Measuring Space: Perimeter and Area | Exercise 6.3

Question 1

Unless stated otherwise, use the approximation 227\frac{22}{7} for π\pi.

Find the area of a sector of a circle with radius 7 cm if the angle of the sector is 60°.

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Solution

We will use the formula to find the area of a sector.

Step 1 — Note the Values

Let's write down the given values. The radius of the circle is 7 cm\mathbf{7 \text{ cm}}. The angle of the sector is 60\mathbf{60^\circ}. We will use π=227\pi = \frac{22}{7}.

Diagram 1

Step 2 — Calculate the Area

Now, let's calculate the area of the sector. The formula for the area of a sector is θ360×πr2\frac{\theta}{360} \times \pi r^2.

Area=60360×227×72\text{Area} = \frac{60}{360} \times \frac{22}{7} \times 7^2

=16×227×49= \frac{1}{6} \times \frac{22}{7} \times 49

=16×22×7= \frac{1}{6} \times 22 \times 7

=1546= \frac{154}{6}

=773= \frac{77}{3}

773 cm2\boxed{\frac{77}{3} \text{ cm}^2}

Answer

(i) The area of the sector is 773 cm2\frac{77}{3} \text{ cm}^2.

More questions in Exercise 6.3

Q1

Unless stated otherwise, use the approximation 227\frac{22}{7} for π\pi.

Find the area of a sector of a circle with radius 7 cm if the angle of the sector is 60°.

Q2

Find the area of a quadrant of a circle whose circumference is 44 cm.

Q3

The length of the minute hand of a clock is 7 cm. Find the area swept by the minute hand in 10 minutes.

Q4

A chord of a circle of radius 10 cm subtends 90° at the centre. Find the area of the corresponding:

(i) minor sector (that subtends 90° at the centre), and (ii) major sector (that subtends 270° at the centre). (Use π3.14\pi \approx 3.14.)

Q5

A chord of a circle of radius 15 cm subtends an angle of 60° at the centre of the circle. Find the areas of the corresponding minor and major segments of the circle. (Use π3.14\pi \approx 3.14 and 31.73\sqrt{3} \approx 1.73.)

Q6

A car has two wipers which do not overlap. Each wiper has a blade of length 28 cm and sweeps through an angle of 120°. Find the total area cleaned at each sweep of the blades.

Q7

A chord of a circle of radius rr subtends an angle of 60° at the centre of the circle. Show that the area of the corresponding minor segment of the circle is equal to πr2(1634)\pi r^2 \left( \frac{1}{6} - \frac{\sqrt{3}}{4} \right).

Q8

An equilateral triangle is inscribed in a circle of radius rr. Show that the ratio of the area of the triangle to the area of the circle is equal to 334π0.413\frac{3\sqrt{3}}{4\pi} \approx 0.413.

Q9

A square is inscribed in a circle of radius rr. Show that the ratio of the area of the square to the area of the circle is equal to 2π0.637\frac{2}{\pi} \approx 0.637.

Q10

A hexagon is inscribed in a circle of radius rr. Show that the ratio of the area of the hexagon to the area of the circle is equal to 332π0.827\frac{3\sqrt{3}}{2\pi} \approx 0.827. Can you see why the answer is exactly twice the answer to Question 8?

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