Coordinate Geometry | Exercise 7.2

Question 8

If A and B are (2,2)(-2, -2) and (2,4)(2, -4), respectively, find the coordinates of P such that AP=37AB\text{AP} = \dfrac{3}{7} \text{AB} and P lies on the line segment AB.

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Solution
Understand the Question
  • Given points A(2,2)\text{A}(-2, -2) and B(2,4)\text{B}(2, -4), with P\text{P} lying on the line segment AB\text{AB} such that AP=37AB\text{AP} = \dfrac{3}{7} \text{AB}.
  • To find the coordinates of P\text{P}, we first determine the ratio AP:PB\text{AP} : \text{PB} in which P\text{P} divides the segment AB\text{AB}.
  • We then apply the section formula: x=mx2+nx1m+n,y=my2+ny1m+nx = \dfrac{mx_2 + nx_1}{m + n}, \quad y = \dfrac{my_2 + ny_1}{m + n}

Step 1 · Find the Ratio AP:PB\text{AP} : \text{PB}

Given AP=37AB\text{AP} = \dfrac{3}{7} \text{AB}.Since P\text{P} lies on AB\text{AB}:

PB=ABAP=AB37AB=47AB\begin{aligned} \text{PB} &= \text{AB} - \text{AP} \\ &= \text{AB} - \dfrac{3}{7} \text{AB} \\ &= \dfrac{4}{7} \text{AB} \end{aligned}

Therefore, the ratio is: APPB=37AB47AB=34\dfrac{\text{AP}}{\text{PB}} = \dfrac{\frac{3}{7}\text{AB}}{\frac{4}{7}\text{AB}} = \dfrac{3}{4}

So, P\text{P} divides AB\text{AB} internally in the ratio m:n=3:4m : n = 3 : 4.

Step 2 · Calculate Coordinates of P Using Section Formula

Here, (x1,y1)=(2,2)(x_1, y_1) = (-2, -2), (x2,y2)=(2,4)(x_2, y_2) = (2, -4), m=3m = 3, and n=4n = 4.

Using the section formula:

x=mx2+nx1m+n=3(2)+4(2)3+4=687=27\begin{aligned} x &= \dfrac{mx_2 + nx_1}{m + n} \\[0.6em] &= \dfrac{3(2) + 4(-2)}{3 + 4} \\[0.6em] &= \dfrac{6 - 8}{7} \\[0.6em] &= -\dfrac{2}{7} \end{aligned} y=my2+ny1m+n=3(4)+4(2)3+4=1287=207\begin{aligned} y &= \dfrac{my_2 + ny_1}{m + n} \\[0.6em] &= \dfrac{3(-4) + 4(-2)}{3 + 4} \\[0.6em] &= \dfrac{-12 - 8}{7} \\[0.6em] &= -\dfrac{20}{7} \end{aligned}

Therefore, the coordinates of P\text{P} are (27,207)\left(-\dfrac{2}{7}, -\dfrac{20}{7}\right).

Answer

(27,207)\left(-\dfrac{2}{7}, -\dfrac{20}{7}\right)

Common Mistakes
  • Ratio Error: Using the ratio 3:73:7 directly instead of calculating AP:PB=3:(73)=3:4\text{AP} : \text{PB} = 3 : (7 - 3) = 3 : 4.
  • Sign Errors in Coordinates: Forgetting the negative signs while substituting (x1,y1)=(2,2)(x_1, y_1) = (-2, -2) or (x2,y2)=(2,4)(x_2, y_2) = (2, -4) into the section formula.

More questions in Exercise 7.2

Q1

Find the coordinates of the point which divides the join of (1,7)(-1, 7) and (4,3)(4, -3) in the ratio 2:32 : 3.

Q2

Find the coordinates of the points of trisection of the line segment joining (4,1)(4, -1) and (2,3)(-2, -3).

Q3

To conduct Sports Day activities, in your rectangular shaped school ground ABCDABCD, lines have been drawn with chalk powder at a distance of 1 m1\text{ m} each. 100100 flower pots have been placed at a distance of 1 m1\text{ m} from each other along ADAD, as shown in Fig. 7.12. Niharika runs 14th\dfrac{1}{4}\text{th} the distance ADAD on the 2nd line and posts a green flag. Preet runs 15th\dfrac{1}{5}\text{th} the distance ADAD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?

Q4

Find the ratio in which the line segment joining the points (3,10)(-3, 10) and (6,8)(6, -8) is divided by (1,6)(-1, 6).

Q5

Find the ratio in which the line segment joining A(1,5)A(1, -5) and B(4,5)B(-4, 5) is divided by the xx-axis. Also find the coordinates of the point of division.

Q6

If (1,2)(1, 2), (4,y)(4, y), (x,6)(x, 6) and (3,5)(3, 5) are the vertices of a parallelogram taken in order, find xx and yy.

Q7

Find the coordinates of a point A\text{A}, where AB\text{AB} is the diameter of a circle whose centre is (2,3)(2, -3) and B\text{B} is (1,4)(1, 4).

Q8

If A and B are (2,2)(-2, -2) and (2,4)(2, -4), respectively, find the coordinates of P such that AP=37AB\text{AP} = \dfrac{3}{7} \text{AB} and P lies on the line segment AB.

Q9

Find the coordinates of the points which divide the line segment joining A(2,2)A(-2, 2) and B(2,8)B(2, 8) into four equal parts.

Q10

Find the area of a rhombus if its vertices are (3,0)(3, 0), (4,5)(4, 5), (1,4)(-1, 4) and (2,1)(-2, -1) taken in order.

[Hint : Area of a rhombus = 12\dfrac{1}{2} (product of its diagonals)]

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