Arithmetic Expressions | FIO

Question 5

For each of the following situations, write the expression describing the situation, identify its terms and find the value of the expression.

(a) Queen Alia gave 100 gold coins to Princess Elsa and 100 gold coins to Princess Anna last year. Princess Elsa used the coins to start a business and doubled her coins. Princess Anna bought jewellery and has only half of the coins left. Write an expression describing how many gold coins Princess Elsa and Princess Anna together have.

(b) A metro train ticket between two stations is ₹40 for an adult and ₹20 for a child. What is the total cost of tickets:

(i) for four adults and three children?

(ii) for two groups having three adults each?

(c) Find the total height of the window by writing an expression describing the relationship among the measurements shown in the picture.

Question diagram 1
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Solution
Understand the Question
  • An expression translates a real-world situation into mathematical operations and numbers.
  • Terms are the parts of an expression separated by addition (++) or subtraction (-) signs (multiplication or grouped quantities within parentheses form a single term).
  • For each scenario, we form the arithmetic expression representing the total, identify each term, and then evaluate the expression using the order of operations (BODMAS).

(a) Queen Alia gave 100 gold coins to Princess Elsa and 100 gold coins to Princess Anna last year. Princess Elsa used the coins to start a business and doubled her coins. Princess Anna bought jewellery and has only half of the coins left. Write an expression describing how many gold coins Princess Elsa and Princess Anna together have.

Step 1 · Write the Expression and Find the Total Coins

Coins with Elsa: 2×100=2002 \times 100 = 200

Coins with Anna: 1002=50\dfrac{100}{2} = 50

Total expression for coins together: Expression: 2×100+1002\text{Expression: } 2 \times 100 + \dfrac{100}{2}

Terms: 2×100 and 1002\text{Terms: } 2 \times 100 \text{ and } \dfrac{100}{2}

Calculating the value:

2×100+1002=200+50=250\begin{aligned} 2 \times 100 + \dfrac{100}{2} &= 200 + 50 \\[0.6em] &= 250 \end{aligned}
Answer

(a) Expression: 2×100+10022 \times 100 + \dfrac{100}{2}, Terms: 2×100,10022 \times 100, \dfrac{100}{2}, Value: 250

(b) (i) A metro train ticket between two stations is ₹40 for an adult and ₹20 for a child. What is the total cost of tickets for four adults and three children?

Step 1 · Write the Expression and Calculate Cost

Cost for four adults: 4×40=1604 \times 40 = 160

Cost for three children: 3×20=603 \times 20 = 60

Total cost expression: Expression: 4×40+3×20\text{Expression: } 4 \times 40 + 3 \times 20

Terms: 4×40 and 3×20\text{Terms: } 4 \times 40 \text{ and } 3 \times 20

Calculating the total value:

4×40+3×20=160+60=220\begin{aligned} 4 \times 40 + 3 \times 20 &= 160 + 60 \\[0.6em] &= 220 \end{aligned}
Answer

(b) (i) Expression: 4×40+3×204 \times 40 + 3 \times 20, Terms: 4×40,3×204 \times 40, 3 \times 20, Value: ₹220

(b) (ii) What is the total cost of tickets for two groups having three adults each?

Step 1 · Write the Expression and Calculate Cost

Cost for one group of three adults: 3×40=1203 \times 40 = 120

For two such groups: Expression: 2×(3×40)\text{Expression: } 2 \times (3 \times 40)

Term: 2×(3×40)\text{Term: } 2 \times (3 \times 40)

Calculating the total value:

2×(3×40)=2×120=240\begin{aligned} 2 \times (3 \times 40) &= 2 \times 120 \\[0.6em] &= 240 \end{aligned}
Answer

(b) (ii) Expression: 2×(3×40)2 \times (3 \times 40), Terms: 2×(3×40)2 \times (3 \times 40), Value: ₹240

(c) Find the total height of the window by writing an expression describing the relationship among the measurements shown in the picture.

