The World of Numbers | Exercise 3.3

Question 5

Find the quotient:

(i) 23÷310\dfrac{2}{3} \div \dfrac{3}{10}

(ii) 711÷58\dfrac{7}{11} \div \dfrac{5}{8}

(iii) 47÷514-\dfrac{4}{7} \div \dfrac{5}{14}

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Solution
Understand the Question
  • To divide one fraction by another, multiply the first fraction (dividend) by the reciprocal of the second fraction (divisor): ab÷cd=ab×dc=a×db×c\dfrac{a}{b} \div \dfrac{c}{d} = \dfrac{a}{b} \times \dfrac{d}{c} = \dfrac{a \times d}{b \times c}
  • Simplify the resulting fraction to its simplest form whenever common factors exist between the numerator and denominator.

(i) 23÷310\dfrac{2}{3} \div \dfrac{3}{10}

Step 1 · Multiply by the Reciprocal

Multiply 23\dfrac{2}{3} by the reciprocal of 310\dfrac{3}{10}, which is 103\dfrac{10}{3}:

23÷310=23×103=2×103×3=209\begin{aligned} \dfrac{2}{3} \div \dfrac{3}{10} &= \dfrac{2}{3} \times \dfrac{10}{3} \\[0.6em] &= \dfrac{2 \times 10}{3 \times 3} \\[0.6em] &= \dfrac{20}{9} \end{aligned}
Answer

(i) 209\dfrac{20}{9}

(ii) 711÷58\dfrac{7}{11} \div \dfrac{5}{8}

Step 1 · Multiply by the Reciprocal

Multiply 711\dfrac{7}{11} by the reciprocal of 58\dfrac{5}{8}, which is 85\dfrac{8}{5}:

711÷58=711×85=7×811×5=5655\begin{aligned} \dfrac{7}{11} \div \dfrac{5}{8} &= \dfrac{7}{11} \times \dfrac{8}{5} \\[0.6em] &= \dfrac{7 \times 8}{11 \times 5} \\[0.6em] &= \dfrac{56}{55} \end{aligned}
Answer

(ii) 5655\dfrac{56}{55}

(iii) 47÷514-\dfrac{4}{7} \div \dfrac{5}{14}

Step 1 · Multiply by the Reciprocal and Simplify

Multiply 47-\dfrac{4}{7} by the reciprocal of 514\dfrac{5}{14}, which is 145\dfrac{14}{5}:

47÷514=47×145=4×147×5=5635\begin{aligned} -\dfrac{4}{7} \div \dfrac{5}{14} &= -\dfrac{4}{7} \times \dfrac{14}{5} \\[0.6em] &= \dfrac{-4 \times 14}{7 \times 5} \\[0.6em] &= \dfrac{-56}{35} \end{aligned}

Divide both numerator and denominator by their common factor 77:

=56÷735÷7=85\begin{aligned} &= \dfrac{-56 \div 7}{35 \div 7} \\[0.6em] &= -\dfrac{8}{5} \end{aligned}
Answer

(iii) 85-\dfrac{8}{5}

Common Mistakes
  • Inverting the Wrong Fraction: Inverting the first fraction (dividend) instead of the second fraction (divisor).
  • Forgetting to Invert: Multiplying the numerators and denominators directly without taking the reciprocal of the divisor first.
  • Sign Errors: Dropping the negative sign when multiplying or reducing fractions in part (iii).
  • Not Reducing to Lowest Terms: Leaving the answer as 5635-\dfrac{56}{35} instead of simplifying to 85-\dfrac{8}{5}.

More questions in Exercise 3.3

Q1

Prove that the following rational numbers are equal:

(i) 23\dfrac{2}{3} and 46\dfrac{4}{6}

(ii) 54\dfrac{5}{4} and 108\dfrac{10}{8}

(iii) 35-\dfrac{3}{5} and 610-\dfrac{6}{10}

(iv) 93\dfrac{9}{3} and 33

Q2

Find the sum:

(i) 25+310\dfrac{2}{5} + \dfrac{3}{10}

(ii) 712+58\dfrac{7}{12} + \dfrac{5}{8}

(iii) 47+314-\dfrac{4}{7} + \dfrac{3}{14}

Q3

Find the difference:

(i) 5614\dfrac{5}{6} - \dfrac{1}{4}

(ii) 11834\dfrac{11}{8} - \dfrac{3}{4}

(iii) 79(23)-\dfrac{7}{9} - \left(-\dfrac{2}{3}\right)

Q4

Find the product:

(i) 23×310\dfrac{2}{3} \times \dfrac{3}{10}

(ii) 711×58\dfrac{7}{11} \times \dfrac{5}{8}

(iii) 47×514-\dfrac{4}{7} \times \dfrac{5}{14}

Q5

Find the quotient:

(i) 23÷310\dfrac{2}{3} \div \dfrac{3}{10}

(ii) 711÷58\dfrac{7}{11} \div \dfrac{5}{8}

(iii) 47÷514-\dfrac{4}{7} \div \dfrac{5}{14}

Q6

Show that:

(12+34)×83=12×83+34×83\left(\dfrac{1}{2} + \dfrac{3}{4}\right) \times \dfrac{8}{3} = \dfrac{1}{2} \times \dfrac{8}{3} + \dfrac{3}{4} \times \dfrac{8}{3}

Q7

Simplify the following using the distributive property:

79(6734)\dfrac{7}{9}\left(\dfrac{6}{7} - \dfrac{3}{4}\right)

Q8

Find the rational number xx such that:

56(x+35)=56x+12\dfrac{5}{6}\left(x + \dfrac{3}{5}\right) = \dfrac{5}{6}x + \dfrac{1}{2}

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