Area of Polygons | IT

Question 14

How do we find the area of this pentagon?

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Solution
Understand the Question
  • To find the area of an irregular polygon such as a pentagon, we divide it into simpler, non-overlapping geometric shapes (such as triangles or trapeziums).
  • By drawing diagonals from one vertex to all non-adjacent vertices, an nn-sided polygon is split into (n2)(n - 2) triangles.
  • The total area of the pentagon is obtained by calculating the area of each individual triangle using the formula Area=12×base×height\text{Area} = \dfrac{1}{2} \times \text{base} \times \text{height} and adding them together.

Step 1 · Divide the Pentagon into Triangles

Let the vertices of the pentagon be labeled A, B, C, D,\text{A, B, C, D,} and E\text{E} in order. By drawing diagonals AC\text{AC} and AD\text{AD} from vertex A\text{A}, the pentagon is divided into three non-overlapping triangles: ABC\triangle \text{ABC}, ACD\triangle \text{ACD}, and ADE\triangle \text{ADE}.Diagram 1

The area of any triangle is given by: Area of a triangle=12×base×height\text{Area of a triangle} = \dfrac{1}{2} \times \text{base} \times \text{height}

For ABC\triangle \text{ABC} with base BC\text{BC} and perpendicular height h1h_1 from vertex A\text{A}: Area(ABC)=12×BC×h1\text{Area}(\triangle \text{ABC}) = \dfrac{1}{2} \times \text{BC} \times h_1

Similarly, calculate Area(ACD)\text{Area}(\triangle \text{ACD}) and Area(ADE)\text{Area}(\triangle \text{ADE}) using their respective bases and perpendicular heights.

The total area of the pentagon is the sum of these three areas: Area of Pentagon=Area(ABC)+Area(ACD)+Area(ADE)\text{Area of Pentagon} = \text{Area}(\triangle \text{ABC}) + \text{Area}(\triangle \text{ACD}) + \text{Area}(\triangle \text{ADE})

Step 2 · Measure and Calculate the Total Area

  1. Measure the length of each chosen base (using a ruler).
  2. Measure the corresponding perpendicular height for each triangle (using a set square).
  3. Substitute the values into the formula for each triangle and sum the results to obtain the total area of the pentagon.
Answer

Divide the pentagon into three triangles by drawing diagonals from one vertex, find the area of each triangle using Area=12×base×height\text{Area} = \dfrac{1}{2} \times \text{base} \times \text{height}, and sum their areas: Area of Pentagon=Area(ABC)+Area(ACD)+Area(ADE)\text{Area of Pentagon} = \text{Area}(\triangle \text{ABC}) + \text{Area}(\triangle \text{ACD}) + \text{Area}(\triangle \text{ADE})

Common Mistakes
  • Overlapping Regions: Drawing intersecting diagonals from multiple different vertices creates overlapping triangles, leading to double-counted areas. Always draw all diagonals from a single common vertex.
  • Slant Height vs. Perpendicular Height: Using the side length of the triangle instead of the true perpendicular altitude to the base when applying the area formula 12×base×height\dfrac{1}{2} \times \text{base} \times \text{height}.

More questions in IT

Q1

Try to think of different creative ways to divide a square into 4 parts of equal area.

Q2

Why Can't Perimeter be a Measure of Area?

Why do we count the number of unit squares to assign measures for area? Couldn't we have just used the perimeter of a region, i.e., the length of its boundary as a measure of its area?

Q3

Context: Consider two regions, Region 1 and Region 2, such that Perimeter of Region 1>Perimeter of Region 2\text{Perimeter of Region 1} > \text{Perimeter of Region 2}, but Area of Region 1<Area of Region 2\text{Area of Region 1} < \text{Area of Region 2}.

Q. Find two rectangles that are examples of such regions. If needed, use a grid paper (given at the end of the book) for this.

Q4

Also give an example of two regions of other shapes, where the region with the larger perimeter has the smaller area! This property should be visually clear in your example.

Q5

In the given figure, which triangle has a greater area: ΔXDC\Delta \text{XDC} or ΔYDC\Delta \text{YDC}, if both the rectangles are identical?

