Measuring Space: Perimeter and Area | Exercise 6.3

Question 9

A square is inscribed in a circle of radius rr. Show that the ratio of the area of the square to the area of the circle is equal to 2π0.637\frac{2}{\pi} \approx 0.637.

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Solution

We need to find the ratio of the area of a square inscribed in a circle to the area of the circle.

Step 1 — Understand the setup

Let the radius of the circle be rr. The square is inscribed in the circle. This means the vertices of the square touch the circle. The diagonal of the square is the diameter of the circle.

Diameter of circle=2r\text{Diameter of circle} = 2r

Diagonal of square=2r\text{Diagonal of square} = 2r

Diagram 1

Step 2 — Find the side of the square

Let the side of the square be aa. We can use the Pythagorean theorem. Consider a right-angled triangle formed by two sides and the diagonal.

a2+a2=(diagonal)2a^2 + a^2 = (\text{diagonal})^2

2a2=(2r)22a^2 = (2r)^2

2a2=4r22a^2 = 4r^2

a2=4r22a^2 = \frac{4r^2}{2}

a2=2r2\boxed{a^2 = 2r^2}

Step 3 — Calculate the areas

The area of the square is a2a^2. From Step 2, we know a2=2r2a^2 = \mathbf{2r^2}.

Area of square=2r2\text{Area of square} = 2r^2

The area of the circle is given by the formula.

Area of circle=πr2\text{Area of circle} = \pi r^2

Step 4 — Find the ratio

We need the ratio of the area of the square to the area of the circle.

Ratio=Area of squareArea of circle\text{Ratio} = \frac{\text{Area of square}}{\text{Area of circle}}

Ratio=2r2πr2\text{Ratio} = \frac{2r^2}{\pi r^2}

Ratio=2π\text{Ratio} = \frac{2}{\pi}

Now, let's approximate this value. We know that π3.14159\pi \approx \mathbf{3.14159}.

Ratio23.14159\text{Ratio} \approx \frac{2}{3.14159}

Ratio0.636619\text{Ratio} \approx 0.636619

Rounding to three decimal places, we get 0.637\mathbf{0.637}.

Ratio0.637\boxed{\text{Ratio} \approx 0.637}

Answer

The ratio of the area of the square to the area of the circle is 2π\frac{2}{\pi}. This ratio is approximately 0.637\mathbf{0.637}.

More questions in Exercise 6.3

Q1

Unless stated otherwise, use the approximation 227\frac{22}{7} for π\pi.

Find the area of a sector of a circle with radius 7 cm if the angle of the sector is 60°.

Q2

Find the area of a quadrant of a circle whose circumference is 44 cm.

Q3

The length of the minute hand of a clock is 7 cm. Find the area swept by the minute hand in 10 minutes.

Q4

A chord of a circle of radius 10 cm subtends 90° at the centre. Find the area of the corresponding:

(i) minor sector (that subtends 90° at the centre), and (ii) major sector (that subtends 270° at the centre). (Use π3.14\pi \approx 3.14.)

Q5

A chord of a circle of radius 15 cm subtends an angle of 60° at the centre of the circle. Find the areas of the corresponding minor and major segments of the circle. (Use π3.14\pi \approx 3.14 and 31.73\sqrt{3} \approx 1.73.)

Q6

A car has two wipers which do not overlap. Each wiper has a blade of length 28 cm and sweeps through an angle of 120°. Find the total area cleaned at each sweep of the blades.

Q7

A chord of a circle of radius rr subtends an angle of 60° at the centre of the circle. Show that the area of the corresponding minor segment of the circle is equal to πr2(1634)\pi r^2 \left( \frac{1}{6} - \frac{\sqrt{3}}{4} \right).

Q8

An equilateral triangle is inscribed in a circle of radius rr. Show that the ratio of the area of the triangle to the area of the circle is equal to 334π0.413\frac{3\sqrt{3}}{4\pi} \approx 0.413.

Q9

A square is inscribed in a circle of radius rr. Show that the ratio of the area of the square to the area of the circle is equal to 2π0.637\frac{2}{\pi} \approx 0.637.

Q10

A hexagon is inscribed in a circle of radius rr. Show that the ratio of the area of the hexagon to the area of the circle is equal to 332π0.827\frac{3\sqrt{3}}{2\pi} \approx 0.827. Can you see why the answer is exactly twice the answer to Question 8?

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