Coordinate Geometry | Exercise 7.2

Question 10

Find the area of a rhombus if its vertices are (3,0)(3, 0), (4,5)(4, 5), (1,4)(-1, 4) and (2,1)(-2, -1) taken in order.

[Hint : Area of a rhombus = 12\dfrac{1}{2} (product of its diagonals)]

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Solution
Understand the Question
  • Let the given vertices taken in order be A(3,0)A(3, 0), B(4,5)B(4, 5), C(1,4)C(-1, 4), and D(2,1)D(-2, -1).
  • The diagonals of the rhombus are the line segments connecting opposite vertices: ACAC and BDBD.
  • The area of a rhombus is given by: Area=12×d1×d2=12×AC×BD\text{Area} = \dfrac{1}{2} \times d_1 \times d_2 = \dfrac{1}{2} \times AC \times BD
  • We first calculate the lengths of diagonals ACAC and BDBD using the distance formula: d=(x2x1)2+(y2y1)2d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}

Step 1 · Find Length of Diagonal ACAC

Let the vertices be A(3,0)A(3, 0), B(4,5)B(4, 5), C(1,4)C(-1, 4), and D(2,1)D(-2, -1).Diagram 1

Using the distance formula for A(3,0)A(3, 0) and C(1,4)C(-1, 4):

AC=(13)2+(40)2=(4)2+(4)2=16+16=32=16×2=42 units\begin{aligned} \text{AC} &= \sqrt{(-1 - 3)^2 + (4 - 0)^2} \\ &= \sqrt{(-4)^2 + (4)^2} \\ &= \sqrt{16 + 16} \\ &= \sqrt{32} \\ &= \sqrt{16 \times 2} \\ &= 4\sqrt{2} \text{ units} \end{aligned}

Step 2 · Find Length of Diagonal BDBD

Using the distance formula for B(4,5)B(4, 5) and D(2,1)D(-2, -1):

BD=(24)2+(15)2=(6)2+(6)2=36+36=72=36×2=62 units\begin{aligned} \text{BD} &= \sqrt{(-2 - 4)^2 + (-1 - 5)^2} \\ &= \sqrt{(-6)^2 + (-6)^2} \\ &= \sqrt{36 + 36} \\ &= \sqrt{72} \\ &= \sqrt{36 \times 2} \\ &= 6\sqrt{2} \text{ units} \end{aligned}

Step 3 · Calculate Area of the Rhombus

Using the formula Area=12×d1×d2\text{Area} = \dfrac{1}{2} \times d_1 \times d_2:

Area=12×AC×BD=12×(42)×(62)=12×24×(2×2)=12×24×2=24 square units\begin{aligned} \text{Area} &= \dfrac{1}{2} \times \text{AC} \times \text{BD} \\[0.6em] &= \dfrac{1}{2} \times (4\sqrt{2}) \times (6\sqrt{2}) \\[0.6em] &= \dfrac{1}{2} \times 24 \times (\sqrt{2} \times \sqrt{2}) \\[0.6em] &= \dfrac{1}{2} \times 24 \times 2 \\[0.6em] &= 24 \text{ square units} \end{aligned}
Answer

24 square units24\text{ square units}

Common Mistakes
  • Choosing Adjacent Sides Instead of Diagonals: Diagonals connect opposite vertices (ACAC and BDBD), not adjacent ones (ABAB or BCBC).
  • Sign Errors in Distance Formula: Carefully handle negative coordinates inside parentheses, e.g., (13)2=(4)2=+16(-1 - 3)^2 = (-4)^2 = +16, not 16-16.
  • Simplifying Product of Radicals: Remember that 2×2=2\sqrt{2} \times \sqrt{2} = 2, so (42)(62)=24×2=48(4\sqrt{2})(6\sqrt{2}) = 24 \times 2 = 48.

More questions in Exercise 7.2

Q1

Find the coordinates of the point which divides the join of (1,7)(-1, 7) and (4,3)(4, -3) in the ratio 2:32 : 3.

Q2

Find the coordinates of the points of trisection of the line segment joining (4,1)(4, -1) and (2,3)(-2, -3).

Q3

To conduct Sports Day activities, in your rectangular shaped school ground ABCDABCD, lines have been drawn with chalk powder at a distance of 1 m1\text{ m} each. 100100 flower pots have been placed at a distance of 1 m1\text{ m} from each other along ADAD, as shown in Fig. 7.12. Niharika runs 14th\dfrac{1}{4}\text{th} the distance ADAD on the 2nd line and posts a green flag. Preet runs 15th\dfrac{1}{5}\text{th} the distance ADAD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?

Q4

Find the ratio in which the line segment joining the points (3,10)(-3, 10) and (6,8)(6, -8) is divided by (1,6)(-1, 6).

Q5

Find the ratio in which the line segment joining A(1,5)A(1, -5) and B(4,5)B(-4, 5) is divided by the xx-axis. Also find the coordinates of the point of division.

Q6

If (1,2)(1, 2), (4,y)(4, y), (x,6)(x, 6) and (3,5)(3, 5) are the vertices of a parallelogram taken in order, find xx and yy.

Q7

Find the coordinates of a point A\text{A}, where AB\text{AB} is the diameter of a circle whose centre is (2,3)(2, -3) and B\text{B} is (1,4)(1, 4).

Q8

If A and B are (2,2)(-2, -2) and (2,4)(2, -4), respectively, find the coordinates of P such that AP=37AB\text{AP} = \dfrac{3}{7} \text{AB} and P lies on the line segment AB.

Q9

Find the coordinates of the points which divide the line segment joining A(2,2)A(-2, 2) and B(2,8)B(2, 8) into four equal parts.

Q10

Find the area of a rhombus if its vertices are (3,0)(3, 0), (4,5)(4, 5), (1,4)(-1, 4) and (2,1)(-2, -1) taken in order.

[Hint : Area of a rhombus = 12\dfrac{1}{2} (product of its diagonals)]

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