Coordinate Geometry | Exercise 7.2

Question 9

Find the coordinates of the points which divide the line segment joining A(2,2)A(-2, 2) and B(2,8)B(2, 8) into four equal parts.

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Solution
Understand the Question
  • Dividing a line segment ABAB into four equal parts requires three points: PP, QQ, and RR.
  • These points divide the segment ABAB internally in the following ratios:
    • PP divides ABAB in the ratio 1:31:3
    • QQ is the midpoint of ABAB (ratio 1:11:1)
    • RR divides ABAB in the ratio 3:13:1
  • Section Formula: If a point (x,y)(x, y) divides the segment joining (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) in the ratio m:nm:n, then: x=mx2+nx1m+n,y=my2+ny1m+nx = \dfrac{mx_2 + nx_1}{m+n}, \quad y = \dfrac{my_2 + ny_1}{m+n}

Step 1 · Find the Coordinates of Point P

Let PP, QQ, and RR divide the line segment joining A(2,2)A(-2, 2) and B(2,8)B(2, 8) into four equal parts.Point PP divides ABAB in the ratio m:n=1:3m:n = 1:3.

Using the section formula for P(x,y)P(x, y):

Px=nx1+mx2m+n=3(2)+1(2)1+3=6+24=44=1\begin{aligned} P_x &= \dfrac{nx_1 + mx_2}{m+n} \\[0.6em] &= \dfrac{3(-2) + 1(2)}{1+3} \\[0.6em] &= \dfrac{-6 + 2}{4} \\[0.6em] &= \dfrac{-4}{4} \\[0.6em] &= -1 \end{aligned} Py=ny1+my2m+n=3(2)+1(8)1+3=6+84=144=72\begin{aligned} P_y &= \dfrac{ny_1 + my_2}{m+n} \\[0.6em] &= \dfrac{3(2) + 1(8)}{1+3} \\[0.6em] &= \dfrac{6 + 8}{4} \\[0.6em] &= \dfrac{14}{4} \\[0.6em] &= \dfrac{7}{2} \end{aligned}

Thus, P=(1,72)P = \left(-1, \dfrac{7}{2}\right).

Step 2 · Find the Coordinates of Point Q

Point QQ is the midpoint of ABAB, dividing it in the ratio 1:11:1.

Using the midpoint formula:

Qx=x1+x22=2+22=02=0\begin{aligned} Q_x &= \dfrac{x_1+x_2}{2} \\[0.6em] &= \dfrac{-2+2}{2} \\[0.6em] &= \dfrac{0}{2} \\[0.6em] &= 0 \end{aligned} Qy=y1+y22=2+82=102=5\begin{aligned} Q_y &= \dfrac{y_1+y_2}{2} \\[0.6em] &= \dfrac{2+8}{2} \\[0.6em] &= \dfrac{10}{2} \\[0.6em] &= 5 \end{aligned}

Thus, Q=(0,5)Q = (0, 5).

Step 3 · Find the Coordinates of Point R

Point RR divides ABAB in the ratio m:n=3:1m:n = 3:1.

Using the section formula for R(x,y)R(x, y):

Rx=nx1+mx2m+n=1(2)+3(2)3+1=2+64=44=1\begin{aligned} R_x &= \dfrac{nx_1 + mx_2}{m+n} \\[0.6em] &= \dfrac{1(-2) + 3(2)}{3+1} \\[0.6em] &= \dfrac{-2 + 6}{4} \\[0.6em] &= \dfrac{4}{4} \\[0.6em] &= 1 \end{aligned} Ry=ny1+my2m+n=1(2)+3(8)3+1=2+244=264=132\begin{aligned} R_y &= \dfrac{ny_1 + my_2}{m+n} \\[0.6em] &= \dfrac{1(2) + 3(8)}{3+1} \\[0.6em] &= \dfrac{2 + 24}{4} \\[0.6em] &= \dfrac{26}{4} \\[0.6em] &= \dfrac{13}{2} \end{aligned}

Thus, R=(1,132)R = \left(1, \dfrac{13}{2}\right).

Answer

(1,72)\left(-1, \dfrac{7}{2}\right), (0,5)(0, 5), and (1,132)\left(1, \dfrac{13}{2}\right)

Common Mistakes
  • Ratio Confusion: Dividing a line into 44 equal parts requires ratios of 1:31:3, 2:22:2, and 3:13:1, not 1:41:4 or 1:21:2.
  • Alternative Midpoint Method: You can also find QQ as the midpoint of ABAB, then PP as the midpoint of AQAQ, and RR as the midpoint of QBQB to simplify calculations.

More questions in Exercise 7.2

Q1

Find the coordinates of the point which divides the join of (1,7)(-1, 7) and (4,3)(4, -3) in the ratio 2:32 : 3.

Q2

Find the coordinates of the points of trisection of the line segment joining (4,1)(4, -1) and (2,3)(-2, -3).

Q3

To conduct Sports Day activities, in your rectangular shaped school ground ABCDABCD, lines have been drawn with chalk powder at a distance of 1 m1\text{ m} each. 100100 flower pots have been placed at a distance of 1 m1\text{ m} from each other along ADAD, as shown in Fig. 7.12. Niharika runs 14th\dfrac{1}{4}\text{th} the distance ADAD on the 2nd line and posts a green flag. Preet runs 15th\dfrac{1}{5}\text{th} the distance ADAD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?

Q4

Find the ratio in which the line segment joining the points (3,10)(-3, 10) and (6,8)(6, -8) is divided by (1,6)(-1, 6).

Q5

Find the ratio in which the line segment joining A(1,5)A(1, -5) and B(4,5)B(-4, 5) is divided by the xx-axis. Also find the coordinates of the point of division.

Q6

If (1,2)(1, 2), (4,y)(4, y), (x,6)(x, 6) and (3,5)(3, 5) are the vertices of a parallelogram taken in order, find xx and yy.

Q7

Find the coordinates of a point A\text{A}, where AB\text{AB} is the diameter of a circle whose centre is (2,3)(2, -3) and B\text{B} is (1,4)(1, 4).

Q8

If A and B are (2,2)(-2, -2) and (2,4)(2, -4), respectively, find the coordinates of P such that AP=37AB\text{AP} = \dfrac{3}{7} \text{AB} and P lies on the line segment AB.

Q9

Find the coordinates of the points which divide the line segment joining A(2,2)A(-2, 2) and B(2,8)B(2, 8) into four equal parts.

Q10

Find the area of a rhombus if its vertices are (3,0)(3, 0), (4,5)(4, 5), (1,4)(-1, 4) and (2,1)(-2, -1) taken in order.

[Hint : Area of a rhombus = 12\dfrac{1}{2} (product of its diagonals)]

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