Squares and Square Roots | IT

Question 16

Why does Baudhāyana’s method work?

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Solution
Understand the Question
  • Baudhāyana's Theorem (the geometric formulation of the Pythagorean Theorem) states that the area of the square constructed on the hypotenuse (diagonal) of a right-angled triangle is equal to the sum of the areas of the squares constructed on the other two sides (legs).
  • If the two legs of the right-angled triangle are aa and bb, and the hypotenuse is cc, then: Area of Square on Hypotenuse=Area of Square on Side a+Area of Square on Side b\text{Area of Square on Hypotenuse} = \text{Area of Square on Side } a + \text{Area of Square on Side } b c2=a2+b2c^2 = a^2 + b^2

Step 1 · Identify the Areas of the Two Smaller Squares

Consider two squares with side lengths aa and bb.Diagram 1

  • Area of the first square (Area A)=a×a=a2(\text{Area A}) = a \times a = a^2
  • Area of the second square (Area B)=b×b=b2(\text{Area B}) = b \times b = b^2

Step 2 · Form a Right-Angled Triangle

Arrange the two squares so that one side from each square meets at a 9090^\circ angle, forming the two perpendicular legs of a right-angled triangle.Diagram 2

Let the length of the hypotenuse (the side opposite the right angle) be cc.

Step 3 · Construct the Square on the Hypotenuse

Construct a third square along the hypotenuse of length cc.

The area of this square is: Area of square on hypotenuse=c2\text{Area of square on hypotenuse} = c^2

From the geometric dissection and rearrangement: Area of square on hypotenuse=Area A+Area B\text{Area of square on hypotenuse} = \text{Area A} + \text{Area B}

Area of square on hypotenuse=a2+b2\text{Area of square on hypotenuse} = a^2 + b^2

Therefore: c2=a2+b2c^2 = a^2 + b^2

Step 4 · Conclusion Based on Baudhāyana's Sutra

Baudhāyana's method in the Sulbasutras states that the square produced by the diagonal of a rectangle equals the sum of the squares produced by its two sides.

Since the geometric construction shows that the combined area of the squares on the legs exactly fills the square on the hypotenuse, Baudhāyana's method is a valid visual proof of the relation a2+b2=c2a^2 + b^2 = c^2.

Answer

Baudhāyana’s method works because it geometrically proves that the area of the square constructed on the hypotenuse equals the sum of the areas of the squares on the other two legs, demonstrating a2+b2=c2a^2 + b^2 = c^2

Common Mistakes
  • Confusing Side Lengths with Areas: Adding the side lengths (a+b=ca + b = c) instead of their squared areas (a2+b2=c2a^2 + b^2 = c^2).
  • Applying to Non-Right Triangles: Baudhāyana's theorem strictly holds only when the angle between the two sides is exactly 9090^\circ.

More questions in IT

Q1

How can one construct a square having double the area of a given square?

Q2

Why does the new dotted square have double the area of the original square?

In many of the constructions in the Śulba-Sūtra, it is desirable to construct, where needed, what Baudhāyana calls ‘east-west’ and ‘north-south’ lines, i.e., horizontal and vertical lines that are perpendicular to each other. Can you draw some horizontal and vertical lines to see why the new square has double the area of the original square? You could draw some horizontal and vertical lines as shown on the right.

Q3

Why should the extension of the vertical and horizontal sides of the original square pass through the vertices of the dotted square?

[Hint: From the diagonal property of a square, the line that bisects an angle passes through the opposite vertex. Argue why the vertical and horizontal sides of the original square bisect the two angles of the dotted square.**]

Q4

Context: So, the new square has double the area of the original square, because the original square is made up of two small triangles, while the new square is made up of four small triangles.

Q. Moreover, all these small triangles are congruent to each other. Can you explain why?

Q5

Now suppose we are given a square, and we want to construct a square whose area is half that of the original square. How would you do it?

Q6

Why is the smaller inside square half the area of the larger square?

Again, adding some east-west and north-south lines can explain it:

Q7

Why is PQRSPQRS a square? Why is its area half that of the original paper?

Explain by connecting QSQS and PRPR, finding the different angles formed, and then using tringle congruence.

Q8

Find the hypotenuse of this isosceles right triangle.

Q9

What is the value of 2\sqrt{2}?

Q10

Is 2\sqrt{2} less than or greater than 1?

Q11

Is 2\sqrt{2} less than or greater than 2?

Q12

Can we find closer bounds for 2\sqrt{2}?

Q13

Will we ever get a number with a terminating decimal representation whose square is 2?

If there is such a terminating decimal starting with 1.4141.414\dots whose square is 2, then it must have a non-zero last digit. If this is the case, then the decimal representation of its square will also have a non-zero last digit after the decimal point. For example, if 2\sqrt{2} is of the form 1.41441.414\dots4, then its square will be of the form—

Q14

Use this formula to check your answers in the Figure it Out on page 39.

Q15

What if we wish to combine two squares of 'different' sizes to make a large square whose area is the sum of the two smaller squares?

Q16

Why does Baudhāyana’s method work?

Q17

Can you see why the method works in the case where the two squares are the same size? Does it agree with the method we used earlier to combine two same sized squares into a bigger square?

Q19

Explain why all the angles of this new 4-sided figure are right angles and so it is a square.

Q20

List down all the Baudhāyana triples with numbers less than or equal to 20.

Q21

Is there an unending sequence of Baudhāyana triples?

Q22

Is (30,40,50)(30, 40, 50) a Baudhāyana triple?

Is (300,400,500)(300, 400, 500) a Baudhāyana triple?

Q23

Context: The list of Baudhāyana triples having numbers less than or equal to 20 contains the following triples — (3,4,5)(3, 4, 5), (6,8,10)(6, 8, 10), (9,12,15)(9, 12, 15), (12,16,20)(12, 16, 20).

Q. Do you see any pattern among them?

Q24

Context: All these triples can be obtained by multiplying each term of (3,4,5)(3, 4, 5) by a certain positive integer.

Q. Can we form a conjecture on Baudhāyana triples based on this observation?

Q25

Context: Conjecture: (3k,4k,5k)(3k, 4k, 5k) is a Baudhāyana triple, where kk is any positive integer.

Q. Is this true?

Q26

Is (5,12,13)(5, 12, 13) a primitive Baudhayana triple? What are the other primitive Baudhayana triples with numbers less than or equal to 2020?

Q27

Generate 5 scaled versions of each of these primitive triples. Are these scaled versions primitive?

Q28

If (a,b,c)(a, b, c) is non-primitive, and the integers have ff — greater than 1 — as a common factor, then is (af,bf,cf)\left(\dfrac{a}{f}, \dfrac{b}{f}, \dfrac{c}{f}\right) a Baudhayana triple? Check this statement for (9,12,15)(9, 12, 15). Justify this statement.

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