Step 1 · Formulate Expression and Calculate Window Height

Diagram 1

From the measurements shown in the figure:

  • 22 borders of 3 cm3\text{ cm} each
  • 66 grill bars of 2 cm2\text{ cm} each
  • 77 gaps of 5 cm5\text{ cm} each

Total height expression: Expression: 2×3+6×2+7×5\text{Expression: } 2 \times 3 + 6 \times 2 + 7 \times 5

Terms: 2×3,  6×2,  7×5\text{Terms: } 2 \times 3,\; 6 \times 2,\; 7 \times 5

Calculating the total value:

2×3+6×2+7×5=6+12+35=18+35=53\begin{aligned} 2 \times 3 + 6 \times 2 + 7 \times 5 &= 6 + 12 + 35 \\[0.6em] &= 18 + 35 \\[0.6em] &= 53 \end{aligned}
Answer

(c) Expression: 2×3+6×2+7×52 \times 3 + 6 \times 2 + 7 \times 5, Terms: 2×3,6×2,7×52 \times 3, 6 \times 2, 7 \times 5, Value: 53 cm

Common Mistakes
  • Confusing Terms with Factors: Factors are multiplied together to form a single term (e.g., in 4×40+3×204 \times 40 + 3 \times 20, the terms are 4×404 \times 40 and 3×203 \times 20, not the individual numbers 4,40,3,204, 40, 3, 20).
  • Miscounting Diagram Segments: Missing the top/bottom borders (2×32 \times 3) or mixing up the number of bars (66) and gaps (77).
  • Order of Operations: Adding before completing multiplications in expressions like 2×3+6×2+7×52 \times 3 + 6 \times 2 + 7 \times 5.

More questions in FIO

Q1

Fill in the blanks to make the expressions equal on both sides of the == sign:

(a) 13+4=+613 + 4 = \underline{\quad} + 6

(b) 22+=6×522 + \underline{\quad} = 6 \times 5

(c) 8×=64÷28 \times \underline{\quad} = 64 \div 2

(d) 34=2534 - \underline{\quad} = 25

Q2

Arrange the following expressions in ascending (increasing) order of their values.

(a) 671967 - 19

(b) 672067 - 20

(c) 35+2535 + 25

(d) 5×115 \times 11

(e) 120÷3120 \div 3

Q3

Find the values of the following expressions by writing the terms in each case.

(a) 287+828 - 7 + 8

(b) 392×6+1139 - 2 \times 6 + 11

(c) 4010+10+1040 - 10 + 10 + 10

(d) 4810×2+16÷248 - 10 \times 2 + 16 \div 2

(e) 6×34×8×56 \times 3 - 4 \times 8 \times 5

Q4

Write a story/situation for each of the following expressions and find their values.

(a) 89+211089 + 21 - 10

(b) 5×1265 \times 12 - 6

(c) 4×9+2×64 \times 9 + 2 \times 6

Q5

For each of the following situations, write the expression describing the situation, identify its terms and find the value of the expression.

(a) Queen Alia gave 100 gold coins to Princess Elsa and 100 gold coins to Princess Anna last year. Princess Elsa used the coins to start a business and doubled her coins. Princess Anna bought jewellery and has only half of the coins left. Write an expression describing how many gold coins Princess Elsa and Princess Anna together have.

(b) A metro train ticket between two stations is ₹40 for an adult and ₹20 for a child. What is the total cost of tickets:

(i) for four adults and three children?

(ii) for two groups having three adults each?

(c) Find the total height of the window by writing an expression describing the relationship among the measurements shown in the picture.

Q6

Add brackets at appropriate places in the expressions such that they lead to the values indicated.

(a) 349+12=1334 - 9 + 12 = 13

(b) 56148=3456 - 14 - 8 = 34

(c) 2212+10+22=22-22 - 12 + 10 + 22 = -22

Q7

Using only reasoning of how terms change their values, fill the blanks to make the expressions on either side of the equality (==) equal.

