Constructions and Tilings | FIO

Question 14

Construct the Fig. 6.6.

Question diagram 1
Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution
Understand the Question
  • The figure is a wave-like pattern composed of alternating 6060^\circ circular sectors of equal radius rr.
  • Since each angle in an equilateral triangle is 6060^\circ and all its sides equal rr, the pattern is built by constructing a chain of adjacent equilateral triangles of side length rr and drawing circular arcs centered at alternating vertices.
  • Alternate sectors are then shaded to complete the pattern.

Step 1 · Draw the Base Segment

Choose a suitable radius rr.Diagram 1

Draw a line segment V1V2V_1V_2 of length rr.

Step 2 · Construct the First Sector

Construct an equilateral triangle V0V1V2V_0V_1V_2 above V1V2V_1V_2 and draw the bounding arc:Diagram 2

  1. With radius rr, draw arcs centered at V1V_1 and V2V_2 above V1V2V_1V_2 intersecting at V0V_0.
  2. Join V0V1V_0V_1 and V0V2V_0V_2.
  3. With center V0V_0 and radius rr, draw an arc connecting V1V_1 and V2V_2 to form the first sector.

Step 3 · Construct the Second Sector

Construct an equilateral triangle V1V2V3V_1V_2V_3 below V1V2V_1V_2:Diagram 3

  1. With radius rr, draw arcs centered at V1V_1 and V2V_2 below V1V2V_1V_2 intersecting at V3V_3.
  2. Join V2V3V_2V_3 and V1V3V_1V_3.
  3. With center V2V_2 and radius rr, draw an arc connecting V1V_1 and V3V_3 to form the second sector.

Step 4 · Construct the Third Sector

Construct an equilateral triangle V2V3V4V_2V_3V_4 above V2V3V_2V_3:Diagram 4

  1. With radius rr, draw arcs centered at V2V_2 and V3V_3 above V2V3V_2V_3 intersecting at V4V_4.
  2. Join V3V4V_3V_4 and V2V4V_2V_4.
  3. With center V3V_3 and radius rr, draw an arc connecting V2V_2 and V4V_4 to form the third sector.

Step 5 · Construct the Fourth Sector

Construct an equilateral triangle V3V4V5V_3V_4V_5 below V3V4V_3V_4:Diagram 5

  1. With radius rr, draw arcs centered at V3V_3 and V4V_4 below V3V4V_3V_4 intersecting at V5V_5.
  2. Join V4V5V_4V_5 and V3V5V_3V_5.
  3. With center V4V_4 and radius rr, draw an arc connecting V3V_3 and V5V_5 to form the fourth sector.

Step 6 · Construct the Fifth Sector

Construct an equilateral triangle V4V5V6V_4V_5V_6 above V4V5V_4V_5:Diagram 6

  1. With radius rr, draw arcs centered at V4V_4 and V5V_5 above V4V5V_4V_5 intersecting at V6V_6.
  2. Join V5V6V_5V_6 and V4V6V_4V_6.
  3. With center V5V_5 and radius rr, draw an arc connecting V4V_4 and V6V_6 to form the fifth sector.

Step 7 · Shade Alternate Sectors

Shade the 1st, 3rd, and 5th sectors (V0V1V2V_0V_1V_2, V3V2V4V_3V_2V_4, and V5V4V6V_5V_4V_6).Diagram 7

Answer

The figure is constructed by drawing alternating 6060^\circ sectors of radius rr and shading the 1st, 3rd, and 5th sectors.

Common Mistakes
  • Changing Compass Radius: Altering the compass width during construction will cause the triangles not to be equilateral and the sector arcs to misalign.
  • Incorrect Arc Center: Placing the compass on the wrong vertex when drawing the circular arc instead of using the apex of each sector.

More questions in FIO

Q1

When constructing the perpendicular bisector, is it necessary to have the same radius for the arcs above and below XYXY? Explore this through construction, and then justify your answer.

[Hint 1: Any point that is of the same distance from XX and YY lies on the perpendicular bisector.

Hint 2: We can draw the whole line if any two of its points are known.]

Q2

Is it necessary to construct the pairs of arcs above and below XYXY? Instead, can we construct both the pairs of arcs on the same side of XYXY? Explore this through construction, and then justify your answer.

Q3

While constructing one pair of intersecting arcs, is it necessary that we use the same radii for both of them ? Explore this through construction, and then justify your answer.

Q4

Recreate this design using only a ruler and compass —

Q5

Justify why AB\text{AB} in Fig. 6.4 is the perpendicular bisector.

Q6

Can you think of different methods to construct a 9090^\circ angle at a given point on a line using a rope?

Q7

Construct at least 4 different angles. Draw their bisectors.

Q8

Construct the 8-petalled figure shown in Fig. 6.5.

Q9

In Step 2 of angle bisection, if arcs of equal radius are drawn on the other side, as shown in the figure, will the line OCOC still be an angle bisector? Explore this through construction, and then justify your answer.

Q10

What are the other angles that can be constructed using angle bisection? Can you construct 65.565.5^\circ angle?

Q11

Come up with a method to construct the angle bisector using a rope.

Q12

Construct the following figure.

How do we construct the petals so that they are of the maximum possible size within a given square?

Q13

Construct at least 4 different angles in different orientations without taking any measurement. Make a copy of all these angles.

Q14

Construct the Fig. 6.6.

Q15

Construct 4 pairs of parallel lines in different orientations.

Q16

Construct the following figure.

Q17

Use support lines in Fig. 6.11 to construct a pointed arch. Make different arches, by changing the radius of the arcs.

Q18

Make your own arch designs.

Q19

Construct the following figures:

Q20

Optical Illusion: Do you notice anything interesting about the following figure? How does this happen? Recreate this in your notebook.

Q21

Construct this figure.

[Hint: Find the angles in this figure.]

Q22

Draw a line ll and mark a point PP anywhere outside the line. Construct a perpendicular to the given line ll through PP.

[Hint: Find a line segment on ll whose perpendicular bisector passes through PP.]

Q23

How can the tangram pieces be rearranged to form each of the following figures?

Q24

Are the following tilings possible?

← Back to Constructions and Tilings