Circles and Geometric Shapes | Exercise 5.1

Question 2

Draw ΔABC\Delta \text{ABC} with AB=5 cm\text{AB} = 5 \text{ cm}, A=100\angle \text{A} = 100^\circ, AC=4 cm\text{AC} = 4 \text{ cm}. Draw the circumcircle of ΔABC\Delta \text{ABC}. Is the centre inside or outside the triangle?

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Solution
Understand the Question
  • To construct the triangle ΔABC\Delta \text{ABC}, we use the given side lengths AB=5 cm\text{AB} = 5\text{ cm}, AC=4 cm\text{AC} = 4\text{ cm}, and included angle A=100\angle \text{A} = 100^\circ.
  • The circumcentre of a triangle is the point of intersection of the perpendicular bisectors of its sides, and the circumcircle is drawn with the circumcentre as the centre passing through all three vertices.
  • Since A=100>90\angle \text{A} = 100^\circ > 90^\circ, ΔABC\Delta \text{ABC} is an obtuse-angled triangle, meaning its circumcentre lies outside the triangle.

Step 1 · Draw the Base

Draw a line segment AB=5 cm\text{AB} = 5\text{ cm}.Diagram 1

Step 2 · Construct Angle A

Using a protractor at point A\text{A}, construct BAX=100\angle \text{BAX} = 100^\circ and draw ray AX\text{AX}.Diagram 2

Step 3 · Locate Point C and Form Triangle ABC

With A\text{A} as centre and radius 4 cm4\text{ cm}, cut an arc on ray AX\text{AX} at point C\text{C}. Join BC\text{BC} to complete ΔABC\Delta \text{ABC}.Diagram 3

Step 4 · Draw the Perpendicular Bisector of AB

With centres A\text{A} and B\text{B} and a compass radius greater than 12AB\frac{1}{2}\text{AB}, draw arcs on both sides of AB\text{AB} intersecting each other. Draw a line passing through these intersection points to obtain the perpendicular bisector of AB\text{AB}.Diagram 4

Step 5 · Draw the Perpendicular Bisector of AC

With centres A\text{A} and C\text{C} and a compass radius greater than 12AC\frac{1}{2}\text{AC}, draw arcs on both sides of AC\text{AC} intersecting each other. Draw a line through these points to obtain the perpendicular bisector of AC\text{AC}.Diagram 5

Step 6 · Locate the Circumcentre

Let the perpendicular bisectors of AB\text{AB} and AC\text{AC} intersect at point O\text{O}. Point O\text{O} is the circumcentre of ΔABC\Delta \text{ABC}.Diagram 6

Step 7 · Draw the Circumcircle

With O\text{O} as centre and radius equal to OA\text{OA} (or OB\text{OB} or OC\text{OC}), draw a circle. This circle passes through all three vertices A\text{A}, B\text{B}, and C\text{C}.Diagram 7

Step 8 · Determine the Position of the Centre

Since A=100>90\angle \text{A} = 100^\circ > 90^\circ, ΔABC\Delta \text{ABC} is an obtuse-angled triangle.

Therefore, the circumcentre O\text{O} lies outside the triangle.

Answer

The centre is outside the triangle.

Common Mistakes
  • Position of Circumcentre: The circumcentre lies inside an acute triangle, on the hypotenuse of a right triangle, and outside an obtuse triangle. Since A=100\angle \text{A} = 100^\circ, the centre must be outside.
  • Bisector Radius: Drawing arcs with a radius less than or equal to half the side length will prevent the arcs from intersecting.
  • Incircle vs. Circumcircle: Confusing the circumcircle (intersection of perpendicular bisectors of sides) with the incircle (intersection of angle bisectors).

More questions in Exercise 5.1

Q1

Draw ΔABC\Delta\text{ABC} with AB=5 cm\text{AB} = 5\text{ cm}, A=70\angle\text{A} = 70^\circ and B=60\angle\text{B} = 60^\circ. Draw the circumcircle of ΔABC\Delta\text{ABC}. Is the centre inside or outside the triangle?

Q2

Draw ΔABC\Delta \text{ABC} with AB=5 cm\text{AB} = 5 \text{ cm}, A=100\angle \text{A} = 100^\circ, AC=4 cm\text{AC} = 4 \text{ cm}. Draw the circumcircle of ΔABC\Delta \text{ABC}. Is the centre inside or outside the triangle?

Q3

Draw ΔABC\Delta \text{ABC}, with AB=6 cm\text{AB} = 6\text{ cm}, BC=7 cm\text{BC} = 7\text{ cm} and CA=7 cm\text{CA} = 7\text{ cm}. Draw the circumcircle of ΔABC\Delta \text{ABC}. Let the circumcentre be OO. Measure OA\text{OA}, OB\text{OB}, OC\text{OC}.

Q4

What is the least possible radius of a circle through two points AA and BB?

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