore this through construction, and then justify your answer.

Q10

What are the other angles that can be constructed using angle bisection? Can you construct 65.565.5^\circ angle?

Q11

Come up with a method to construct the angle bisector using a rope.

Q12

Construct the following figure.

How do we construct the petals so that they are of the maximum possible size within a given square?

Q13

Construct at least 4 different angles in different orientations without taking any measurement. Make a copy of all these angles.

Q14

Construct the Fig. 6.6.

Q15

Construct 4 pairs of parallel lines in different orientations.

Q16

Construct the following figure.

Q17

Use support lines in Fig. 6.11 to construct a pointed arch. Make different arches, by changing the radius of the arcs.

Q18

Make your own arch designs.

Q19

Construct the following figures:

Q20

Optical Illusion: Do you notice anything interesting about the following figure? How does this happen? Recreate this in your notebook.

Q21

Construct this figure.

[Hint: Find the angles in this figure.]

Q22

Draw a line ll and mark a point PP anywhere outside the line. Construct a perpendicular to the given line ll through PP.

[Hint: Find a line segment on ll whose perpendicular bisector passes through PP.]

Q23

How can the tangram pieces be rearranged to form each of the following figures?

Q24

Are the following tilings possible?

← Back to Constructions and Tilings