Question 5
One diagonal of a rhombus is twice as long as the other diagonal. If the rhombus has area , find the length of the shorter diagonal.
- The area of a rhombus is given by the formula , where and are the lengths of the diagonals.
- Given that one diagonal is twice the length of the other, let the shorter diagonal be and the longer diagonal be .
- Substitute the given area () into the formula to solve for .
Step 1 · Set Up the Equation
Let the shorter diagonal be and the longer diagonal be .
Using the area formula for a rhombus
Given
Step 2 · Calculate the Shorter Diagonal
Solve for by taking the square root
- Forgetting the Factor: Using instead of .
- Incomplete Radical Simplification: Leaving the answer as instead of extracting the perfect square factor .
More questions in Exercise 6.2
Find the area of triangle ADE in Fig. 6.31.
The parallel sides of a trapezium are and . If its non-parallel sides are both equal, each being , find the area of the trapezium.
Find the area of a triangle, given that its sides are and long, and its perimeter is .
The sides of a triangular plot are in the ratio ; its perimeter is . Find its area.
One diagonal of a rhombus is twice as long as the other diagonal. If the rhombus has area , find the length of the shorter diagonal.
is a parallelogram. and are any two points on side . What can you say about the ratio ?
is any point on the diagonal of a parallelogram . Prove that the areas of triangles and are equal.
If the mid-points of the sides of a 4-gon (also known as a quadrilateral, but we prefer to call it a ‘4-gon’) are joined in order, prove that the area of the parallelogram thus formed will be half of the area of the given 4-gon. (You may wonder whether the 4-gon thus formed is always a parallelogram, and if so, why? These questions will be tackled and answered in the chapter on quadrilaterals.)
In , the midpoint of is (Fig. 6.32). Median is drawn. is any point on . Show that .
Given a square , let be a point within it. Join , , , (Fig. 6.33). What is the ratio of the areas of the red region ( and ) and the green region ( and )?
In , is the midpoint of . is any point on , and is a point on such that . is joined (Fig. 6.34). Prove that