Question 12
When two chords intersect, each of them is divided into two line segments. Show that if the intersecting chords are of equal length, then the line segments of one chord are equal to the corresponding line segments of the other chord.
- We are given a circle where two equal chords, and , intersect at a point inside the circle.
- We need to show that the line segments of one chord are equal to the corresponding line segments of the other chord: and .
- Key Geometric Properties Used:
- Equal chords are equidistant from the centre of the circle.
- The perpendicular from the centre to a chord bisects the chord.
- Right-hypotenuse-side (RHS) congruency criterion.
Step 1 · Set Up Given, To Prove, and Construction
Let a circle with centre have two equal chords and intersecting at point inside the circle.Given:
To Prove:
Construction: Draw and . Join .
Step 2 · Prove Congruence of Triangles OME and ONE
In right-angled triangles and :
By RHS congruence criterion:
By CPCT (Corresponding Parts of Congruent Triangles):
Step 3 · Prove the Segments Are Equal
Since the perpendicular from the centre to a chord bisects the chord:
Since , their halves are also equal:
Adding equation and equation :
Subtracting equation from :
Hence proved, and .
- Confusing Bisected Halves with Chord Segments: Assuming that is the midpoint of the chords. The chords intersect at an arbitrary point , so in general; rather, the perpendiculars and bisect the chords at and .
- Missing the Equidistant Theorem: Forgetting the justification that holds because chords of equal length are equidistant from the centre.
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