Arithmetic Expressions | FIO

Question 15

Read the situations given below. Write appropriate expressions for each of them and find their values.

(a) The district market in Begur operates on all seven days of a week. Rahim supplies 9 kg of mangoes each day from his orchard and Shyam supplies 11 kg of mangoes each day from his orchard to this market. Find the amount of mangoes supplied by them in a week to the local district market.

(b) Binu earns ₹20,000 per month. She spends ₹5,000 on rent, ₹5,000 on food, and ₹2,000 on other expenses every month. What is the amount Binu will save by the end of a year?

(c) During the daytime a snail climbs 3 cm up a post, and during the night while asleep, accidentally slips down by 2 cm. The post is 10 cm high, and a delicious treat is on its top. In how many days will the snail get the treat?

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Solution
Understand the Question

We need to form mathematical expressions for three real-world situations and evaluate them:

  • Part (a): Calculate the total weekly mango supply by multiplying the daily supplies by the 77 days in a week.
  • Part (b): Find the monthly savings by subtracting total monthly expenses from monthly income, then multiply by 1212 months to find the yearly savings.
  • Part (c): Track the net daily progress of the snail (1 cm/day1\text{ cm/day}), noting that on the final day, the snail reaches the 10 cm10\text{ cm} top during daytime (+3 cm+3\text{ cm}) and does not slip back down.

(a) The district market in Begur operates on all seven days of a week. Rahim supplies 9 kg of mangoes each day from his orchard and Shyam supplies 11 kg of mangoes each day from his orchard to this market. Find the amount of mangoes supplied by them in a week to the local district market.

Step 1 · Calculate Weekly Mango Supply

Calculate the weekly supply for each person (77 days in a week)

Rahim’s weekly supply=9×7=63 kgShyam’s weekly supply=11×7=77 kg\begin{aligned} \text{Rahim's weekly supply} &= 9 \times 7 = 63\text{ kg} \\ \text{Shyam's weekly supply} &= 11 \times 7 = 77\text{ kg} \end{aligned}

Calculate the total supply

Total weekly supply=63+77=140 kg\begin{aligned} \text{Total weekly supply} &= 63 + 77 \\ &= 140\text{ kg} \end{aligned}

Alternatively, as a single expression

(9+11)×7=20×7=140 kg(9 + 11) \times 7 = 20 \times 7 = 140\text{ kg}
Answer

(a) 140 kg140\text{ kg}

(b) Binu earns ₹20,000 per month. She spends ₹5,000 on rent, ₹5,000 on food, and ₹2,000 on other expenses every month. What is the amount Binu will save by the end of a year?

Step 1 · Calculate Monthly Expenses and Savings

Calculate total monthly expenses

Total monthly expenses=5000+5000+2000=12,000\begin{aligned} \text{Total monthly expenses} &= 5000 + 5000 + 2000 \\ &= \text{₹}12{,}000 \end{aligned}

Calculate monthly savings

Monthly savings=2000012000=8,000\begin{aligned} \text{Monthly savings} &= 20000 - 12000 \\ &= \text{₹}8{,}000 \end{aligned}

Step 2 · Calculate Total Savings in a Year

There are 1212 months in a year

Yearly savings=8000×12=96,000\begin{aligned} \text{Yearly savings} &= 8000 \times 12 \\ &= \text{₹}96{,}000 \end{aligned}

Alternatively, as a single expression

[20000(5000+5000+2000)]×12=8000×12=96,000[20000 - (5000 + 5000 + 2000)] \times 12 = 8000 \times 12 = \text{₹}96{,}000
Answer

(b) 96,000\text{₹}96{,}000

(c) During the daytime a snail climbs 3 cm up a post, and during the night while asleep, accidentally slips down by 2 cm. The post is 10 cm high, and a delicious treat is on its top. In how many days will the snail get the treat?

Step 1 · Calculate Net Daily Climb

Diagram 1

Climb during day=3 cmSlip during night=2 cmNet climb per day=32=1 cm\begin{aligned} \text{Climb during day} &= 3\text{ cm} \\ \text{Slip during night} &= 2\text{ cm} \\ \text{Net climb per day} &= 3 - 2 = 1\text{ cm} \end{aligned}

Step 2 · Determine Days Needed to Reach the Top

On the final day, the snail climbs 3 cm3\text{ cm} and reaches the top without slipping down.

Height to cover before the final day

103=7 cm10 - 3 = 7\text{ cm}

Days required to reach 7 cm7\text{ cm}

71=7 days\dfrac{7}{1} = 7\text{ days}

On the 8th8^{\text{th}} day, the snail climbs 3 cm3\text{ cm} from 7 cm7\text{ cm} to reach 10 cm10\text{ cm}

Total days=7+1=8 days\text{Total days} = 7 + 1 = 8\text{ days}
Answer

(c) 8 days8\text{ days}

Common Mistakes
  • Snail Problem Fallacy: Calculating 1032=10 days\dfrac{10}{3 - 2} = 10\text{ days} by assuming the snail slips down every day. Once the snail reaches the top on the 8th8^{\text{th}} day, it secures the treat immediately and does not slip down.
  • Unit/Time Factor: Forgetting to multiply monthly savings by 1212 for yearly savings in part (b), or forgetting to multiply daily amounts by 77 in part (a).

