Area of Polygons | IT

Question 19

What are the sidelengths of the rectangle WXYZ?

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Solution

IT-19

Chapter: AREA OF POLYGONS
Class: 8 (Class 8)
Category: in_text


Question

What are the sidelengths of the rectangle WXYZ?

Question diagram(s):

Question diagram


The image shows how four right-angled triangles are rearranged to form a larger rectangle WXYZ.

Step 1 — Identify common side lengths

Let us look at the tick marks on the sides of the triangles. The single tick mark means those sides have the same length. The double tick mark means those sides have another common length. Let L1L_1 be the length of the side with one tick mark. Let L2L_2 be the length of the side with two tick marks.

For the orange triangles (OAD\triangle OAD and ABO\triangle ABO): The legs are OAOA (one tick) and ODOD (two ticks) for OAD\triangle OAD. The legs are AOAO (one tick) and BOBO (two ticks) for ABO\triangle ABO. So, OA=AO=L1OA = AO = L_1. And OD=BO=L2OD = BO = L_2.

For the green triangles (BOC\triangle BOC and COD\triangle COD): The legs are OCOC (one tick) and BOBO (two ticks) for BOC\triangle BOC. The legs are COCO (one tick) and ODOD (two ticks) for COD\triangle COD. So, OC=CO=L1OC = CO = L_1. And BO=OD=L2BO = OD = L_2. All four triangles are congruent right-angled triangles with legs L1L_1 and L2L_2.

Step 2 — Dimensions of the orange rectangle

The orange rectangle is formed by combining the two orange triangles. These triangles have legs of length L1L_1 and L2L_2. When two such congruent right triangles are placed together, they form a rectangle with sides equal to their legs. From the diagram, the orange rectangle has its longer side horizontal and its shorter side vertical. So, the width of the orange rectangle is L2L_2. The height of the orange rectangle is L1L_1.

Step 3 — Dimensions of the green rectangle

The green rectangle is formed by combining the two green triangles. These triangles also have legs of length L1L_1 and L2L_2. Similar to the orange rectangle, the green rectangle will have sides L1L_1 and L2L_2. From the diagram, the green rectangle also has its longer side horizontal and its shorter side vertical. So, the width of the green rectangle is L2L_2. The height of the green rectangle is L1L_1.

Step 4 — Sidelengths of rectangle WXYZ

Rectangle WXYZ is formed by stacking the orange rectangle on top of the green rectangle. The width of WXYZ is the common width of the two individual rectangles. The height of WXYZ is the sum of the heights of the two individual rectangles.

The width of WXYZ is L2L_2. The height of WXYZ is L1+L1=2L1L_1 + L_1 = 2L_1.

Let us express these lengths using the labels from the original triangles. We know L1=OAL_1 = OA (or OCOC). We know L2=ODL_2 = OD (or OBOB).

So, the width of rectangle WXYZ is ODOD. The height of rectangle WXYZ is 2×OA2 \times OA.

The sidelengths of rectangle WXYZ are the lengths of its sides, XYXY (or WZWZ) and XWXW (or YZYZ). The width XYXY (or WZWZ) is ODOD. The height XWXW (or YZYZ) is 2×OA2 \times OA.

Width =OD\boxed{\text{Width } = OD} Height =2×OA\boxed{\text{Height } = 2 \times OA}

Diagram 1

Answer

The width of rectangle WXYZ is OD. The height of rectangle WXYZ is 2 * OA.

More questions in IT

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Q2

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Q3

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Q19

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Q20

Area of rhombus ABCD can also be determined by finding the areas of ΔADB\Delta\text{ADB} and ΔCDB\Delta\text{CDB}. What formula does this give us?

Q21

Context: The area of rhombus ABCD can be written as: Area of rhombus ABCD=Area(ΔADB)+Area(ΔCDB)=12×AO×BD+12×CO×BD\text{Area of rhombus ABCD} = \text{Area}(\Delta\text{ADB}) + \text{Area}(\Delta\text{CDB}) = \frac{1}{2} \times \text{AO} \times \text{BD} + \frac{1}{2} \times \text{CO} \times \text{BD}

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