The World of Numbers | Exercise 3.2

Question 2

A spice trader takes a loan (debt) of ₹850. The next day, he makes a profit (fortune) of ₹1,200. The following week, he incurs a loss of ₹450. Write this sequence as an equation using integers and calculate his final financial standing.

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Solution
Understand the Question
  • Represent the transactions using positive and negative integers:
    • Loan/Debt: Money owed, represented as a negative integer (850-850).
    • Profit/Fortune: Money gained, represented as a positive integer (+1200+1200).
    • Loss: Money lost, represented as a negative integer (450-450).
  • To find the final financial standing, sum all the integer values together.

Step 1 · Form the Equation

Representing the transactions with integers:

  • Debt of ₹850 =850= -850
  • Profit of ₹1,200 =+1200= +1200
  • Loss of ₹450 =450= -450Diagram 1

Equation representing the sequence: 850+1200450-850 + 1200 - 450

Step 2 · Calculate the Final Financial Standing

Adding the integers from left to right:

850+1200450=350450=100\begin{aligned} -850 + 1200 - 450 &= 350 - 450 \\ &= -100 \end{aligned}
Answer

Equation: 850+1200450-850 + 1200 - 450 Final financial standing: 100-\text{₹}100 (a net loss of 100\text{₹}100)

Common Mistakes
  • Incorrect Sign Conventions: Treating debt or loss as positive values instead of negative integers.
  • Sign Errors in Arithmetic: Making errors when combining positive and negative integers (e.g., computing 850+1200-850 + 1200 as 350-350 instead of +350+350).

More questions in Exercise 3.2

Q1

The temperature in the high-altitude desert of Ladakh is recorded as 4C4^\circ\text{C} at noon. By midnight, it drops by 15C15^\circ\text{C}. What is the midnight temperature?

Q2

A spice trader takes a loan (debt) of ₹850. The next day, he makes a profit (fortune) of ₹1,200. The following week, he incurs a loss of ₹450. Write this sequence as an equation using integers and calculate his final financial standing.

Q3

Calculate the following using Brahmagupta's laws:

(i) (12)×5(-12) \times 5

(ii) (8)×(7)(-8) \times (-7)

(iii) 0(14)0 - (-14)

(iv) (20)÷4(-20) \div 4

Q4

Explain, using a real-world example of debt, why subtracting a negative number is the same as adding a positive number (e.g., 10(5)=1510 - (-5) = 15).

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