The World of Numbers | Exercise 3.3

Question 7

Simplify the following using the distributive property:

79(6734)\dfrac{7}{9}\left(\dfrac{6}{7} - \dfrac{3}{4}\right)

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Solution
Understand the Question
  • The distributive property of multiplication over subtraction states that a(bc)=(a×b)(a×c)a(b - c) = (a \times b) - (a \times c).
  • To simplify the expression using this property, multiply 79\dfrac{7}{9} with each fraction inside the parentheses separately and then subtract the two products.

Step 1 · Apply Distributive Property

Using the distributive property a(bc)=(a×b)(a×c)a(b - c) = (a \times b) - (a \times c)

79(6734)=(79×67)(79×34)=42632136=23712\begin{aligned} \dfrac{7}{9}\left(\dfrac{6}{7} - \dfrac{3}{4}\right) &= \left(\dfrac{7}{9} \times \dfrac{6}{7}\right) - \left(\dfrac{7}{9} \times \dfrac{3}{4}\right) \\[0.6em] &= \dfrac{42}{63} - \dfrac{21}{36} \\[0.6em] &= \dfrac{2}{3} - \dfrac{7}{12} \end{aligned}

Step 2 · Subtract the Fractions

The LCM\text{LCM} of denominators 33 and 1212 is 1212.

Convert 23\dfrac{2}{3} to have a denominator of 1212 23=2×43×4=812\dfrac{2}{3} = \dfrac{2 \times 4}{3 \times 4} = \dfrac{8}{12}

Now subtract the fractions

812712=8712=112\begin{aligned} \dfrac{8}{12} - \dfrac{7}{12} &= \dfrac{8 - 7}{12} \\[0.6em] &= \dfrac{1}{12} \end{aligned}
Answer

112\dfrac{1}{12}

Common Mistakes
  • Partial Distribution: Multiplying 79\dfrac{7}{9} only by the first term 67\dfrac{6}{7} and forgetting to multiply it by the second term 34\dfrac{3}{4}.
  • Sign Error: Adding the products instead of subtracting them, misapplying a(bc)=abaca(b - c) = ab - ac as ab+acab + ac.
  • Direct Simplification: Solving the bracket first (6734)\left(\dfrac{6}{7} - \dfrac{3}{4}\right) directly without using the distributive property as specifically instructed by the question.

More questions in Exercise 3.3

Q1

Prove that the following rational numbers are equal:

(i) 23\dfrac{2}{3} and 46\dfrac{4}{6}

(ii) 54\dfrac{5}{4} and 108\dfrac{10}{8}

(iii) 35-\dfrac{3}{5} and 610-\dfrac{6}{10}

(iv) 93\dfrac{9}{3} and 33

Q2

Find the sum:

(i) 25+310\dfrac{2}{5} + \dfrac{3}{10}

(ii) 712+58\dfrac{7}{12} + \dfrac{5}{8}

(iii) 47+314-\dfrac{4}{7} + \dfrac{3}{14}

Q3

Find the difference:

(i) 5614\dfrac{5}{6} - \dfrac{1}{4}

(ii) 11834\dfrac{11}{8} - \dfrac{3}{4}

(iii) 79(23)-\dfrac{7}{9} - \left(-\dfrac{2}{3}\right)

Q4

Find the product:

(i) 23×310\dfrac{2}{3} \times \dfrac{3}{10}

(ii) 711×58\dfrac{7}{11} \times \dfrac{5}{8}

(iii) 47×514-\dfrac{4}{7} \times \dfrac{5}{14}

Q5

Find the quotient:

(i) 23÷310\dfrac{2}{3} \div \dfrac{3}{10}

(ii) 711÷58\dfrac{7}{11} \div \dfrac{5}{8}

(iii) 47÷514-\dfrac{4}{7} \div \dfrac{5}{14}

Q6

Show that:

(12+34)×83=12×83+34×83\left(\dfrac{1}{2} + \dfrac{3}{4}\right) \times \dfrac{8}{3} = \dfrac{1}{2} \times \dfrac{8}{3} + \dfrac{3}{4} \times \dfrac{8}{3}

Q7

Simplify the following using the distributive property:

79(6734)\dfrac{7}{9}\left(\dfrac{6}{7} - \dfrac{3}{4}\right)

Q8

Find the rational number xx such that:

56(x+35)=56x+12\dfrac{5}{6}\left(x + \dfrac{3}{5}\right) = \dfrac{5}{6}x + \dfrac{1}{2}

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