Question 12
Construct the following figure.
How do we construct the petals so that they are of the maximum possible size within a given square?

- To construct four petals of the maximum size inside a square, we start by drawing a square .
- Next, locate the midpoints on the four sides of the square.
- Using the corners of the square as centers, draw circular arcs between adjacent midpoints to form each symmetrical petal.
Step 1 · Draw the Square

- Draw a line segment of the chosen side length.
- At point , construct a perpendicular line segment such that .
- At point , construct a perpendicular line segment such that .
- Join and to complete the square .
Step 2 · Find the Midpoints of the Sides

- Use a compass to find the perpendicular bisector of each side:
- Midpoint of : Point
- Midpoint of : Point
- Midpoint of : Point
- Midpoint of : Point
- These four midpoints mark where the petals meet the square.
Step 3 · Draw the Arcs to Form Petals

Draw arcs using the square vertices as centers:
-
Top-left petal (near ):
- Center at , radius : Draw arc from to .
- Center at , radius : Draw arc from to .
-
Top-right petal (near ):
- Center at , radius : Draw arc from to .
- Center at , radius : Draw arc from to .
-
Bottom-right petal (near ):
- Center at , radius : Draw arc from to .
- Center at , radius : Draw arc from to .
-
Bottom-left petal (near ):
- Center at , radius : Draw arc from to .
- Center at , radius : Draw arc from to .
The four petals of maximum size are constructed by drawing circular arcs connecting adjacent side midpoints () using the vertices of the square as centers.
- Center Confusion: Placing the compass needle at the side midpoints rather than the square's corners () to draw the arcs.
- Incorrect Radius: Not adjusting the compass radius to precisely touch the opposite side midpoints, which leads to asymmetrical petals.
More questions in FIO
When constructing the perpendicular bisector, is it necessary to have the same radius for the arcs above and below ? Explore this through construction, and then justify your answer.
[Hint 1: Any point that is of the same distance from and lies on the perpendicular bisector.
Hint 2: We can draw the whole line if any two of its points are known.]
Is it necessary to construct the pairs of arcs above and below ? Instead, can we construct both the pairs of arcs on the same side of ? Explore this through construction, and then justify your answer.
While constructing one pair of intersecting arcs, is it necessary that we use the same radii for both of them ? Explore this through construction, and then justify your answer.
Recreate this design using only a ruler and compass —
Justify why in Fig. 6.4 is the perpendicular bisector.
Can you think of different methods to construct a angle at a given point on a line using a rope?
Construct at least 4 different angles. Draw their bisectors.
Construct the 8-petalled figure shown in Fig. 6.5.
In Step 2 of angle bisection, if arcs of equal radius are drawn on the other side, as shown in the figure, will the line still be an angle bisector? Explore this through construction, and then justify your answer.
What are the other angles that can be constructed using angle bisection? Can you construct angle?
Come up with a method to construct the angle bisector using a rope.
Construct the following figure.
How do we construct the petals so that they are of the maximum possible size within a given square?
Construct at least 4 different angles in different orientations without taking any measurement. Make a copy of all these angles.
Construct the Fig. 6.6.
Construct 4 pairs of parallel lines in different orientations.
Construct the following figure.
Use support lines in Fig. 6.11 to construct a pointed arch. Make different arches, by changing the radius of the arcs.
Make your own arch designs.
Construct the following figures:
Optical Illusion: Do you notice anything interesting about the following figure? How does this happen? Recreate this in your notebook.
Construct this figure.
[Hint: Find the angles in this figure.]
Draw a line and mark a point anywhere outside the line. Construct a perpendicular to the given line through .
[Hint: Find a line segment on whose perpendicular bisector passes through .]
How can the tangram pieces be rearranged to form each of the following figures?
Are the following tilings possible?