Predicting What Comes Next: Sequences and Progressions | Exercise 8.3

Question 3

A sequence is given by the recursive rule t1=2t_1 = 2, tn+1=3tn2t_{n+1} = 3t_n - 2 for n1n \ge 1. Which term of the sequence is 730?

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Solution

We need to find the term number for 730 in the given sequence.

Step 1 — Find the term 730

Let's find the first term. It is given as 2.

t1=2t_1 = 2

Now, we find the second term. We use the given rule tn+1=3tn2t_{n+1} = 3t_n - 2.

t2=3t12t_2 = 3t_1 - 2

=3(2)2= 3(2) - 2

=62= 6 - 2

=4= 4

Next, we find the third term.

t3=3t22t_3 = 3t_2 - 2

=3(4)2= 3(4) - 2

=122= 12 - 2

=10= 10

Let's find the fourth term.

t4=3t32t_4 = 3t_3 - 2

=3(10)2= 3(10) - 2

=302= 30 - 2

=28= 28

Now, we find the fifth term.

t5=3t42t_5 = 3t_4 - 2

=3(28)2= 3(28) - 2

=842= 84 - 2

=82= 82

Let's find the sixth term.

t6=3t52t_6 = 3t_5 - 2

=3(82)2= 3(82) - 2

=2462= 246 - 2

=244= 244

Finally, we find the seventh term.

t7=3t62t_7 = 3t_6 - 2

=3(244)2= 3(244) - 2

=7322= 732 - 2

=730= 730

This means 730 is the

7th term\boxed{7\text{th term}}

Answer

(i) The term 730 is the 7th term of the sequence.

More questions in Exercise 8.3

Q1

Find the 12th12^{\text{th}} term of a GP with common ratio 2, whose 8th8^{\text{th}} term is 192.

Q2

Find the 10th10^{\text{th}} and nthn^{\text{th}} terms of the GP: 5, 25, 125, ... .

Q3

A sequence is given by the recursive rule t1=2t_1 = 2, tn+1=3tn2t_{n+1} = 3t_n - 2 for n1n \ge 1. Which term of the sequence is 730?

Q4

Which term of the GP: 2, 6, 18, ... is 4374? Write the explicit formula as well as the recursive formula for the nthn^{\text{th}} term.

Q5

A ball is dropped from a height of 80 metres. After hitting the ground, it bounces back to 60% of the height from which it fell. It continues bouncing in this way—each time rising to 60% of the previous height.

(i) What height does the ball reach after the 5th5^{\text{th}} bounce? (ii) What is the total vertical distance the ball has travelled by the time it hits the ground for the 6th6^{\text{th}} time?

Q6

Which term of the sequence 2,22,4,2, 2\sqrt{2}, 4, \dots is 128?

Q7

Fig. 8.12 shows Stages 0 to 3 of the Sierpiński square carpet. Stage 0 of this fractal is a square sheet of paper. To construct Stage 1, each side of the square is trisected and the points of trisection of opposite sides are joined to obtain nine smaller squares. The centre square is then removed and the 8 smaller squares are retained, leaving a square hole in the centre. The same process is repeated on the eight smaller shaded squares to obtain Stage 2 and so on.

Look at Fig. 8.12 and try to answer the following questions.

(i) How many red squares are there in Stages 0 to 3? (ii) Can you predict the number of red squares in Stages 4 and 5? (iii) Can you find a rule for the number of red squares at the nthn^{\text{th}} stage? Write the explicit formula as well as the recursive formula for the number of red squares at any stage. (iv) Suppose the area of the square in Stage 0 is 1 square unit. What is the area of the red region in Stages 1, 2 and 3? What will be the area of the red region in Stages 4 and 5? Find the explicit as well as the recursive formula for the area of the red region at the nthn^{\text{th}} stage. What happens to this area as nn, the number of stages, goes on increasing?

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