Working with Fractions | IT

Question 5

Context: If we assume 1 gold dinar = 12 silver drammas, 1 silver dramma = 4 copper panas, 1 copper pana = 6 mashakas, and 1 pana = 30 cowrie shells,

Given: 1 copper pana = 148\dfrac{1}{48} gold dinar (112×14)\left(\dfrac{1}{12} \times \dfrac{1}{4}\right)

Fill in the blanks:

(i) 1 cowrie shell = ______ copper panas

(ii) 1 cowrie shell = ______ gold dinar.

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Solution
Understand the Question
  • We are given conversion relationships between different units of currency:
    • 1 copper pana=30 cowrie shells    1 cowrie shell=130 copper pana1 \text{ copper pana} = 30 \text{ cowrie shells} \implies 1 \text{ cowrie shell} = \dfrac{1}{30} \text{ copper pana}
    • 1 copper pana=148 gold dinar1 \text{ copper pana} = \dfrac{1}{48} \text{ gold dinar}
  • To convert cowrie shells into gold dinars, substitute the value of 1 copper pana1 \text{ copper pana} in terms of gold dinars into the fraction for 1 cowrie shell1 \text{ cowrie shell}.

(i) 1 cowrie shell = ______ copper panas

Step 1 · Convert Cowrie Shells to Copper Panas

Given 1 copper pana=30 cowrie shells1 \text{ copper pana} = 30 \text{ cowrie shells}Diagram 1

Therefore 1 cowrie shell=130 copper panas1 \text{ cowrie shell} = \dfrac{1}{30} \text{ copper panas}

Answer

(i) 130\dfrac{1}{30}

(ii) 1 cowrie shell = ______ gold dinar.

Step 1 · Convert Cowrie Shells to Gold Dinars

From part (i), 1 cowrie shell=130 copper panas1 \text{ cowrie shell} = \dfrac{1}{30} \text{ copper panas}.

Given that 1 copper pana=148 gold dinar1 \text{ copper pana} = \dfrac{1}{48} \text{ gold dinar}, substitute this into the expression:

1 cowrie shell=130×(148 gold dinar)=1×130×48 gold dinar=11440 gold dinar\begin{aligned} 1 \text{ cowrie shell} &= \dfrac{1}{30} \times \left(\dfrac{1}{48} \text{ gold dinar}\right) \\[0.6em] &= \dfrac{1 \times 1}{30 \times 48} \text{ gold dinar} \\[0.6em] &= \dfrac{1}{1440} \text{ gold dinar} \end{aligned}
Answer

(ii) 11440\dfrac{1}{1440}

Common Mistakes
  • Multiplying Instead of Dividing: Confusing the conversion direction by writing 1 cowrie shell=30 copper panas1 \text{ cowrie shell} = 30 \text{ copper panas} instead of the reciprocal 130\dfrac{1}{30}.
  • Multiplication Errors in the Denominator: Making an arithmetic mistake when calculating 30×48=144030 \times 48 = 1440.

More questions in IT

Q1

Context: In Fig. 8.3, the length and breadth of the shaded rectangle are 12\dfrac{1}{2} unit and 14\dfrac{1}{4} unit, and its area is 18\dfrac{1}{8} square units.

Q. Do you see any relation between the area and the product of length and breadth?

Q2

In each of the division problems above, observe how we found the answer. Can we frame a rule that tells us how to divide two fractions?

Q3

When do you think the quotient is less than the dividend and when is it greater than the dividend?

Is there a similar relationship between the divisor and the quotient?

Q4

In each of the figures given below, find the fraction of the big square that the shaded region occupies.

Q5

Context: If we assume 1 gold dinar = 12 silver drammas, 1 silver dramma = 4 copper panas, 1 copper pana = 6 mashakas, and 1 pana = 30 cowrie shells,

Given: 1 copper pana = 148\dfrac{1}{48} gold dinar (112×14)\left(\dfrac{1}{12} \times \dfrac{1}{4}\right)

Fill in the blanks:

(i) 1 cowrie shell = ______ copper panas

(ii) 1 cowrie shell = ______ gold dinar.

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