Question 17
In a circle with centre , chords and are congruent. Explain why this statement is true: "The centre of the circle lies on the angle bisector of ".
- Let each circle have a radius , which means the diameter of each circle is .
- The height of the rectangle is equal to the diameter of one circle, and the length is equal to the sum of the diameters of all circles placed side by side.
- To find the fraction of the rectangle covered by the circles, calculate the ratio:
(i) Fig. 6.45: What fraction of the rectangle is covered by the circles?
Step 1 · Find Dimensions and Areas for Fig. 6.45
Let the radius of each circle be . Then the diameter of each circle is .
Dimensions of the rectangle:
Calculate the areas:
Calculate the fraction covered:
(i)
(ii) Fig. 6.46: What fraction of the rectangle is covered by the circles?
Step 1 · Find Dimensions and Areas for Fig. 6.46
Let the radius of each circle be . Then the diameter of each circle is .
Dimensions of the rectangle:
Calculate the areas:
Calculate the fraction covered:
(ii)
- Using Radius Instead of Diameter: Taking the height as instead of the diameter , leading to an incorrect rectangle area.
- Omitting the Number of Circles: Forgetting to multiply the single circle area by the total number of circles ( or ).
- General Invariance: Notice that for any number of identical circles packed in a single row inside a fitting rectangle, the fraction covered is always .
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