Exploring Algebraic Identities | EOT

Question 13

Find the value of

(i) x3+y312xy+64x^3 + y^3 - 12xy + 64, when x+y=4x + y = -4

(ii) x38y336xy216x^3 - 8y^3 - 36xy - 216, when x=2y+6x = 2y + 6

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Solution
Understand the Question

To find the values of these algebraic expressions, we use the algebraic expansion of the cube of a binomial:

  • (a+b)3=a3+b3+3ab(a+b)(a + b)^3 = a^3 + b^3 + 3ab(a + b)
  • (ab)3=a3b33ab(ab)(a - b)^3 = a^3 - b^3 - 3ab(a - b)

By cubing both sides of the given linear equations and substituting the known values, the required cubic expressions can be directly evaluated.

(i) Find the value of x3+y312xy+64x^3 + y^3 - 12xy + 64, when x+y=4x + y = -4

Step 1 · Cube both sides of the given equation

Given x+y=4x + y = -4

Cubing both sides (x+y)3=(4)3(x + y)^3 = (-4)^3

x3+y3+3xy(x+y)=64x^3 + y^3 + 3xy(x + y) = -64

Substitute x+y=4x + y = -4

x3+y3+3xy(4)=64x3+y312xy=64x3+y312xy+64=0\begin{aligned} x^3 + y^3 + 3xy(-4) &= -64 \\[0.6em] x^3 + y^3 - 12xy &= -64 \\[0.6em] x^3 + y^3 - 12xy + 64 &= 0 \end{aligned}
Answer

(i) 00

(ii) Find the value of x38y336xy216x^3 - 8y^3 - 36xy - 216, when x=2y+6x = 2y + 6

Step 1 · Rearrange and cube both sides

Given x=2y+6    x2y=6x = 2y + 6 \implies x - 2y = 6

Cubing both sides (x2y)3=63(x - 2y)^3 = 6^3

Using (ab)3=a3b33ab(ab)(a - b)^3 = a^3 - b^3 - 3ab(a - b) x3(2y)33(x)(2y)(x2y)=216x^3 - (2y)^3 - 3(x)(2y)(x - 2y) = 216

x38y36xy(x2y)=216x^3 - 8y^3 - 6xy(x - 2y) = 216

Substitute x2y=6x - 2y = 6

x38y36xy(6)=216x38y336xy=216x38y336xy216=0\begin{aligned} x^3 - 8y^3 - 6xy(6) &= 216 \\[0.6em] x^3 - 8y^3 - 36xy &= 216 \\[0.6em] x^3 - 8y^3 - 36xy - 216 &= 0 \end{aligned}
Answer

(ii) 00

Common Mistakes
  • Sign errors during cubing: Forgetting that (4)3=64(-4)^3 = -64 (a negative number cubed remains negative), or mishandling signs in the expansion of (x2y)3(x - 2y)^3.
  • Incorrect binomial cube formula: Confusing (ab)3=a3b33ab(ab)(a - b)^3 = a^3 - b^3 - 3ab(a - b) with a3b3+3ab(ab)a^3 - b^3 + 3ab(a - b).
  • Forgetting to substitute the inner term: Omitting the step where (x+y)(x + y) or (x2y)(x - 2y) inside 3ab()3ab(\dots) is replaced by its given numerical value.

More questions in EOT

Q1

Use suitable identities to find the following products:

(i) (3x+4)2(-3x + 4)^2

(ii) (2s+7)(2s7)(2s + 7)(2s - 7)

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(vi) (12r4r)2\left(\dfrac{1}{2r} - 4r\right)^2

(vii) (3m+4kl)2(-3m + 4k - l)^2

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Q2

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(ii) 104×96104 \times 96

(iii) 24×1624 \times 16

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(viii) (299)3(-299)^3

Q3

Factor the following algebraic expressions:

(i) 4y2+1+116y24y^2 + 1 + \dfrac{1}{16y^2}

(ii) 9m2125n29m^2 - \dfrac{1}{25n^2}

(iii) 27b3164b327b^3 - \dfrac{1}{64b^3}

(iv) x2+5x6+16x^2 + \dfrac{5x}{6} + \dfrac{1}{6}

(v) 27u3112527u25+9u2527u^3 - \dfrac{1}{125} - \dfrac{27u^2}{5} + \dfrac{9u}{25}

(vi) 64y3+1125z364y^3 + \dfrac{1}{125}z^3

(vii) p3+27q3+r39pqrp^3 + 27q^3 + r^3 - 9pqr

(viii) 9m212m+49m^2 - 12m + 4

(ix) 9x383y3+z33+6xyz9x^3 - \dfrac{8}{3}y^3 + \dfrac{z^3}{3} + 6xyz

(x) 4x2+9y2+36z2+12xz+36yz+24xy4x^2 + 9y^2 + 36z^2 + 12xz + 36yz + 24xy

(xi) 27u312169u22+u427u^3 - \dfrac{1}{216} - \dfrac{9u^2}{2} + \dfrac{u}{4}

Q4

Simplify the following:

(i) 4x2+4x+14x21\dfrac{4x^2 + 4x + 1}{4x^2 - 1}

(ii) 9(3a324b3)9a236b2\dfrac{9(3a^3 - 24b^3)}{9a^2 - 36b^2}

(iii) s3+125t3s22st35t2\dfrac{s^3 + 125t^3}{s^2 - 2st - 35t^2}

Note: Assume that the denominators are not equal to 0.

Q5

Find possible expressions for the length and breadth of each of the following rectangles whose areas are given by the following expressions in square units.

(i) 25a230ab+9b225a^2 - 30ab + 9b^2

(ii) 36s249t236s^2 - 49t^2

Q6

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(i) 6a224b26a^2 - 24b^2

(ii) 3ps215ps+12p3ps^2 - 15ps + 12p

Q7

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Q8

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Q9

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Q10

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Q11

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Q12

By factoring the expression, check that n3nn^3 - n is always divisible by 6 for all natural numbers nn. Give reasons.

Q13

Find the value of

(i) x3+y312xy+64x^3 + y^3 - 12xy + 64, when x+y=4x + y = -4

(ii) x38y336xy216x^3 - 8y^3 - 36xy - 216, when x=2y+6x = 2y + 6

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