Circles and Geometric Shapes | EOT

Question 17

In a circle with centre OO, chords ABAB and ACAC are congruent. Explain why this statement is true: "The centre of the circle lies on the angle bisector of BAC\angle BAC".

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Solution
Understand the Question
  • Let each circle have a radius rr, which means the diameter of each circle is 2r2r.
  • The height of the rectangle is equal to the diameter of one circle, and the length is equal to the sum of the diameters of all circles placed side by side.
  • To find the fraction of the rectangle covered by the circles, calculate the ratio: Fraction=Total Area of CirclesArea of Rectangle\text{Fraction} = \dfrac{\text{Total Area of Circles}}{\text{Area of Rectangle}}

(i) Fig. 6.45: What fraction of the rectangle is covered by the circles?

Step 1 · Find Dimensions and Areas for Fig. 6.45

Let the radius of each circle be rr. Then the diameter of each circle is 2r2r.Diagram 1

Dimensions of the rectangle: Height=2r\text{Height} = 2r Length=3×(2r)=6r\text{Length} = 3 \times (2r) = 6r

Calculate the areas: Area of 3 circles=3×πr2=3πr2\text{Area of 3 circles} = 3 \times \pi r^2 = 3\pi r^2 Area of rectangle=(6r)×(2r)=12r2\text{Area of rectangle} = (6r) \times (2r) = 12r^2

Calculate the fraction covered:

Fraction=Area of circlesArea of rectangle=3πr212r2=3π12=π4\begin{aligned} \text{Fraction} &= \dfrac{\text{Area of circles}}{\text{Area of rectangle}} \\[0.6em] &= \dfrac{3\pi r^2}{12r^2} \\[0.6em] &= \dfrac{3\pi}{12} \\[0.6em] &= \dfrac{\pi}{4} \end{aligned}
Answer

(i) π4\dfrac{\pi}{4}

(ii) Fig. 6.46: What fraction of the rectangle is covered by the circles?

Step 1 · Find Dimensions and Areas for Fig. 6.46

Let the radius of each circle be rr. Then the diameter of each circle is 2r2r.Diagram 2

Dimensions of the rectangle: Height=2r\text{Height} = 2r Length=4×(2r)=8r\text{Length} = 4 \times (2r) = 8r

Calculate the areas: Area of 4 circles=4×πr2=4πr2\text{Area of 4 circles} = 4 \times \pi r^2 = 4\pi r^2 Area of rectangle=(8r)×(2r)=16r2\text{Area of rectangle} = (8r) \times (2r) = 16r^2

Calculate the fraction covered:

Fraction=Area of circlesArea of rectangle=4πr216r2=4π16=π4\begin{aligned} \text{Fraction} &= \dfrac{\text{Area of circles}}{\text{Area of rectangle}} \\[0.6em] &= \dfrac{4\pi r^2}{16r^2} \\[0.6em] &= \dfrac{4\pi}{16} \\[0.6em] &= \dfrac{\pi}{4} \end{aligned}
Answer

(ii) π4\dfrac{\pi}{4}

Common Mistakes
  • Using Radius Instead of Diameter: Taking the height as rr instead of the diameter 2r2r, leading to an incorrect rectangle area.
  • Omitting the Number of Circles: Forgetting to multiply the single circle area πr2\pi r^2 by the total number of circles (33 or 44).
  • General Invariance: Notice that for any number nn of identical circles packed in a single row inside a fitting rectangle, the fraction covered is always nπr2(n2r)(2r)=π4\dfrac{n \pi r^2}{(n \cdot 2r)(2r)} = \dfrac{\pi}{4}.

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Q17

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