Question 10
Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.
Supplementary Angles: Two angles are supplementary if their sum is 180°. This proof shows that ∠APB + ∠BOA = 180°, making them supplementary.
Angle subtended at the centre: ∠BOA is the angle formed at the centre O by the two radii OA and OB — the radii drawn to the points of contact of the tangents.
Let's prove the relationship between the angles.
Step 1 — Identify perpendicular radii
Let O be the center of the circle. Let P be an external point. PA and PB are tangents from P. A and B are points of contact. OA is the radius to tangent PA. OB is the radius to tangent PB. Tangent-Radius Perpendicularity Theorem: The radius drawn to the point of tangency is always perpendicular to the tangent.
A radius is perpendicular to the tangent. So, angle OAP is 90°. Angle OBP is also 90°.

Step 2 — Sum of angles in quadrilateral
Consider the quadrilateral OAPB.
Angle Sum of a Quadrilateral: The four interior angles of any quadrilateral always add up to 360°.
The sum of angles in a quadrilateral is 360°. Let's add all the angles.
Substitute the known angle values.
Combine the constant terms.
Subtract 180° from both sides.
Answer
The angle between the two tangents () and the angle subtended by the line-segment joining the points of contact at the centre () are supplementary.
More questions in Exercise 10.2
In Q.1 to 3, choose the correct option and give justification.
- From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is (A) 7 cm (B) 12 cm (C) 15 cm (D) 24.5 cm
In Q.1 to 3, choose the correct option and give justification.
- In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that , then is equal to (A) (B) (C) (D)
In Q.1 to 3, choose the correct option and give justification.
- If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of , then is equal to (A) (B) (C) (D)
Prove that the tangents drawn at the ends of a diameter of a circle are parallel.
Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.
The length of a tangent from a point A at distance 5 cm from the centre of the circle is 4 cm. Find the radius of the circle.
Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.
A quadrilateral ABCD is drawn to circumscribe a circle (see Fig. 10.12). Prove that
In Fig. 10.13, XY and are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and at B. Prove that .
Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.
Prove that the parallelogram circumscribing a circle is a rhombus.
A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively (see Fig. 10.14). Find the sides AB and AC.
Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.