Question 22
Draw a line and mark a point P anywhere outside the line. Construct a perpendicular to the given line through P.
[Hint: Find a line segment on whose perpendicular bisector passes through P.]
We will find two points on the line that are equally far from P. Then we will draw the perpendicular bisector of the segment connecting these two points.
Step 1 — Mark two points on line
Let us draw a line . Let us mark a point P outside line .
Place the compass needle on point P. Open the compass to a suitable radius. The radius must be large enough to cross line . Draw an arc that cuts line at two distinct points. Let us name these points A and B.

Step 2 — Draw intersecting arcs from A and B
Now, place the compass needle on point A. Open the compass to a radius. This radius must be more than half the length of segment AB. Draw an arc above line . Draw another arc below line . Keep the compass opening exactly the same. Place the compass needle on point B. Draw an arc above line . This arc should intersect the first arc. Draw another arc below line . This arc should intersect the second arc. Let us name the points where these arcs intersect C and D.

Step 3 — Draw the perpendicular line
Use a ruler to connect points C and D. Draw a straight line passing through C and D. Observe that this line also passes through point P. This line is perpendicular to line . Let us call this new line m.

Answer
(i) A line m has been constructed. (ii) Line m passes through point P. (iii) Line m is perpendicular to line l.
More questions in FIO
When constructing the perpendicular bisector, is it necessary to have the same radius for the arcs above and below XY? Explore this through construction, and then justify your answer.
[Hint 1: Any point that is of the same distance from X and Y lies on the perpendicular bisector.
Hint 2: We can draw the whole line if any two of its points are known.]
Is it necessary to construct the pairs of arcs above and below XY? Instead, can we construct both the pairs of arcs on the same side of XY? Explore this through construction, and then justify your answer.
While constructing one pair of intersecting arcs, is it necessary that we use the same radii for both of them ? Explore this through construction, and then justify your answer.
Recreate this design using only a ruler and compass —
Justify why AB in Fig. 6.4 is the perpendicular bisector.
Can you think of different methods to construct a 90° angle at a given point on a line using a rope?
Construct at least 4 different angles. Draw their bisectors.
Construct the 8-petalled figure shown in Fig. 6.5.
In Step 2 of angle bisection, if arcs of equal radius are drawn on the other side, as shown in the figure, will the line OC still be an angle bisector? Explore this through construction, and then justify your answer.
What are the other angles that can be constructed using angle bisection? Can you construct 65.5° angle?
Come up with a method to construct the angle bisector using a rope.
Construct the following figure.
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Construct at least 4 different angles in different orientations without taking any measurement. Make a copy of all these angles.
Construct the Fig. 6.6.
Construct 4 pairs of parallel lines in different orientations.
Construct the following figure.
Use support lines in Fig. 6.11 to construct a pointed arch. Make different arches, by changing the radius of the arcs.
Make your own arch designs.
Construct the following figures:
Optical Illusion: Do you notice anything interesting about the following figure? How does this happen? Recreate this in your notebook.
Construct this figure.
[Hint: Find the angles in this figure.]
Draw a line and mark a point P anywhere outside the line. Construct a perpendicular to the given line through P.
[Hint: Find a line segment on whose perpendicular bisector passes through P.]
How can the tangram pieces be rearranged to form each of the following figures?
Are the following tilings possible?