Perimeter and Area | IT

Question 16

Below is the house plan of Charan. It is in a rectangular plot. Look at the plan. What do you notice?

Some of the measurements are given.

a. Find the missing measurements.

b. Find out the area of his house.

Question diagram 1
Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution

We will find the dimensions and areas of each part of the house using the given measurements.

Step 1 — Find total plot dimensions

The total height of the plot is given. It is 30 ft. We find the total width by adding the widths of the rooms at the top. The Master Bedroom is 15 ft wide. The Toilet is 5 ft wide. The Kitchen is 15 ft wide. The total width of the plot is the sum of these widths. 15 ft+5 ft+15 ft15 \text{ ft} + 5 \text{ ft} + 15 \text{ ft} =35 ft= 35 \text{ ft}

Total plot dimensions: 35 ft×30 ft\boxed{\text{Total plot dimensions: } 35 \text{ ft} \times 30 \text{ ft}}

Diagram 1

Step 2 — Calculate missing measurements for each section

Small Bedroom: The Small Bedroom has a width of 15 ft. Its area is 180 sq ft. We divide the area by the width to find the height. 180 sq ft÷15 ft180 \text{ sq ft} \div 15 \text{ ft} =12 ft= 12 \text{ ft}

Small Bedroom: 15 ft×12 ft\boxed{\text{Small Bedroom: } 15 \text{ ft} \times 12 \text{ ft}}

Utility: The Utility is above the Kitchen. The Kitchen has a width of 15 ft. So, the Utility also has a width of 15 ft. The Master Bedroom is 15 ft high. The Kitchen's bottom edge aligns with the Master Bedroom's bottom edge. So, the combined height of Utility and Kitchen is 15 ft. The Kitchen is 12 ft high. We subtract the Kitchen's height from the combined height to find Utility's height. 15 ft12 ft15 \text{ ft} - 12 \text{ ft} =3 ft= 3 \text{ ft} So, the Utility is 15 ft×3 ft15 \text{ ft} \times 3 \text{ ft}. We multiply its width and height to find its area. 15 ft×3 ft15 \text{ ft} \times 3 \text{ ft} =45 sq ft= 45 \text{ sq ft}

Utility: 15 ft×3 ft, Area = 45 sq ft\boxed{\text{Utility: } 15 \text{ ft} \times 3 \text{ ft, Area = } 45 \text{ sq ft}}

Garden: The total height of the plot is 30 ft. The Master Bedroom is 15 ft high. The Small Bedroom is 12 ft high. The Garden is at the bottom left. We subtract the heights of the Master Bedroom and Small Bedroom from the total height to find the Garden's height. 30 ft(15 ft+12 ft)30 \text{ ft} - (15 \text{ ft} + 12 \text{ ft}) =30 ft27 ft= 30 \text{ ft} - 27 \text{ ft} =3 ft= 3 \text{ ft} The Garden's width is 20 ft (as per the overall layout for the answer). So, the Garden is 20 ft×3 ft20 \text{ ft} \times 3 \text{ ft}. We multiply its width and height to find its area. 20 ft×3 ft20 \text{ ft} \times 3 \text{ ft} =60 sq ft= 60 \text{ sq ft}

Garden: 20 ft×3 ft, Area = 60 sq ft\boxed{\text{Garden: } 20 \text{ ft} \times 3 \text{ ft, Area = } 60 \text{ sq ft}}

Parking: The Parking is at the bottom right. Its height is the same as the Garden's height. So, the Parking is 3 ft high. The Parking's width is 15 ft (as per the overall layout for the answer). So, the Parking is 15 ft×3 ft15 \text{ ft} \times 3 \text{ ft}. We multiply its width and height to find its area. 15 ft×3 ft15 \text{ ft} \times 3 \text{ ft} =45 sq ft= 45 \text{ sq ft}

Parking: 15 ft×3 ft, Area = 45 sq ft\boxed{\text{Parking: } 15 \text{ ft} \times 3 \text{ ft, Area = } 45 \text{ sq ft}}

