Question 16
Why does Baudhāyana’s method work?

The diagram shows a visual proof of the Pythagorean theorem.
Step 1 — Identifying the squares
We start with two squares of different sizes. Let the side length of the smaller square be . Its area is . Let the side length of the larger square be . Its area is .

Step 2 — Forming a right-angled triangle
These two squares are then arranged. One side of the square with area forms one leg of a right-angled triangle. One side of the square with area forms the other leg of the right-angled triangle. These two sides meet at a right angle (an angle of 90 degrees). Let the length of the hypotenuse (the side opposite the right angle) of this triangle be .

Step 3 — Constructing the third square
A third square is constructed. This third square is built on the hypotenuse of the right-angled triangle. The diagram clearly labels the area of this third square as "Area A + Area B". This means the area of the square on the hypotenuse is the sum of the areas of the other two squares.
We know that the area of a square with side length is . So, the diagram visually demonstrates that:
Step 4 — Baudhāyana's method
Baudhāyana's method, as described in his Sulbasutra, is a geometric way to understand this relationship. It states that the square constructed on the diagonal (hypotenuse) of a rectangle has an area equal to the sum of the areas of the squares constructed on its sides (legs). The diagram perfectly illustrates this principle. It shows that the area of the square built on the hypotenuse is exactly equal to the combined areas of the squares built on the other two sides. This is the Pythagorean theorem (also known as Baudhāyana's theorem in India). Therefore, Baudhāyana's method works because it provides a geometric construction that proves the fundamental relationship between the sides of a right-angled triangle.
Answer
Baudhāyana’s method works because it geometrically demonstrates the Pythagorean theorem. It shows that when squares are constructed on the two shorter sides (legs) of a right-angled triangle, the sum of their areas is equal to the area of the square constructed on the longest side (hypotenuse). This means if the legs have lengths and , and the hypotenuse has length , then .
More questions in IT
How can one construct a square having double the area of a given square?
Why does the new dotted square have double the area of the original square?
In many of the constructions in the Śulba-Sūtra, it is desirable to construct, where needed, what Baudhāyana calls ‘east-west’ and ‘north-south’ lines, i.e., horizontal and vertical lines that are perpendicular to each other. Can you draw some horizontal and vertical lines to see why the new square has double the area of the original square? You could draw some horizontal and vertical lines as shown on the right.
Why should the extension of the vertical and horizontal sides of the original square pass through the vertices of the dotted square?
[Hint: From the diagonal property of a square, the line that bisects an angle passes through the opposite vertex. Argue why the vertical and horizontal sides of the original square bisect the two angles of the dotted square.**]
Context: So, the new square has double the area of the original square, because the original square is made up of two small triangles, while the new square is made up of four small triangles.
Q. Moreover, all these small triangles are congruent to each other. Can you explain why?
Now suppose we are given a square, and we want to construct a square whose area is half that of the original square. How would you do it?
Why is the smaller inside square half the area of the larger square?
Again, adding some east-west and north-south lines can explain it:
Why is PQRS a square? Why is its area half that of the original paper?
Explain by connecting QS and PR, finding the different angles formed, and then using tringle congruence.
Find the hypotenuse of this isosceles right triangle.
What is the value of ?
Is less than or greater than 1?
Is less than or greater than 2?
Can we find closer bounds for ?
Will we ever get a number with a terminating decimal representation whose square is 2?
If there is such a terminating decimal starting with 1.414... whose square is 2, then it must have a non-zero last digit. If this is the case, then the decimal representation of its square will also have a non-zero last digit after the decimal point. For example, if is of the form 1.414...4, then its square will be of the form—
Use this formula to check your answers in the Figure it Out on page 39.
What if we wish to combine two squares of 'different' sizes to make a large square whose area is the sum of the two smaller squares?
Why does Baudhāyana’s method work?
Can you see why the method works in the case where the two squares are the same size? Does it agree with the method we used earlier to combine two same sized squares into a bigger square?
Explain why all the angles of this new 4-sided figure are right angles and so it is a square.
List down all the Baudhāyana triples with numbers less than or equal to 20.
Is there an unending sequence of Baudhāyana triples?
Is (30, 40, 50) a Baudhāyana triple?
Is (300, 400, 500) a Baudhāyana triple?
Context: The list of Baudhāyana triples having numbers less than or equal to 20 contains the following triples — (3, 4, 5), (6, 8, 10), (9, 12, 15), (12, 16, 20).
Q. Do you see any pattern among them?
Context: All these triples can be obtained by multiplying each term of (3, 4, 5) by a certain positive integer.
Q. Can we form a conjecture on Baudhāyana triples based on this observation?
Context: Conjecture: (3k, 4k, 5k) is a Baudhāyana triple, where k is any positive integer.
Q. Is this true?
Is a primitive Baudhayana triple? What are the other primitive Baudhayana triples with numbers less than or equal to 20?
Generate 5 scaled versions of each of these primitive triples. Are these scaled versions primitive?
If is non-primitive, and the integers have — greater than 1 — as a common factor, then is a Baudhayana triple? Check this statement for . Justify this statement.