Circles and Geometric Shapes | EOT

Question 22

"There is no chord of a circle that is longer than its diameter." How do you justify this statement?

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Solution
Understand the Question
  • A square of side s=2 unitss = 2\text{ units} contains a 4-petalled flower formed by intersecting circular arcs of radius r=2 unitsr = 2\text{ units}.
  • Each petal is bounded by 22 quarter-circle arcs, giving a total of 4×2=84 \times 2 = 8 quarter-circle arcs for the flower's perimeter.
  • The area of the flower is calculated by subtracting the area of the 44 unshaded corner regions (circular segments) from the total area of the square.

(i) Find the perimeter of the flower.

Step 1 · Calculate the Perimeter of the Flower

The square has side length s=2 unitss = 2\text{ units}. Each arc forming the petals is a quarter circle of radius r=2 unitsr = 2\text{ units}.Diagram 1

Side length of square (s)=2 units\text{Side length of square } (s) = 2 \text{ units} Radius of each arc (r)=s=2 units\text{Radius of each arc } (r) = s = 2 \text{ units}

Length of one quarter-circle arc:

Length of one quarter circle arc=14×2πr=12πr=12π(2)=π units\begin{aligned} \text{Length of one quarter circle arc} &= \dfrac{1}{4} \times 2\pi r \\[0.6em] &= \dfrac{1}{2}\pi r \\[0.6em] &= \dfrac{1}{2}\pi (2) \\[0.6em] &= \pi \text{ units} \end{aligned}

Since the flower consists of 88 identical arcs: Perimeter of flower=8×π=8π units\text{Perimeter of flower} = 8 \times \pi = 8\pi \text{ units}

Answer

(i) 8π units8\pi \text{ units}

(ii) Find the area of the flower.

Step 1 · Calculate Area of Square and Corner Segments

Area of the square:

Area of square=s2=(2)2=4 square units\begin{aligned} \text{Area of square} &= s^2 \\ &= (2)^2 \\ &= 4 \text{ square units} \end{aligned}

Each unshaded corner region is a segment formed by a sector of angle 9090^\circ and radius r=2 unitsr = 2\text{ units} minus a right isosceles triangle:

Area of one sector=90360×πr2=14π(2)2=π square units\begin{aligned} \text{Area of one sector} &= \dfrac{90^\circ}{360^\circ} \times \pi r^2 \\[0.6em] &= \dfrac{1}{4}\pi (2)^2 \\[0.6em] &= \pi \text{ square units} \end{aligned} Area of this triangle=12×base×height=12×2×2=2 square units\begin{aligned} \text{Area of this triangle} &= \dfrac{1}{2} \times \text{base} \times \text{height} \\[0.6em] &= \dfrac{1}{2} \times 2 \times 2 \\[0.6em] &= 2 \text{ square units} \end{aligned}

Area of one unshaded corner segment:

Area of one segment=Area of sectorArea of triangle=π2 square units\begin{aligned} \text{Area of one segment} &= \text{Area of sector} - \text{Area of triangle} \\ &= \pi - 2 \text{ square units} \end{aligned}

Total area of the 44 unshaded regions:

Total unshaded area=4×(π2)=4π8 square units\begin{aligned} \text{Total unshaded area} &= 4 \times (\pi - 2) \\ &= 4\pi - 8 \text{ square units} \end{aligned}

Area of the flower:

Area of flower=Area of squareTotal unshaded area=4(4π8)=44π+8=124π square units\begin{aligned} \text{Area of flower} &= \text{Area of square} - \text{Total unshaded area} \\ &= 4 - (4\pi - 8) \\ &= 4 - 4\pi + 8 \\ &= 12 - 4\pi \text{ square units} \end{aligned}
Answer

(ii) (124π) square units(12 - 4\pi) \text{ square units}

Common Mistakes
  • Arc Count Error: The flower has 44 petals and each petal has 22 arcs, making a total of 88 quarter-circle arcs, not 44.
  • Sign Error in Subtraction: When subtracting total unshaded area, forgetting to distribute the negative sign: 4(4π8)=124π4 - (4\pi - 8) = 12 - 4\pi, not 44π-4 - 4\pi.
  • Sector vs. Segment: Using the full sector area instead of the corner segment area (sector minus triangle) when subtracting unshaded regions.

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Q22

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