Perimeter and Area | IT

Question 9

Now, see the figures below. Is the area of the blue rectangle more or less than the area of the yellow triangle? Or is it the same? Why?

  • Can you see some relationship between the blue rectangle and the yellow triangle and their areas? Write the relationship here.
Question diagram 1
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Solution
Understand the Question
  • To compare the areas of the blue rectangle (square) and the yellow triangle, find their areas in terms of side length ss.
  • Area of Square/Rectangle: Side×Side=s×s=s2\text{Side} \times \text{Side} = s \times s = s^2
  • Area of Triangle: 12×base×height=12×2s×s=s2\dfrac{1}{2} \times \text{base} \times \text{height} = \dfrac{1}{2} \times 2s \times s = s^2
  • Since both formulas give s2s^2, their areas are equal.

(i) Is the area of the blue rectangle more or less than the area of the yellow triangle? Or is it the same? Why?

Step 1 · Calculate Area of the Blue Rectangle

Let the side of the blue square/rectangle be ss units.Diagram 1

Area of blue rectangle=s×s=s2 square units\begin{aligned} \text{Area of blue rectangle} &= s \times s \\ &= s^2 \text{ square units} \end{aligned}

Step 2 · Calculate Area of the Yellow Triangle

The height of the yellow triangle is ss units and its base is 2s2s units.Diagram 2

Area of yellow triangle=12×base×height=12×(2s)×s=s2 square units\begin{aligned} \text{Area of yellow triangle} &= \dfrac{1}{2} \times \text{base} \times \text{height} \\[0.6em] &= \dfrac{1}{2} \times (2s) \times s \\[0.6em] &= s^2 \text{ square units} \end{aligned}
Answer

(i) The area of the blue rectangle and the yellow triangle are the same (s2 square unitss^2\text{ square units}).

(ii) Can you see some relationship between the blue rectangle and the yellow triangle and their areas? Write the relationship here.

Step 1 · Find the Relationship Between the Areas

Both shapes have the exact same area: Area of blue rectangle=Area of yellow triangle=s2\text{Area of blue rectangle} = \text{Area of yellow triangle} = s^2

Additionally, a diagonal divides the blue rectangle into two identical triangles of area s22\dfrac{s^2}{2} each. Therefore: Area of rectangle=2×Area of one internal triangle\text{Area of rectangle} = 2 \times \text{Area of one internal triangle}

Answer

(ii) Area of Blue Rectangle=Area of Yellow Triangle=2×Area of each half-triangle\text{Area of Blue Rectangle} = \text{Area of Yellow Triangle} = 2 \times \text{Area of each half-triangle}

Common Mistakes
  • Forgetting the Half Factor: Omitting 12\dfrac{1}{2} in the triangle area formula 12×base×height\dfrac{1}{2} \times \text{base} \times \text{height}, leading to an incorrect double area.
  • Misidentifying Dimensions: Overlooking that the base of the yellow triangle spans 2s2s while its height is only ss.

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Q9

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  • Can you see some relationship between the blue rectangle and the yellow triangle and their areas? Write the relationship here.
Q10

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Q11

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