More questions in FIO

Q1

Fill in the blanks to make the expressions equal on both sides of the == sign:

(a) 13+4=+613 + 4 = \underline{\quad} + 6

(b) 22+=6×522 + \underline{\quad} = 6 \times 5

(c) 8×=64÷28 \times \underline{\quad} = 64 \div 2

(d) 34=2534 - \underline{\quad} = 25

Q2

Arrange the following expressions in ascending (increasing) order of their values.

(a) 671967 - 19

(b) 672067 - 20

(c) 35+2535 + 25

(d) 5×115 \times 11

(e) 120÷3120 \div 3

Q3

Find the values of the following expressions by writing the terms in each case.

(a) 287+828 - 7 + 8

(b) 392×6+1139 - 2 \times 6 + 11

(c) 4010+10+1040 - 10 + 10 + 10

(d) 4810×2+16÷248 - 10 \times 2 + 16 \div 2

(e) 6×34×8×56 \times 3 - 4 \times 8 \times 5

Q4

Write a story/situation for each of the following expressions and find their values.

(a) 89+211089 + 21 - 10

(b) 5×1265 \times 12 - 6

(c) 4×9+2×64 \times 9 + 2 \times 6

Q5

For each of the following situations, write the expression describing the situation, identify its terms and find the value of the expression.

(a) Queen Alia gave 100 gold coins to Princess Elsa and 100 gold coins to Princess Anna last year. Princess Elsa used the coins to start a business and doubled her coins. Princess Anna bought jewellery and has only half of the coins left. Write an expression describing how many gold coins Princess Elsa and Princess Anna together have.

(b) A metro train ticket between two stations is ₹40 for an adult and ₹20 for a child. What is the total cost of tickets:

(i) for four adults and three children?

(ii) for two groups having three adults each?

(c) Find the total height of the window by writing an expression describing the relationship among the measurements shown in the picture.

Q6

Add brackets at appropriate places in the expressions such that they lead to the values indicated.

(a) 349+12=1334 - 9 + 12 = 13

(b) 56148=3456 - 14 - 8 = 34

(c) 2212+10+22=22-22 - 12 + 10 + 22 = -22

Q7

Using only reasoning of how terms change their values, fill the blanks to make the expressions on either side of the equality (==) equal.

(a) 423+=419+423 + \underline{\quad\quad} = 419 + \underline{\quad\quad}

(b) 20768=210207 - 68 = 210 - \underline{\quad\quad}

Q8

Using the numbers 2, 3 and 5, and the operators '+' and '-', and brackets, as necessary, generate expressions to give as many different values as possible. For example, 23+5=42 - 3 + 5 = 4 and 3(52)=03 - (5 - 2) = 0.

Q9

Whenever Jasoda has to subtract 9 from a number, she subtracts 10 and adds 1 to it. For example, 369=26+136 - 9 = 26 + 1.

(a) Do you think she always gets the correct answer? Why?

(b) Can you think of other similar strategies? Give some examples.

Q10

Consider the two expressions: a) 7314+173 - 14 + 1, b) 7314173 - 14 - 1. For each of these expressions, identify the expressions from the following collection that are equal to it.

(a) 73(14+1)73 - (14 + 1)

(b) 73(141)73 - (14 - 1)

(c) 73+(14+1)73 + (-14 + 1)

(d) 73+(141)73 + (-14 - 1)

Q11

Figure it Out

  1. Fill in the blanks with numbers, and boxes by signs, so that the expressions on both sides are equal.

(a) 3×(6+7)=3×6+3×73 \times (6 + 7) = 3 \times 6 + 3 \times 7

(b) (8+3)×4=8×4+3×4(8 + 3) \times 4 = 8 \times 4 + 3 \times 4

(c) 3×(5+8)=3×5  3×   3 \times (5 + 8) = 3 \times 5 \ \Box\ 3 \times \underline{\ \ \ }

(d) (9+2)×4=9×4  2×   (9 + 2) \times 4 = 9 \times 4 \ \Box\ 2 \times \underline{\ \ \ }

(e) 3×(   +4)=3    +   3 \times (\underline{\ \ \ } + 4) = 3 \ \underline{\ \ \ } + \underline{\ \ \ }

(f) (   +6)×4=13×4+   (\underline{\ \ \ } + 6) \times 4 = 13 \times 4 + \underline{\ \ \ }

(g) 3×(   +   )=3×5+3×23 \times (\underline{\ \ \ } + \underline{\ \ \ }) = 3 \times 5 + 3 \times 2

(h) (   +   )×   =2×4+3×4(\underline{\ \ \ } + \underline{\ \ \ }) \times \underline{\ \ \ } = 2 \times 4 + 3 \times 4

(i) 5×(92)=5×95×   5 \times (9 - 2) = 5 \times 9 - 5 \times \underline{\ \ \ }

(j) (52)×7=5×72×   (5 - 2) \times 7 = 5 \times 7 - 2 \times \underline{\ \ \ }

(k) 5×(83)=5×8  5×   5 \times (8 - 3) = 5 \times 8 \ \Box\ 5 \times \underline{\ \ \ }