Q6

In the given figure, which triangle has a greater area: ΔXDC\Delta \text{XDC} or ΔYBC\Delta \text{YBC}, if both the rectangles are identical?

Q7

Find the area of ΔXDC\Delta \text{XDC}.

Q8

To find the area of a triangle, what measurements do we need?

Q9

How do we get the outer rectangle from the given triangle?

Q10

Will this formula hold for the kind of triangle, around which we cannot draw a rectangle with BC\text{BC} as the base?

Q11

Line lBCl \parallel \text{BC}. Consider the different triangles that have BC\text{BC} as their base, and with their third vertex lying anywhere on ll.

(i) Which of these triangles has the maximum area, and which has the minimum area?

(ii) Which of these triangles has the maximum perimeter, and which has the minimum perimeter?

Q12

Analyse whether AA lies on the perpendicular bisector of BCBC.

Q13

Area of any Polygon

How do we find the area of this quadrilateral? What measurements do we need for this?

Q14

How do we find the area of this pentagon?

Q15

Can any polygon be divided into triangles?

Q16

Give a method to convert a parallelogram into a rectangle of equal area.

You can try this using a cut-out of a parallelogram.

Q17

Can ΔAXD\Delta \text{AXD} and ABCX\text{ABCX} fit together, as shown in the figure, to get a rectangle?

Q18

Try working this out!

Q19

What are the sidelengths of the rectangle WXYZWXYZ?

Q20

Area of rhombus ABCD can also be determined by finding the areas of ΔADB\Delta \text{ADB} and ΔCDB\Delta \text{CDB}. What formula does this give us?

Q21

Context: The area of rhombus ABCD can be written as:

Area of rhombus ABCD=Area(ΔADB)+Area(ΔCDB)=12×AO×BD+12×CO×BD\text{Area of rhombus } ABCD = \text{Area}(\Delta \text{ADB}) + \text{Area}(\Delta \text{CDB}) = \dfrac{1}{2} \times \text{AO} \times \text{BD} + \dfrac{1}{2} \times \text{CO} \times \text{BD}

Q. Simplify the expression to show that we get the same formula for the area of a rhombus in terms of its diagonals.

Q22

Find the areas of the following trapeziums by breaking them into figures whose areas can be computed.

Q23

Will this formula hold for a trapezium that looks like this?

Q24

Will Approach 2 work for any type of trapezium?

Q25

What figure will we get when the two trapeziums are joined along BC\text{BC}?

Q26

What type of a quadrilateral is this?

Q27

What do you think is the area of an A4 sheet? Its sidelengths are 21 cm21\text{ cm} and 29.7 cm29.7\text{ cm}. Now find its area.

Q28

What do you think is the area of the tabletop that you use at school or at home? You could perhaps try to visualise how many A4 sheets can fit on your table.

Q29

Express the following lengths in centimeters:

(i) 5 in5 \text{ in}

(ii) 7.4 in7.4 \text{ in}

Q30

Express the following lengths in inches:

(i) 5.08 cm5.08 \text{ cm}

(ii) 11.43 cm11.43 \text{ cm}

Q31

How many cm2\text{cm}^2 is 1 in21 \text{ in}^2?

Q32

Context: Convert 161.29 cm2161.29 \text{ cm}^2 to in2\text{in}^2. Every 6.4516 cm26.4516 \text{ cm}^2 gives an in2\text{in}^2. Hence, 161.29 cm2=161.296.4516 in2161.29 \text{ cm}^2 = \dfrac{161.29}{6.4516} \text{ in}^2.

Q. Evaluate the quotient.

Q33

What do you think is the area of your classroom?

Q34

How many in2\text{in}^2 is 1 ft21 \text{ ft}^2?

Q35

What do you think is the area of your school? Make an estimate and compare it with the actual data.

Q36

Find out the local unit of area measurement in your region.

Q37

What do you think is the area of your village/town/city? Make an estimate and compare it with the actual data.

Q38

How many m2\text{m}^2 is a km2\text{km}^2?

Q39

How many times is your village/town/city bigger than your school?

Q40

Find the city with the largest area in:

(i) India

(ii) the world

Q41

Find the city with the smallest area in:

(i) India

(ii) the world

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