Constructions and Tilings | IT

Question 11

How do we construct this figure?

Question diagram 1
Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution
Understand the Question
  • The figure is a symmetric 8-petal flower inscribed inside a circle.
  • To construct it:
    1. Draw a base circle with center OO and divide it into 8 equal angular sectors (4545^\circ each) to get petal tips P1,P2,,P8P_1, P_2, \dots, P_8.
    2. Construct outward-curving circular arcs connecting center OO to each tip PiP_i using arc centers found at the intersection of the perpendicular bisector of OPiOP_i and the adjacent radial lines.
    3. Repeat symmetrically for all 8 petals.

Step 1 · Draw the Base Circle and Center

Mark a center point OO. Using a compass set to a convenient radius RR, draw a circle with center OO. This circle defines the outer tips of all petals.Diagram 1

Step 2 · Divide the Circle into 8 Equal Parts

Diagram 2

  1. Draw a horizontal diameter through OO meeting the circle at P1P_1 and P5P_5.
  2. Draw a vertical diameter through OO perpendicular to the first, meeting the circle at P3P_3 and P7P_7.
  3. Bisect the four 9090^\circ angles (e.g., P1OP3\angle P_1OP_3 and P3OP5\angle P_3OP_5) by drawing intersecting arcs from adjacent points.
  4. Extend the bisectors through center OO to meet the circle at P2,P4,P6,P_2, P_4, P_6, and P8P_8.

This gives 8 equally spaced points on the circumference at 4545^\circ intervals.

Step 3 · Construct the First Petal

Diagram 3

For the petal with tip P1P_1:

  1. Draw the perpendicular bisector of segment OP1OP_1.
  2. Let the bisector intersect radial line OP2OP_2 at center C1C_1, and radial line OP8OP_8 at center C2C_2.
  3. With center C1C_1 and radius C1OC_1O, draw an arc from OO to P1P_1 (left side of petal).
  4. With center C2C_2 and radius C2OC_2O, draw an arc from OO to P1P_1 (right side of petal).

Step 4 · Construct the Remaining Petals

Diagram 4

Repeat the process for each tip PiP_i (for i=2,3,,8i = 2, 3, \dots, 8):

  • Draw the perpendicular bisector of OPiOP_i.
  • Find its intersections with adjacent radial lines OPi+1OP_{i+1} and OPi1OP_{i-1} to locate the arc centers Ci,leftC_{i, \text{left}} and Ci,rightC_{i, \text{right}}.
  • Draw the two symmetric arcs connecting OO to PiP_i.

Drawing all 16 arcs completes the 8-petal flower.

Answer

The 8-petal symmetrical flower design is constructed by dividing the circle into 8 equal parts of 4545^\circ each and drawing symmetric circular arcs from center OO to each vertex PiP_i.

Common Mistakes
  • Inaccurate Angle Bisection: Imprecise angle bisectors lead to unequal petal widths and broken rotational symmetry.
  • Incorrect Arc Centers: Forgetting to use the perpendicular bisector of OPiOP_i when locating centers C1C_1 and C2C_2, resulting in arcs that do not smoothly meet at both OO and PiP_i.
  • Radius Inconsistency: Changing the compass width between drawing the left and right arcs of a petal, causing asymmetric petals.

More questions in IT

Q1

How do we find such AA and BB?

From XX and YY, draw arcs above and below XYXY, with the same radii. The two points at which the arcs meet, above and below XYXY, give us AA and BB, respectively.

Use this to construct an eye.

Q2

In Fig. 6.1, join AA and BB with a line. Where does ABAB intersect XYXY, and what is the angle formed between them?

Q3

Will the line joining the two points at which the arcs meet, above and below XYXY, always be the perpendicular bisector of XYXY, i.e., when XYXY is of any length, and the arcs are drawn using a radius of any length?

Q4

Which two triangles should be congruent for ABAB to be the perpendicular bisector of XYXY (that is, OO is the midpoint of XYXY and ABAB is perpendicular to XYXY)?

Q5

How do we get these different shapes? Try!

Q6

Will CC and DD lie on the perpendicular bisector AB\text{AB}?

Q7

Justify the following statement using the facts that we have established.

Any point that has the same distance from XX and YY lies on the perpendicular bisector of XY\text{XY}.

Q8

Given a line segment XYXY, how do we draw its perpendicular bisector using only an unmarked ruler and a compass?

Q9

Can we extend the method of constructing the perpendicular bisector to construct a 9090^\circ angle at any point on a line? Draw a line and mark a point OO on it. Construct a 9090^\circ angle at point OO.