(a) 423+=419+423 + \underline{\quad\quad} = 419 + \underline{\quad\quad}

(b) 20768=210207 - 68 = 210 - \underline{\quad\quad}

Q8

Using the numbers 2, 3 and 5, and the operators '+' and '-', and brackets, as necessary, generate expressions to give as many different values as possible. For example, 23+5=42 - 3 + 5 = 4 and 3(52)=03 - (5 - 2) = 0.

Q9

Whenever Jasoda has to subtract 9 from a number, she subtracts 10 and adds 1 to it. For example, 369=26+136 - 9 = 26 + 1.

(a) Do you think she always gets the correct answer? Why?

(b) Can you think of other similar strategies? Give some examples.

Q10

Consider the two expressions: a) 7314+173 - 14 + 1, b) 7314173 - 14 - 1. For each of these expressions, identify the expressions from the following collection that are equal to it.

(a) 73(14+1)73 - (14 + 1)

(b) 73(141)73 - (14 - 1)

(c) 73+(14+1)73 + (-14 + 1)

(d) 73+(141)73 + (-14 - 1)

Q11

Figure it Out

  1. Fill in the blanks with numbers, and boxes by signs, so that the expressions on both sides are equal.

(a) 3×(6+7)=3×6+3×73 \times (6 + 7) = 3 \times 6 + 3 \times 7

(b) (8+3)×4=8×4+3×4(8 + 3) \times 4 = 8 \times 4 + 3 \times 4

(c) 3×(5+8)=3×5  3×   3 \times (5 + 8) = 3 \times 5 \ \Box\ 3 \times \underline{\ \ \ }

(d) (9+2)×4=9×4  2×   (9 + 2) \times 4 = 9 \times 4 \ \Box\ 2 \times \underline{\ \ \ }

(e) 3×(   +4)=3    +   3 \times (\underline{\ \ \ } + 4) = 3 \ \underline{\ \ \ } + \underline{\ \ \ }

(f) (   +6)×4=13×4+   (\underline{\ \ \ } + 6) \times 4 = 13 \times 4 + \underline{\ \ \ }

(g) 3×(   +   )=3×5+3×23 \times (\underline{\ \ \ } + \underline{\ \ \ }) = 3 \times 5 + 3 \times 2

(h) (   +   )×   =2×4+3×4(\underline{\ \ \ } + \underline{\ \ \ }) \times \underline{\ \ \ } = 2 \times 4 + 3 \times 4

(i) 5×(92)=5×95×   5 \times (9 - 2) = 5 \times 9 - 5 \times \underline{\ \ \ }

(j) (52)×7=5×72×   (5 - 2) \times 7 = 5 \times 7 - 2 \times \underline{\ \ \ }

(k) 5×(83)=5×8  5×   5 \times (8 - 3) = 5 \times 8 \ \Box\ 5 \times \underline{\ \ \ }

(l) (83)×7=8×7  3×7(8 - 3) \times 7 = 8 \times 7 \ \Box\ 3 \times 7

(m) 5×(12   )=     5×   5 \times (12 - \underline{\ \ \ }) = \underline{\ \ \ } \ \Box\ 5 \times \underline{\ \ \ }

(n) (15   )×7=     6×7(15 - \underline{\ \ \ }) \times 7 = \underline{\ \ \ } \ \Box\ 6 \times 7

(o) 5×(      )=5×95×45 \times (\underline{\ \ \ } - \underline{\ \ \ }) = 5 \times 9 - 5 \times 4

(p) (      )×   =17×79×7(\underline{\ \ \ } - \underline{\ \ \ }) \times \underline{\ \ \ } = 17 \times 7 - 9 \times 7

Q12

In the boxes below, fill '<', '>' or '=' after analysing the expressions on the LHS and RHS. Use reasoning and understanding of terms and brackets to figure this out and not by evaluating the expressions.