(l) (83)×7=8×7  3×7(8 - 3) \times 7 = 8 \times 7 \ \Box\ 3 \times 7

(m) 5×(12   )=     5×   5 \times (12 - \underline{\ \ \ }) = \underline{\ \ \ } \ \Box\ 5 \times \underline{\ \ \ }

(n) (15   )×7=     6×7(15 - \underline{\ \ \ }) \times 7 = \underline{\ \ \ } \ \Box\ 6 \times 7

(o) 5×(      )=5×95×45 \times (\underline{\ \ \ } - \underline{\ \ \ }) = 5 \times 9 - 5 \times 4

(p) (      )×   =17×79×7(\underline{\ \ \ } - \underline{\ \ \ }) \times \underline{\ \ \ } = 17 \times 7 - 9 \times 7

Q12

In the boxes below, fill '<', '>' or '=' after analysing the expressions on the LHS and RHS. Use reasoning and understanding of terms and brackets to figure this out and not by evaluating the expressions.

(a) (83)×29  (38)×29(8 - 3) \times 29 \ \square\ (3 - 8) \times 29

(b) 15+9×18  (15+9)×1815 + 9 \times 18 \ \square\ (15 + 9) \times 18

(c) 23×(179)  23×17+23×923 \times (17 - 9) \ \square\ 23 \times 17 + 23 \times 9

(d) (3428)×42  34×4228×42(34 - 28) \times 42 \ \square\ 34 \times 42 - 28 \times 42

Q13

Here is one way to make 14: 2×(1+6)=142 \times (1 + 6) = 14. Are there other ways of getting 14? Fill them out below:

(a) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(b) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(c) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(d) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

Q14

Find out the sum of the numbers given in each picture below in at least two different ways. Describe how you solved it through expressions.

Q15

Read the situations given below. Write appropriate expressions for each of them and find their values.

(a) The district market in Begur operates on all seven days of a week. Rahim supplies 9 kg of mangoes each day from his orchard and Shyam supplies 11 kg of mangoes each day from his orchard to this market. Find the amount of mangoes supplied by them in a week to the local district market.

(b) Binu earns ₹20,000 per month. She spends ₹5,000 on rent, ₹5,000 on food, and ₹2,000 on other expenses every month. What is the amount Binu will save by the end of a year?

(c) During the daytime a snail climbs 3 cm up a post, and during the night while asleep, accidentally slips down by 2 cm. The post is 10 cm high, and a delicious treat is on its top. In how many days will the snail get the treat?

Q16

Melvin reads a two-page story every day except on Tuesdays and Saturdays. How many stories would he complete reading in 8 weeks? Which of the expressions below describes this scenario?

(a) 5×2×85 \times 2 \times 8

(b) (72)×8(7 - 2) \times 8

(c) 8×78 \times 7

(d) 7×2×87 \times 2 \times 8

(e) 7×527 \times 5 - 2

(f) (7+2)×8(7 + 2) \times 8

(g) 7×82×87 \times 8 - 2 \times 8

(h) (75)×8(7 - 5) \times 8

Q17

Find different ways of evaluating the following expressions:

(a) 12+34+56+78+9101 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + 9 - 10

(b) 11+11+11+11+111 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1

Q18

Compare the following pairs of expressions using '<<', '>>' or '==' or by reasoning.

(a) 497+8497+849 - 7 + 8 \quad \square \quad 49 - 7 + 8

(b) 83×421883×401883 \times 42 - 18 \quad \square \quad 83 \times 40 - 18

(c) 14517×814517×6145 - 17 \times 8 \quad \square \quad 145 - 17 \times 6

(d) 23×483523×(4835)23 \times 48 - 35 \quad \square \quad 23 \times (48 - 35)

(e) (1611)×1211×12+16×12(16 - 11) \times 12 \quad \square \quad -11 \times 12 + 16 \times 12

(f) (7653)×8888×(5376)(76 - 53) \times 88 \quad \square \quad 88 \times (53 - 76)

(g) 25×(42+16)25×(43+15)25 \times (42 + 16) \quad \square \quad 25 \times (43 + 15)

(h) 36×(2816)35×(2715)36 \times (28 - 16) \quad \square \quad 35 \times (27 - 15)

Q19

Identify which of the following expressions are equal to the given expression without computation. You may rewrite the expressions using terms or removing brackets. There can be more than one expression which is equal to the given expression.

(a) 83371283 - 37 - 12

(i) 84381284 - 38 - 12

(ii) 84(37+12)84 - (37 + 12)

(iii) 83381383 - 38 - 13

(iv) 37+8312-37 + 83 - 12

(b) 93+37×44+7693 + 37 \times 44 + 76

(i) 37+93×44+7637 + 93 \times 44 + 76

(ii) 93+37×76+4493 + 37 \times 76 + 44

(iii) (93+37)×(44+76)(93 + 37) \times (44 + 76)

(iv) 37×44+93+7637 \times 44 + 93 + 76

Q20

Choose a number and create ten different expressions having that value.

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