Some Applications of Trigonometry | Exercise 9.1

Question 1

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 3030^\circ (see Fig. 9.11).

Question diagram 1
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Solution
Understand the Question
  • The vertical pole and the ground form a right-angled triangle ABC\text{ABC} where B=90\angle \text{B} = 90^\circ.
  • The rope AC=20 m\text{AC} = 20\text{ m} acts as the hypotenuse, and the pole AB\text{AB} is the side opposite to the angle made with the ground (C=30\angle \text{C} = 30^\circ).
  • To find the height of the pole (AB\text{AB}), we use the sine trigonometric ratio: sinθ=OppositeHypotenuse\sin \theta = \dfrac{\text{Opposite}}{\text{Hypotenuse}}.

Step 1 · Find the Height of the Pole

Let AB\text{AB} be the vertical pole and AC\text{AC} be the rope.Diagram 1

In right-angled triangle ABC\text{ABC} sinC=ABAC\sin \text{C} = \dfrac{\text{AB}}{\text{AC}}

Substitute C=30\text{C} = 30^\circ and AC=20 m\text{AC} = 20\text{ m} sin30=AB20\sin 30^\circ = \dfrac{\text{AB}}{20}

Since sin30=12\sin 30^\circ = \dfrac{1}{2} 12=AB20\dfrac{1}{2} = \dfrac{\text{AB}}{20}

AB=20×12\text{AB} = 20 \times \dfrac{1}{2}

AB=10 m\text{AB} = 10\text{ m}

Answer

10 m10\text{ m}

Common Mistakes
  • Wrong Trigonometric Ratio: Using cos30=BCAC\cos 30^\circ = \dfrac{\text{BC}}{\text{AC}} or tan30=ABBC\tan 30^\circ = \dfrac{\text{AB}}{\text{BC}} instead of sin30\sin 30^\circ, which directly relates the unknown opposite side to the known hypotenuse.
  • Incorrect Value of sin30\sin 30^\circ: Confusing sin30=12\sin 30^\circ = \dfrac{1}{2} with cos30=32\cos 30^\circ = \dfrac{\sqrt{3}}{2} or tan30=13\tan 30^\circ = \dfrac{1}{\sqrt{3}}.

More questions in Exercise 9.1

Q1

A circus artist is climbing a 20 m long rope, which is tightly stretched and tied from the top of a vertical pole to the ground. Find the height of the pole, if the angle made by the rope with the ground level is 3030^\circ (see Fig. 9.11).

Q2

A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground making an angle 3030^\circ with it. The distance between the foot of the tree to the point where the top touches the ground is 8 m. Find the height of the tree.

Q3

A contractor plans to install two slides for the children to play in a park. For the children below the age of 5 years, she prefers to have a slide whose top is at a height of 1.5 m, and is inclined at an angle of 3030^\circ to the ground, whereas for elder children, she wants to have a steep slide at a height of 3 m, and inclined at an angle of 6060^\circ to the ground. What should be the length of the slide in each case?

Q4

The angle of elevation of the top of a tower from a point on the ground, which is 30 m away from the foot of the tower, is 3030^\circ. Find the height of the tower.

Q5

A kite is flying at a height of 60 m60\text{ m} above the ground. The string attached to the kite is temporarily tied to a point on the ground. The inclination of the string with the ground is 6060^\circ. Find the length of the string, assuming that there is no slack in the string.

Q6

A 1.5 m1.5\text{ m} tall boy is standing at some distance from a 30 m30\text{ m} tall building. The angle of elevation from his eyes to the top of the building increases from 3030^\circ to 6060^\circ as he walks towards the building. Find the distance he walked towards the building.

Q7

From a point on the ground, the angles of elevation of the bottom and the top of a transmission tower fixed at the top of a 20 m high building are 4545^\circ and 6060^\circ respectively. Find the height of the tower.

Q8

A statue, 1.6 m1.6\text{ m} tall, stands on the top of a pedestal. From a point on the ground, the angle of elevation of the top of the statue is 6060^\circ and from the same point the angle of elevation of the top of the pedestal is 4545^\circ. Find the height of the pedestal.

Q9
  1. The angle of elevation of the top of a building from the foot of the tower is 3030^\circ and the angle of elevation of the top of the tower from the foot of the building is 6060^\circ. If the tower is 50 m high, find the height of the building.
Q10
  1. Two poles of equal heights are standing opposite each other on either side of the road, which is 80 m wide. From a point between them on the road, the angles of elevation of the top of the poles are 6060^\circ and 3030^\circ, respectively. Find the height of the poles and the distances of the point from the poles.
Q11
  1. A TV tower stands vertically on a bank of a canal. From a point on the other bank directly opposite the tower, the angle of elevation of the top of the tower is 6060^\circ. From another point 20 m away from this point on the line joing this point to the foot of the tower, the angle of elevation of the top of the tower is 3030^\circ (see Fig. 9.12). Find the height of the tower and the width of the canal.
Q12
  1. From the top of a 7 m7\text{ m} high building, the angle of elevation of the top of a cable tower is 6060^\circ and the angle of depression of its foot is 4545^\circ. Determine the height of the tower.
Q13
  1. As observed from the top of a 75 m75\text{ m} high lighthouse from the sea-level, the angles of depression of two ships are 3030^\circ and 4545^\circ. If one ship is exactly behind the other on the same side of the lighthouse, find the distance between the two ships.
Q14
  1. A 1.2 m1.2\text{ m} tall girl spots a balloon moving with the wind in a horizontal line at a height of 88.2 m88.2\text{ m} from the ground. The angle of elevation of the balloon from the eyes of the girl at any instant is 6060^\circ. After some time, the angle of elevation reduces to 3030^\circ (see Fig. 9.13). Find the distance travelled by the balloon during the interval.
Q15
  1. A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of 3030^\circ, which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 6060^\circ. Find the time taken by the car to reach the foot of the tower from this point.
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