Exploring Algebraic Identities | EOT

Question 9

A rectangular pool has area 2x2+7x+32x^2 + 7x + 3 square hastas. If its width is 2x+12x + 1 hastas, find its length. Hasta was a unit used to measure length.

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Solution
Understand the Question
  • The area of a rectangle is given by the formula Area=Length×Width\text{Area} = \text{Length} \times \text{Width}.
  • We are given:
    • Area=2x2+7x+3\text{Area} = 2x^2 + 7x + 3
    • Width=2x+1\text{Width} = 2x + 1
  • To find the length, we divide the area by the width: Length=AreaWidth\text{Length} = \dfrac{\text{Area}}{\text{Width}}, which can be solved by factorising the quadratic polynomial 2x2+7x+32x^2 + 7x + 3.

Step 1 · Factorise the Quadratic Expression for Area

To factorise 2x2+7x+32x^2 + 7x + 3, we find two numbers whose product is 2×3=62 \times 3 = 6 and whose sum is 77. The numbers are 66 and 11.

2x2+7x+3=2x2+6x+x+3=2x(x+3)+1(x+3)=(2x+1)(x+3)\begin{aligned} 2x^2 + 7x + 3 &= 2x^2 + 6x + x + 3 \\ &= 2x(x + 3) + 1(x + 3) \\ &= (2x + 1)(x + 3) \end{aligned}

Step 2 · Calculate the Length

Using the relationship Area=Length×Width\text{Area} = \text{Length} \times \text{Width}

Length=AreaWidth=(2x+1)(x+3)2x+1=x+3\begin{aligned} \text{Length} &= \dfrac{\text{Area}}{\text{Width}} \\[0.6em] &= \dfrac{(2x + 1)(x + 3)}{2x + 1} \\[0.6em] &= x + 3 \end{aligned}
Answer

(x+3) hastas(x + 3) \text{ hastas}

Common Mistakes
  • Splitting the Middle Term Error: Looking for factors of 33 instead of the product a×c=2×3=6a \times c = 2 \times 3 = 6.
  • Omitting the Unit: Forgetting to write the unit (hastas) in the final answer.

More questions in EOT

Q1

Use suitable identities to find the following products:

(i) (3x+4)2(-3x + 4)^2

(ii) (2s+7)(2s7)(2s + 7)(2s - 7)

(iii) (p2+12)(p212)\left(p^2 + \dfrac{1}{2}\right)\left(p^2 - \dfrac{1}{2}\right)

(iv) (2n+7)(2n7)(2n + 7)(2n - 7)

(v) (s2t)(s2+2st+4t2)(s - 2t)(s^2 + 2st + 4t^2)

(vi) (12r4r)2\left(\dfrac{1}{2r} - 4r\right)^2

(vii) (3m+4kl)2(-3m + 4k - l)^2

(viii) (x13y)3\left(x - \dfrac{1}{3}y\right)^3

(ix) (72k23m)3\left(\dfrac{7}{2}k - \dfrac{2}{3}m\right)^3

Q2

Find the values using suitable identities:

(i) 17×2117 \times 21

(ii) 104×96104 \times 96

(iii) 24×1624 \times 16

(iv) 1473147^3

(v) 1993199^3

(vi) 1273127^3

(vii) (107)3(-107)^3

(viii) (299)3(-299)^3

Q3

Factor the following algebraic expressions:

(i) 4y2+1+116y24y^2 + 1 + \dfrac{1}{16y^2}

(ii) 9m2125n29m^2 - \dfrac{1}{25n^2}

(iii) 27b3164b327b^3 - \dfrac{1}{64b^3}

(iv) x2+5x6+16x^2 + \dfrac{5x}{6} + \dfrac{1}{6}

(v) 27u3112527u25+9u2527u^3 - \dfrac{1}{125} - \dfrac{27u^2}{5} + \dfrac{9u}{25}

(vi) 64y3+1125z364y^3 + \dfrac{1}{125}z^3

(vii) p3+27q3+r39pqrp^3 + 27q^3 + r^3 - 9pqr

(viii) 9m212m+49m^2 - 12m + 4

(ix) 9x383y3+z33+6xyz9x^3 - \dfrac{8}{3}y^3 + \dfrac{z^3}{3} + 6xyz

(x) 4x2+9y2+36z2+12xz+36yz+24xy4x^2 + 9y^2 + 36z^2 + 12xz + 36yz + 24xy

(xi) 27u312169u22+u427u^3 - \dfrac{1}{216} - \dfrac{9u^2}{2} + \dfrac{u}{4}

Q4

Simplify the following:

(i) 4x2+4x+14x21\dfrac{4x^2 + 4x + 1}{4x^2 - 1}

(ii) 9(3a324b3)9a236b2\dfrac{9(3a^3 - 24b^3)}{9a^2 - 36b^2}

(iii) s3+125t3s22st35t2\dfrac{s^3 + 125t^3}{s^2 - 2st - 35t^2}

Note: Assume that the denominators are not equal to 0.

Q5

Find possible expressions for the length and breadth of each of the following rectangles whose areas are given by the following expressions in square units.

(i) 25a230ab+9b225a^2 - 30ab + 9b^2

(ii) 36s249t236s^2 - 49t^2

Q6

Find possible expressions for the length, breadth, and heights of each of the following cuboids whose volumes are given by the following expressions in cubic units.

(i) 6a224b26a^2 - 24b^2

(ii) 3ps215ps+12p3ps^2 - 15ps + 12p

Q7

The village playground is shaped as a square of side 40 metres. A path of width ss metres is created around the playground for people to walk. Find an expression for the area of the path in terms of ss.

Q8

If a number plus its reciprocal equals 103\dfrac{10}{3}, find the number.

Q9

A rectangular pool has area 2x2+7x+32x^2 + 7x + 3 square hastas. If its width is 2x+12x + 1 hastas, find its length. Hasta was a unit used to measure length.

Q10

If both x2x - 2 and x12x - \dfrac{1}{2} are factors of px2+5x+rpx^2 + 5x + r, show that p=rp = r.

Q11

If a+b+c=5a + b + c = 5 and ab+bc+ca=10ab + bc + ca = 10, then prove that a3+b3+c33abc=25a^3 + b^3 + c^3 - 3abc = -25.

Q12

By factoring the expression, check that n3nn^3 - n is always divisible by 6 for all natural numbers nn. Give reasons.

Q13

Find the value of

(i) x3+y312xy+64x^3 + y^3 - 12xy + 64, when x+y=4x + y = -4

(ii) x38y336xy216x^3 - 8y^3 - 36xy - 216, when x=2y+6x = 2y + 6

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