Q10

Find a segment of this line for which OO is the midpoint.

Q11

How do we construct this figure?

Q12

What is the angle between two adjacent lines?

Q13

How do we construct a 4545^\circ angle using only a ruler and a compass?

Q14

Construct the following figure.

Q15

Draw an angle. Create a copy of this angle using only a ruler and compass.

Q16

How do we implement this idea using a ruler and a compass?

Q17

How did they make these arches?

Q18

Construct this arch shape on a piece of paper.

Let us think about the support lines this figure will need.

For symmetry, we should have AB=CDAB = CD, and BAD=CDA\angle BAD = \angle CDA. How would you construct these support lines?

Q19

Use these support lines to construct an arch. If required, adjust the radii of the arcs to make the arch look more aesthetically pleasing.

Q20

How do we construct this shape?

What supporting lines will you use to draw this arch?

Remember 'Wavy Wave' from the Grade 6 Textbook?

The supporting lines are just two line segments of equal length.

Q21

If their midpoints are marked, will you be able to construct a pointed arch?

Q22

How do we construct a regular pentagon (5-sided figure) and a regular hexagon (6-sided figure)? To begin with, try to construct a pentagon and hexagon with equal sidelengths.

Q23

Can we break a regular hexagon into smaller pieces that can be constructed?

Q24

Can six congruent equilateral triangles be placed together as in Fig. 6.12? If yes, will it result in a regular hexagon?

Q25

Consider this figure. Will the 7070^\circ angle fit into the gap? What is the gap angle AOI\angle AOI?

We have, 40+60+50+30+40+90+gap angle=36040^\circ + 60^\circ + 50^\circ + 30^\circ + 40^\circ + 90^\circ + \text{gap angle} = 360^\circ

Use this to determine whether the 7070^\circ angle fits the gap.

Q26

In Fig. 6.12 can you explain why AODAOD, BOEBOE and COFCOF are straight lines?

Q27

Construct a regular hexagon with a sidelength 4 cm4\text{ cm} using a ruler and a compass.

Q28

Context: We can construct a regular hexagon more directly if we can construct a 120120^\circ angle using a ruler and a compass.

Q. How do we do it?

Q29

Why is CAX=60\angle \text{CAX} = 60^\circ? Is there an equilateral triangle here?

Q30

Construct a regular hexagon of sidelength 5 cm5\text{ cm}.

Q31

How will you construct 3030^\circ and 1515^\circ angles?

Q32

Construct the following 6-pointed star. Note that it has a rotational symmetry.

Q33

Are the six triangles forming the 6 points of the star — ΔAGH\Delta \text{AGH}, ΔBHI\Delta \text{BHI}, ΔCIJ\Delta \text{CIJ}, ΔDJK\Delta \text{DJK}, ΔELK\Delta \text{ELK}, ΔFLG\Delta \text{FLG} — equilateral? Why?

[Hint: Find the angles.]

Q34

Can a 4×64 \times 6 grid be tiled using multiple copies of 2×12 \times 1 tiles? We are allowed to rotate a 2×12 \times 1 tile and use it.

Q35

Can a 4×74 \times 7 grid be tiled using 2×12 \times 1 tiles?

Q36

What about a 5×75 \times 7 grid?

Complete the justification.

Q38

Is an m×nm \times n grid tileable with 2×12 \times 1 tiles, if both mm and nn are even? If yes, come up with a general strategy to tile it.

Q39

Is an m×nm \times n grid tileable with 2×12 \times 1 tiles, if one of mm and nn is even and the other is odd? If yes, come up with a general strategy to tile it.

Q40

Is an m×nm \times n grid tileable with 2×12 \times 1 tiles, if both mm and nn are odd? Give reasons.

Q41

Here is a 5×35 \times 3 grid, with a unit square removed. Now, it has an even number of unit squares. Is it tileable with 2×12 \times 1 tiles?

Q42

Is the following region tileable with 2×12 \times 1 tiles?

Q43

Context: We are considering whether a given region can be tiled using 2×12 \times 1 tiles.

Q. What about this one?

Q44

Were you able to tile this? How can we be sure that this is not tileable? Can you find another unit square that, when removed from a 5×35 \times 3 grid, makes it non-tileable?

Q45

If the plain grid is tileable, is the black-and-white-grid tileable?

Q46

If the black-and-white grid is tileable, is the plain grid tileable?

Q47

Use this idea to find another unit square that, when removed from a 5×35 \times 3 grid, makes it non-tileable?

← Back to Constructions and Tilings