Rational Numbers | FIO

Question 9

How many tiny squares are there in the following picture? Write the prime factorisation of the number of tiny squares.

Question diagram 1
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Solution
Understand the Question
  • The given image consists of a large grid arranged into 99 rows and 99 columns of big squares.
  • Each big square is further divided into a smaller grid of 5×55 \times 5 tiny squares.
  • To find the total number of tiny squares, multiply the total number of big squares by the number of tiny squares in each big square.
  • The prime factorisation is obtained by expressing the total count as a product of prime powers.

Step 1 · Count Total Number of Big Squares

Number of big squares in a row =9= 9 Number of big squares in a column =9= 9Diagram 1

Total number of big squares=Number of rows×Number of columns=9×9=81\begin{aligned} \text{Total number of big squares} &= \text{Number of rows} \times \text{Number of columns} \\ &= 9 \times 9 \\ &= 81 \end{aligned}

Step 2 · Count Tiny Squares in Each Big Square

Number of tiny squares along one side of a big square =5= 5

Number of tiny squares in each big square=5×5=25\begin{aligned} \text{Number of tiny squares in each big square} &= 5 \times 5 \\ &= 25 \end{aligned}

Step 3 · Calculate Total Number of Tiny Squares

Total tiny squares=Total number of big squares×Number of tiny squares in each big square=81×25=2025\begin{aligned} \text{Total tiny squares} &= \text{Total number of big squares} \times \text{Number of tiny squares in each big square} \\ &= 81 \times 25 \\ &= 2025 \end{aligned}

Step 4 · Find Prime Factorisation of Total Tiny Squares

Dividing 20252025 by prime factors:

2025÷5=405405÷5=81\begin{aligned} 2025 \div 5 &= 405 \\ 405 \div 5 &= 81 \end{aligned}

Since 81=9×9=(3×3)×(3×3)81 = 9 \times 9 = (3 \times 3) \times (3 \times 3):

Prime factorisation of 2025=3×3×3×3×5×5=34×52\begin{aligned} \text{Prime factorisation of } 2025 &= 3 \times 3 \times 3 \times 3 \times 5 \times 5 \\ &= 3^4 \times 5^2 \end{aligned}
Answer

Total tiny squares =2025= 2025; Prime factorisation =34×52= 3^4 \times 5^2

Common Mistakes
  • Manual Counting: Attempting to count all tiny squares individually instead of multiplying grid dimensions (81×2581 \times 25).
  • Incomplete Prime Factorisation: Leaving factors with composite bases like 92×529^2 \times 5^2 or 81×2581 \times 25 instead of reducing 8181 to prime base 343^4.
  • Direct Factorisation Shortcut: 2025=81×25=34×522025 = 81 \times 25 = 3^4 \times 5^2 can be factored directly from the sub-counts without needing long division.

More questions in FIO

Q1

Which of the following numbers are not perfect squares?

(i) 2032 (ii) 2048 (iii) 1027 (iv) 1089

Q2

Which one among 64264^2, 1082108^2, 2922292^2, 36236^2 has last digit 4?

Q3

Given 1252=15625125^2 = 15625, what is the value of 1262126^2?

(i) 15625+12615625 + 126

(ii) 15625+26215625 + 26^2

(iii) 15625+25315625 + 253

(iv) 15625+25115625 + 251

(v) 15625+51215625 + 51^2

Q4

Find the length of the side of a square whose area is 441 m2441 \text{ m}^2.

Q5

Find the smallest square number that is divisible by each of the following numbers: 4, 9, and 10.

Q6

Find the smallest number by which 9408 must be multiplied so that the product is a perfect square. Find the square root of the product.

Q7

How many numbers lie between the squares of the following numbers?

(i) 16 and 17 (ii) 99 and 100

Q8

In the following pattern, fill in the missing numbers:

12+22+22=3222+32+62=7232+42+122=132\begin{aligned} 1^2 + 2^2 + 2^2 &= 3^2 \\ 2^2 + 3^2 + 6^2 &= 7^2 \\ 3^2 + 4^2 + 12^2 &= 13^2 \end{aligned}

(a) 42+52+202=()24^2 + 5^2 + 20^2 = (\underline{\quad})^2

(b) 92+102+()2=()29^2 + 10^2 + (\underline{\quad})^2 = (\underline{\quad})^2

Q9

How many tiny squares are there in the following picture? Write the prime factorisation of the number of tiny squares.

Q10

Find the cube roots of 2700027000 and 1064810648.

Q11

What number will you multiply by 1323 to make it a cube number?

Q12

State true or false. Explain your reasoning.

(i) The cube of any odd number is even.

(ii) There is no perfect cube that ends with 8.

(iii) The cube of a 2-digit number may be a 3-digit number.

(iv) The cube of a 2-digit number may have seven or more digits.

(v) Cube numbers have an odd number of factors.

Q13

You are told that 13311331 is a perfect cube. Can you guess without factorisation what its cube root is? Similarly, guess the cube roots of 49134913, 1216712167, and 3276832768.

Q14

Which of the following is the greatest? Explain your reasoning.

(i) 67366367^3 - 66^3

(ii) 43342343^3 - 42^3

(iii) 67266267^2 - 66^2

(iv) 43242243^2 - 42^2

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