(a) (83)×29  (38)×29(8 - 3) \times 29 \ \square\ (3 - 8) \times 29

(b) 15+9×18  (15+9)×1815 + 9 \times 18 \ \square\ (15 + 9) \times 18

(c) 23×(179)  23×17+23×923 \times (17 - 9) \ \square\ 23 \times 17 + 23 \times 9

(d) (3428)×42  34×4228×42(34 - 28) \times 42 \ \square\ 34 \times 42 - 28 \times 42

Q13

Here is one way to make 14: 2×(1+6)=142 \times (1 + 6) = 14. Are there other ways of getting 14? Fill them out below:

(a) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(b) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(c) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

(d) ×(+)=14\underline{\quad} \times (\underline{\quad} + \underline{\quad}) = 14

Q14

Find out the sum of the numbers given in each picture below in at least two different ways. Describe how you solved it through expressions.

Q15

Read the situations given below. Write appropriate expressions for each of them and find their values.

(a) The district market in Begur operates on all seven days of a week. Rahim supplies 9 kg of mangoes each day from his orchard and Shyam supplies 11 kg of mangoes each day from his orchard to this market. Find the amount of mangoes supplied by them in a week to the local district market.

(b) Binu earns ₹20,000 per month. She spends ₹5,000 on rent, ₹5,000 on food, and ₹2,000 on other expenses every month. What is the amount Binu will save by the end of a year?

(c) During the daytime a snail climbs 3 cm up a post, and during the night while asleep, accidentally slips down by 2 cm. The post is 10 cm high, and a delicious treat is on its top. In how many days will the snail get the treat?

Q16

Melvin reads a two-page story every day except on Tuesdays and Saturdays. How many stories would he complete reading in 8 weeks? Which of the expressions below describes this scenario?

(a) 5×2×85 \times 2 \times 8

(b) (72)×8(7 - 2) \times 8

(c) 8×78 \times 7

(d) 7×2×87 \times 2 \times 8

(e) 7×527 \times 5 - 2

(f) (7+2)×8(7 + 2) \times 8

(g) 7×82×87 \times 8 - 2 \times 8

(h) (75)×8(7 - 5) \times 8

Q17

Find different ways of evaluating the following expressions:

(a) 12+34+56+78+9101 - 2 + 3 - 4 + 5 - 6 + 7 - 8 + 9 - 10

(b) 11+11+11+11+111 - 1 + 1 - 1 + 1 - 1 + 1 - 1 + 1 - 1

Q18

Compare the following pairs of expressions using '<<', '>>' or '==' or by reasoning.

(a) 497+8497+849 - 7 + 8 \quad \square \quad 49 - 7 + 8

(b) 83×421883×401883 \times 42 - 18 \quad \square \quad 83 \times 40 - 18

(c) 14517×814517×6145 - 17 \times 8 \quad \square \quad 145 - 17 \times 6

(d) 23×483523×(4835)23 \times 48 - 35 \quad \square \quad 23 \times (48 - 35)

(e) (1611)×1211×12+16×12(16 - 11) \times 12 \quad \square \quad -11 \times 12 + 16 \times 12

(f) (7653)×8888×(5376)(76 - 53) \times 88 \quad \square \quad 88 \times (53 - 76)

(g) 25×(42+16)25×(43+15)25 \times (42 + 16) \quad \square \quad 25 \times (43 + 15)

(h) 36×(2816)35×(2715)36 \times (28 - 16) \quad \square \quad 35 \times (27 - 15)

Q19

Identify which of the following expressions are equal to the given expression without computation. You may rewrite the expressions using terms or removing brackets. There can be more than one expression which is equal to the given expression.

(a) 83371283 - 37 - 12

(i) 84381284 - 38 - 12

(ii) 84(37+12)84 - (37 + 12)

(iii) 83381383 - 38 - 13

(iv) 37+8312-37 + 83 - 12

(b) 93+37×44+7693 + 37 \times 44 + 76

(i) 37+93×44+7637 + 93 \times 44 + 76

(ii) 93+37×76+4493 + 37 \times 76 + 44

(iii) (93+37)×(44+76)(93 + 37) \times (44 + 76)

(iv) 37×44+93+7637 \times 44 + 93 + 76

Q20

Choose a number and create ten different expressions having that value.

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