Circles and Geometric Shapes | Exercise 5.1

Question 1

Draw ΔABC\Delta\text{ABC} with AB=5 cm\text{AB} = 5\text{ cm}, A=70\angle\text{A} = 70^\circ and B=60\angle\text{B} = 60^\circ. Draw the circumcircle of ΔABC\Delta\text{ABC}. Is the centre inside or outside the triangle?

Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution
Understand the Question
  • To construct the triangle, draw base AB=5 cm\text{AB} = 5\text{ cm} and construct angles A=70\angle\text{A} = 70^\circ and B=60\angle\text{B} = 60^\circ to locate vertex C\text{C}.
  • The circumcentre of a triangle is the point of intersection of the perpendicular bisectors of its sides.
  • The circumcircle is drawn with the circumcentre as the centre and the distance to any vertex as the radius.
  • The position of the circumcentre depends on the angles of the triangle:
    • Acute triangle: Circumcentre lies inside.
    • Right triangle: Circumcentre lies on the hypotenuse (midpoint).
    • Obtuse triangle: Circumcentre lies outside.

Step 1 · Construct Triangle ABC

  1. Draw a line segment AB=5 cm\text{AB} = 5\text{ cm}.
  2. At point A\text{A}, construct CAB=70\angle\text{CAB} = 70^\circ.
  3. At point B\text{B}, construct CBA=60\angle\text{CBA} = 60^\circ.
  4. Let the two rays intersect at point C\text{C} to form ΔABC\Delta\text{ABC}.Diagram 1

Step 2 · Find Circumcentre O

  1. Draw the perpendicular bisectors of sides AB\text{AB}, BC\text{BC}, and AC\text{AC}.
  2. Mark their point of intersection as O\text{O}. Point O\text{O} is the circumcentre of ΔABC\Delta\text{ABC}.Diagram 2

Step 3 · Draw Circumcircle

  1. With O\text{O} as centre and radius equal to OA\text{OA} (or OB\text{OB}, OC\text{OC}), draw a circle.
  2. The circle passes through all three vertices A\text{A}, B\text{B}, and C\text{C}, forming the circumcircle.Diagram 3

Step 4 · Determine Circumcentre Position

Using the angle sum property of a triangle:

C=180(A+B)=180(70+60)=180130=50\begin{aligned} \angle\text{C} &= 180^\circ - (\angle\text{A} + \angle\text{B}) \\[0.6em] &= 180^\circ - (70^\circ + 60^\circ) \\[0.6em] &= 180^\circ - 130^\circ \\[0.6em] &= 50^\circ \end{aligned}

Since all three angles (A=70\angle\text{A} = 70^\circ, B=60\angle\text{B} = 60^\circ, and C=50\angle\text{C} = 50^\circ) are acute (<90< 90^\circ), ΔABC\Delta\text{ABC} is an acute-angled triangle.

Therefore, the circumcentre lies inside the triangle.

Answer

The centre is inside the triangle.

Common Mistakes
  • Circumcentre vs Incentre: Using angle bisectors instead of perpendicular bisectors of sides. Perpendicular bisectors give the circumcentre; angle bisectors give the incentre.
  • Position Misconception: Assuming circumcentres always lie inside the triangle. For obtuse-angled triangles, the circumcentre lies outside, and for right-angled triangles, it lies at the midpoint of the hypotenuse.

More questions in Exercise 5.1

Q1

Draw ΔABC\Delta\text{ABC} with AB=5 cm\text{AB} = 5\text{ cm}, A=70\angle\text{A} = 70^\circ and B=60\angle\text{B} = 60^\circ. Draw the circumcircle of ΔABC\Delta\text{ABC}. Is the centre inside or outside the triangle?

Q2

Draw ΔABC\Delta \text{ABC} with AB=5 cm\text{AB} = 5 \text{ cm}, A=100\angle \text{A} = 100^\circ, AC=4 cm\text{AC} = 4 \text{ cm}. Draw the circumcircle of ΔABC\Delta \text{ABC}. Is the centre inside or outside the triangle?

Q3

Draw ΔABC\Delta \text{ABC}, with AB=6 cm\text{AB} = 6\text{ cm}, BC=7 cm\text{BC} = 7\text{ cm} and CA=7 cm\text{CA} = 7\text{ cm}. Draw the circumcircle of ΔABC\Delta \text{ABC}. Let the circumcentre be OO. Measure OA\text{OA}, OB\text{OB}, OC\text{OC}.

Q4

What is the least possible radius of a circle through two points AA and BB?

← Back to Circles and Geometric Shapes