Circles | Exercise 10.2

Question 10

Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.

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Solution

Supplementary Angles: Two angles are supplementary if their sum is 180°. This proof shows that ∠APB + ∠BOA = 180°, making them supplementary.

Angle subtended at the centre: ∠BOA is the angle formed at the centre O by the two radii OA and OB — the radii drawn to the points of contact of the tangents.

Let's prove the relationship between the angles.

Step 1 — Identify perpendicular radii

Let O be the center of the circle. Let P be an external point. PA and PB are tangents from P. A and B are points of contact. OA is the radius to tangent PA. OB is the radius to tangent PB. Tangent-Radius Perpendicularity Theorem: The radius drawn to the point of tangency is always perpendicular to the tangent.

A radius is perpendicular to the tangent. So, angle OAP is 90°. Angle OBP is also 90°.

OAP=90\angle OAP = 90^\circ

OBP=90\angle OBP = 90^\circ

Diagram 1

Step 2 — Sum of angles in quadrilateral

Consider the quadrilateral OAPB.

Angle Sum of a Quadrilateral: The four interior angles of any quadrilateral always add up to 360°.

The sum of angles in a quadrilateral is 360°. Let's add all the angles.

OAP+APB+OBP+BOA=360\angle OAP + \angle APB + \angle OBP + \angle BOA = 360^\circ

Substitute the known angle values.

90+APB+90+BOA=36090^\circ + \angle APB + 90^\circ + \angle BOA = 360^\circ

Combine the constant terms.

180+APB+BOA=360180^\circ + \angle APB + \angle BOA = 360^\circ

Subtract 180° from both sides.

APB+BOA=360180\angle APB + \angle BOA = 360^\circ - 180^\circ

APB+BOA=180\boxed{\angle APB + \angle BOA = 180^\circ}

Answer

The angle between the two tangents (APB\angle APB) and the angle subtended by the line-segment joining the points of contact at the centre (BOA\angle BOA) are supplementary.

More questions in Exercise 10.2

Q1

In Q.1 to 3, choose the correct option and give justification.

  1. From a point Q, the length of the tangent to a circle is 24 cm and the distance of Q from the centre is 25 cm. The radius of the circle is (A) 7 cm (B) 12 cm (C) 15 cm (D) 24.5 cm
Q2

In Q.1 to 3, choose the correct option and give justification.

  1. In Fig. 10.11, if TP and TQ are the two tangents to a circle with centre O so that POQ=110\angle \text{POQ} = 110^\circ, then PTQ\angle \text{PTQ} is equal to (A) 6060^\circ (B) 7070^\circ (C) 8080^\circ (D) 9090^\circ
Q3

In Q.1 to 3, choose the correct option and give justification.

  1. If tangents PA and PB from a point P to a circle with centre O are inclined to each other at angle of 8080^\circ, then POA\angle \text{POA} is equal to (A) 5050^\circ (B) 6060^\circ (C) 7070^\circ (D) 8080^\circ
Q4

Prove that the tangents drawn at the ends of a diameter of a circle are parallel.

Q5

Prove that the perpendicular at the point of contact to the tangent to a circle passes through the centre.

Q6

The length of a tangent from a point A at distance 5 cm from the centre of the circle is 4 cm. Find the radius of the circle.

Q7

Two concentric circles are of radii 5 cm and 3 cm. Find the length of the chord of the larger circle which touches the smaller circle.

Q8

A quadrilateral ABCD is drawn to circumscribe a circle (see Fig. 10.12). Prove that

AB+CD=AD+BC\text{AB} + \text{CD} = \text{AD} + \text{BC}

Q9

In Fig. 10.13, XY and XY\text{X}'\text{Y}' are two parallel tangents to a circle with centre O and another tangent AB with point of contact C intersecting XY at A and XY\text{X}'\text{Y}' at B. Prove that AOB=90\angle\text{AOB} = 90^\circ.

Q10

Prove that the angle between the two tangents drawn from an external point to a circle is supplementary to the angle subtended by the line-segment joining the points of contact at the centre.

Q11

Prove that the parallelogram circumscribing a circle is a rhombus.

Q12

A triangle ABC is drawn to circumscribe a circle of radius 4 cm such that the segments BD and DC into which BC is divided by the point of contact D are of lengths 8 cm and 6 cm respectively (see Fig. 10.14). Find the sides AB and AC.

Q13

Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angles at the centre of the circle.

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