Rational Numbers | FIO

Question 6

Find the smallest number by which 9408 must be multiplied so that the product is a perfect square. Find the square root of the product.

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Solution
Understand the Question
  • A number is a perfect square if all prime factors in its prime factorisation occur in complete pairs (even powers).
  • To find the smallest number to multiply 94089408 by, we find its prime factorisation and identify any unpaired factor.
  • Multiplying 94089408 by the unpaired factor makes all prime factors paired, giving a perfect square.
  • We then take one factor from each pair to find the square root of the new product.

Step 1 · Prime Factorisation of 9408

Diagram 1

9408÷2=47044704÷2=23522352÷2=11761176÷2=588588÷2=294294÷2=147147÷3=4949÷7=77÷7=1\begin{aligned} 9408 \div 2 &= 4704 \\ 4704 \div 2 &= 2352 \\ 2352 \div 2 &= 1176 \\ 1176 \div 2 &= 588 \\ 588 \div 2 &= 294 \\ 294 \div 2 &= 147 \\ 147 \div 3 &= 49 \\ 49 \div 7 &= 7 \\ 7 \div 7 &= 1 \end{aligned}

Prime factorisation of 94089408: 9408=2×2×2×2×2×2×3×7×79408 = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 3 \times 7 \times 7

Grouping into pairs: 9408=(2×2)×(2×2)×(2×2)×3×(7×7)9408 = (2 \times 2) \times (2 \times 2) \times (2 \times 2) \times 3 \times (7 \times 7)

The prime factor 33 is unpaired. Therefore, 94089408 must be multiplied by 33 to make it a perfect square.

Step 2 · Calculate the Product and its Square Root

Multiply 94089408 by 33:

Product=9408×3=28224\begin{aligned} \text{Product} &= 9408 \times 3 \\[0.6em] &= 28224 \end{aligned}

Prime factors of 2822428224: 28224=(2×2)×(2×2)×(2×2)×(3×3)×(7×7)28224 = (2 \times 2) \times (2 \times 2) \times (2 \times 2) \times (3 \times 3) \times (7 \times 7)

Taking one factor from each pair:

28224=(2×2)×(2×2)×(2×2)×(3×3)×(7×7)=2×2×2×3×7=8×21=168\begin{aligned} \sqrt{28224} &= \sqrt{(2 \times 2) \times (2 \times 2) \times (2 \times 2) \times (3 \times 3) \times (7 \times 7)} \\[0.6em] &= 2 \times 2 \times 2 \times 3 \times 7 \\[0.6em] &= 8 \times 21 \\[0.6em] &= 168 \end{aligned}
Answer

Smallest multiplying factor is 33, and 28224=168\sqrt{28224} = 168

Common Mistakes
  • Arithmetic Error in Division: Making mistakes during repeated division, particularly when dividing 147147 by 33 or 4949 by 77.
  • Pairing Error: Forgetting to include the newly multiplied factor 33 when pairing the prime factors for the square root calculation.
  • Taking Square Root Directly: Attempting to find the square root of 94089408 instead of the resulting product (2822428224).

More questions in FIO

Q1

Which of the following numbers are not perfect squares?

(i) 2032 (ii) 2048 (iii) 1027 (iv) 1089

Q2

Which one among 64264^2, 1082108^2, 2922292^2, 36236^2 has last digit 4?

Q3

Given 1252=15625125^2 = 15625, what is the value of 1262126^2?

(i) 15625+12615625 + 126

(ii) 15625+26215625 + 26^2

(iii) 15625+25315625 + 253

(iv) 15625+25115625 + 251

(v) 15625+51215625 + 51^2

Q4

Find the length of the side of a square whose area is 441 m2441 \text{ m}^2.

Q5

Find the smallest square number that is divisible by each of the following numbers: 4, 9, and 10.

Q6

Find the smallest number by which 9408 must be multiplied so that the product is a perfect square. Find the square root of the product.

Q7

How many numbers lie between the squares of the following numbers?

(i) 16 and 17 (ii) 99 and 100

Q8

In the following pattern, fill in the missing numbers:

12+22+22=3222+32+62=7232+42+122=132\begin{aligned} 1^2 + 2^2 + 2^2 &= 3^2 \\ 2^2 + 3^2 + 6^2 &= 7^2 \\ 3^2 + 4^2 + 12^2 &= 13^2 \end{aligned}

(a) 42+52+202=()24^2 + 5^2 + 20^2 = (\underline{\quad})^2

(b) 92+102+()2=()29^2 + 10^2 + (\underline{\quad})^2 = (\underline{\quad})^2

Q9

How many tiny squares are there in the following picture? Write the prime factorisation of the number of tiny squares.

Q10

Find the cube roots of 2700027000 and 1064810648.

Q11

What number will you multiply by 1323 to make it a cube number?

Q12

State true or false. Explain your reasoning.

(i) The cube of any odd number is even.

(ii) There is no perfect cube that ends with 8.

(iii) The cube of a 2-digit number may be a 3-digit number.

(iv) The cube of a 2-digit number may have seven or more digits.

(v) Cube numbers have an odd number of factors.

Q13

You are told that 13311331 is a perfect cube. Can you guess without factorisation what its cube root is? Similarly, guess the cube roots of 49134913, 1216712167, and 3276832768.

Q14

Which of the following is the greatest? Explain your reasoning.

(i) 67366367^3 - 66^3

(ii) 43342343^3 - 42^3

(iii) 67266267^2 - 66^2

(iv) 43242243^2 - 42^2

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