Coordinate Geometry | Exercise 7.2

Question 8

If A and B are (2,2)(-2, -2) and (2,4)(2, -4), respectively, find the coordinates of P such that AP=37AB\text{AP} = \frac{3}{7} \text{AB} and P lies on the line segment AB.

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Solution

AP=37AB\text{AP} = \frac{3}{7}\text{AB} means P is 37\frac{3}{7}ths of the way from A to B, so AP takes 3 parts and PB takes the remaining 4 parts — giving a ratio of 3:43:4.

Section Formula: If a point P(x,y)\text{P}(x, y) divides the line segment joining A(x1,y1)\text{A}(x_1, y_1) and B(x2,y2)\text{B}(x_2, y_2) in the ratio m:nm:n internally, then:

x=mx2+nx1m+n,y=my2+ny1m+nx = \frac{mx_2 + nx_1}{m + n}, \quad y = \frac{my_2 + ny_1}{m + n}

We will use the section formula to find point P.

Step 1 — Find the ratio

The problem tells us AP=37AB\text{AP} = \frac{3}{7} \text{AB}. This means AP is 3 parts of the segment. AB is 7 parts in total. So, PB must be 73=47 - 3 = 4 parts. Point P divides AB in the ratio 3:43:4. We can say m=3m = 3 and n=4n = 4.

m:n=3:4\boxed{m:n = 3:4}

Step 2 — Identify coordinates

Let's write down the given points. Point A is (x1,y1)=(2,2)(x_1, y_1) = (-2, -2). Point B is (x2,y2)=(2,4)(x_2, y_2) = (2, -4).

Step 3 — Calculate x-coordinate

We use the section formula for xx. The formula is x=mx2+nx1m+nx = \frac{mx_2 + nx_1}{m+n}. x=3(2)+4(2)3+4x = \frac{3(2) + 4(-2)}{3+4} =687= \frac{6 - 8}{7} =27= \frac{-2}{7}

x=27\boxed{x = -\frac{2}{7}}

Step 4 — Calculate y-coordinate

Now we find the y-coordinate. The formula is y=my2+ny1m+ny = \frac{my_2 + ny_1}{m+n}. y=3(4)+4(2)3+4y = \frac{3(-4) + 4(-2)}{3+4} =1287= \frac{-12 - 8}{7} =207= \frac{-20}{7}

y=207\boxed{y = -\frac{20}{7}}

Step 5 — State P's coordinates

Let's write the coordinates of P. P has coordinates (x,y)(x, y).

P(27,207)\boxed{\text{P} \left(-\frac{2}{7}, -\frac{20}{7}\right)}

Answer

The coordinates of P are (27,207)\left(-\frac{2}{7}, -\frac{20}{7}\right).

More questions in Exercise 7.2

Q1

Find the coordinates of the point which divides the join of (1,7)(-1, 7) and (4,3)(4, -3) in the ratio 2:32 : 3.

Q2

Find the coordinates of the points of trisection of the line segment joining (4,1)(4, -1) and (2,3)(-2, -3).

Q3

To conduct Sports Day activities, in your rectangular shaped school ground ABCD, lines have been drawn with chalk powder at a distance of 1m each. 100 flower pots have been placed at a distance of 1m from each other along AD, as shown in Fig. 7.12. Niharika runs 14\frac{1}{4} th the distance AD on the 2nd line and posts a green flag. Preet runs 15\frac{1}{5} th the distance AD on the eighth line and posts a red flag. What is the distance between both the flags? If Rashmi has to post a blue flag exactly halfway between the line segment joining the two flags, where should she post her flag?

Q4

Find the ratio in which the line segment joining the points (3,10)(-3, 10) and (6,8)(6, -8) is divided by (1,6)(-1, 6).

Q5

Find the ratio in which the line segment joining A(1,5)A(1, -5) and B(4,5)B(-4, 5) is divided by the xx-axis. Also find the coordinates of the point of division.

Q6

If (1,2)(1, 2), (4,y)(4, y), (x,6)(x, 6) and (3,5)(3, 5) are the vertices of a parallelogram taken in order, find xx and yy.

Q7

Find the coordinates of a point A, where AB is the diameter of a circle whose centre is (2,3)(2, -3) and B is (1,4)(1, 4).

Q8

If A and B are (2,2)(-2, -2) and (2,4)(2, -4), respectively, find the coordinates of P such that AP=37AB\text{AP} = \frac{3}{7} \text{AB} and P lies on the line segment AB.

Q9

Find the coordinates of the points which divide the line segment joining A(2,2)A(-2, 2) and B(2,8)B(2, 8) into four equal parts.

Q10

Find the area of a rhombus if its vertices are (3,0)(3, 0), (4,5)(4, 5), (1,4)(-1, 4) and (2,1)(-2, -1) taken in order.

[Hint : Area of a rhombus = 12\frac{1}{2} (product of its diagonals)]

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