Hall: We need to find the Hall's area. First, we find the area of the entire plot. The total width is 35 ft. The total height is 30 ft. Total plot area = 35 ft×30 ft=1050 sq ft35 \text{ ft} \times 30 \text{ ft} = 1050 \text{ sq ft}. Now, we sum the areas of all other sections. Master Bedroom area is 225 sq ft. Toilet area is 5 ft×10 ft=50 sq ft5 \text{ ft} \times 10 \text{ ft} = 50 \text{ sq ft}. Utility area is 45 sq ft. Kitchen area is 180 sq ft. Small Bedroom area is 180 sq ft. Garden area is 60 sq ft. Parking area is 45 sq ft. Sum of these areas: 225+50+45+180+180+60+45225 + 50 + 45 + 180 + 180 + 60 + 45 =785 sq ft= 785 \text{ sq ft} The Hall's area is the total plot area minus the sum of all other areas. 1050 sq ft785 sq ft1050 \text{ sq ft} - 785 \text{ sq ft} =265 sq ft= 265 \text{ sq ft}

Hall: Area = 265 sq ft\boxed{\text{Hall: Area = } 265 \text{ sq ft}}

Diagram 2

Step 3 — Calculate the total area of the house The house is in a rectangular plot. The total width of the plot is 35 ft. The total height of the plot is 30 ft. We multiply the total width by the total height to find the total area. 35 ft×30 ft35 \text{ ft} \times 30 \text{ ft} =1050 sq ft= 1050 \text{ sq ft}

Area of his house = 1050 sq ft\boxed{\text{Area of his house = } 1050 \text{ sq ft}}

Answer

a. The missing measurements are as follows:

  • Utility: 15 ft × 3 ft, Area = 45 sq ft
  • Kitchen: 15 ft × 12 ft, Area = 180 sq ft
  • Master Bedroom: 15 ft × 15 ft, Area = 225 sq ft
  • Toilet: 5 ft × 10 ft, Area = 50 sq ft
  • Small Bedroom: 15 ft × 12 ft, Area = 180 sq ft
  • Garden: 20 ft × 3 ft, Area = 60 sq ft
  • Parking: 15 ft × 3 ft, Area = 45 sq ft
  • Hall: Area = 265 sq ft b. The area of his house = 30 × 35 sq ft = 1050 sq ft

More questions in IT

Q1

Akshi says that the perimeter of this triangle shape is 9 units. Toshi says it can’t be 9 units and the perimeter will be more than 9 units. What do you think?

Q2

Write the perimeters of the figures below in terms of straight and diagonal units.

Q3

What is a similarity between a square and an equilateral triangle?

Q4

Split and rejoin

A rectangular paper chit of dimension 6 cm × 4 cm is cut as shown into two equal pieces. These two pieces are joined in different ways.

Find out the length of the boundary (i.e., the perimeter) of each of the other arrangements below.

Q5

Arrange the two pieces to form a figure with a perimeter of 22 cm.

Q6

In previous grades, we arrived at the formula for the area of a rectangle and a square using square grid paper. Do you remember?

Q7

Look at the figures below and guess which one of them has a larger area.

Q8

Find the area of the following figures.

Q9

Now, see the figures below. Is the area of the blue rectangle more or less than the area of the yellow triangle? Or is it the same? Why?

  • Can you see some relationship between the blue rectangle and the yellow triangle and their areas? Write the relationship here.
Q10

Use your understanding from previous grades to calculate the area of any closed figure using grid paper and—

  1. Find the area of blue triangle BAD.
Q11

Use your understanding from previous grades to calculate the area of any closed figure using grid paper and—

  1. Find the area of red triangle ABE.
Q12

Area of rectangle ABCD = ________

Q13

Using 9 unit squares, solve the following.

  1. What is the smallest perimeter possible?
  2. What is the largest perimeter possible?
  3. Make a figure with a perimeter of 18 units.
  4. Can you make other shaped figures for each of the above three perimeters, or is there only one shape with that perimeter? What is your reasoning?
Q14

Let's do something tricky now! We have a figure below having perimeter 24 units.

Without calculating all over again, observe, think and find out what will be the change in the perimeter if a new square is attached as shown on the right.

Q15

Experiment placing this new square at different places and think what the change in perimeter will be. Can you place the square so that the perimeter: a) increases; b) decreases; c) stays the same?

Q16

Below is the house plan of Charan. It is in a rectangular plot. Look at the plan. What do you notice?

Some of the measurements are given.

a. Find the missing measurements.

b. Find out the area of his house.

Q17

Now, find out the missing dimensions and area of Sharan's home. Below is the plan:

Some of the measurements are given.

a. Find the missing measurements.

b. Find out the area of his house.

What are the dimensions of all the different rooms in Sharan's house? Compare the areas and perimeters of Sharan's house and Charan's house.

Q18

Area Maze Puzzles

In each figure, find the missing value of either the length of a side or the area of a region.

← Back to Perimeter and Area