Rational Numbers | FIO

Question 3

Given 1252=15625125^2 = 15625, what is the value of 1262126^2?

(i) 15625+12615625 + 126

(ii) 15625+26215625 + 26^2

(iii) 15625+25315625 + 253

(iv) 15625+25115625 + 251

(v) 15625+51215625 + 51^2

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Solution
Understand the Question
  • We are given the value of 1252=15625125^2 = 15625 and need to find the expression for 1262126^2.
  • We can rewrite 126126 as (125+1)(125 + 1) and expand it using the standard algebraic identity: (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
  • Substituting a=125a = 125 and b=1b = 1 allows us to express 1262126^2 in terms of 1252125^2.

Step 1 · Expand 1262126^2 using (a+b)2(a + b)^2

Write 126126 as (125+1)(125 + 1).

Using the identity (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2 where a=125a = 125 and b=1b = 1:

1262=(125+1)2=1252+(2×125×1)+12=15625+250+1=15625+251\begin{aligned} 126^2 &= (125 + 1)^2 \\ &= 125^2 + (2 \times 125 \times 1) + 1^2 \\ &= 15625 + 250 + 1 \\ &= 15625 + 251 \end{aligned}

This matches option (iv).

Answer

(iv) 15625+25115625 + 251

Common Mistakes
  • Forgetting the 2ab2ab term: Incorrectly assuming (125+1)2=1252+12=15625+1(125 + 1)^2 = 125^2 + 1^2 = 15625 + 1, missing the linear cross term 2×125×1=2502 \times 125 \times 1 = 250.
  • Adding the base instead of the difference: Choosing option (i) by mistakenly adding 126126 instead of the actual difference between consecutive squares, (n+1)2n2=2n+1=2(125)+1=251(n+1)^2 - n^2 = 2n + 1 = 2(125) + 1 = 251.

More questions in FIO

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(i) 2032 (ii) 2048 (iii) 1027 (iv) 1089

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Q3

Given 1252=15625125^2 = 15625, what is the value of 1262126^2?

(i) 15625+12615625 + 126

(ii) 15625+26215625 + 26^2

(iii) 15625+25315625 + 253

(iv) 15625+25115625 + 251

(v) 15625+51215625 + 51^2

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(i) 16 and 17 (ii) 99 and 100

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(a) 42+52+202=()24^2 + 5^2 + 20^2 = (\underline{\quad})^2

(b) 92+102+()2=()29^2 + 10^2 + (\underline{\quad})^2 = (\underline{\quad})^2

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Q12

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(i) The cube of any odd number is even.

(ii) There is no perfect cube that ends with 8.

(iii) The cube of a 2-digit number may be a 3-digit number.

(iv) The cube of a 2-digit number may have seven or more digits.

(v) Cube numbers have an odd number of factors.

Q13

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(iii) 67266267^2 - 66^2

(iv) 43242243^2 - 42^2

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