Power Play (Exponents) | FIO

Question 10

Circle the numbers that are the same—

24×362^4 \times 3^6            64×326^4 \times 3^2            6106^{10}            182×6218^2 \times 6^2            6246^{24}

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Solution

We will write each number using only its prime factors to compare them easily.

Step 1 — Simplify the first number

The first number is 24×362^4 \times 3^6. It is already in its simplest prime factor form. We will use this form to compare other numbers.

24×36\boxed{2^4 \times 3^6}

Step 2 — Simplify the second number

The second number is 64×326^4 \times 3^2. We know that 66 can be written as 2×32 \times 3. We use the exponent rule (a×b)m=am×bm(a \times b)^m = a^m \times b^m. This rule tells us how to distribute a power over a product. We also use am×an=am+na^m \times a^n = a^{m+n}. This rule helps us combine powers with the same base.

64×326^4 \times 3^2

=(2×3)4×32= (2 \times 3)^4 \times 3^2

=24×34×32= 2^4 \times 3^4 \times 3^2

=24×3(4+2)= 2^4 \times 3^{(4+2)}

24×36\boxed{2^4 \times 3^6}

Step 3 — Simplify the third number

The third number is 6106^{10}. Again, we write 66 as 2×32 \times 3. We use the rule (a×b)m=am×bm(a \times b)^m = a^m \times b^m.

6106^{10}

=(2×3)10= (2 \times 3)^{10}

210×310\boxed{2^{10} \times 3^{10}}

Step 4 — Simplify the fourth number

The fourth number is 182×6218^2 \times 6^2. First, we find the prime factors of 1818. 18=2×9=2×3218 = 2 \times 9 = 2 \times 3^2. We already know 6=2×36 = 2 \times 3. We use the rule (a×b)m=am×bm(a \times b)^m = a^m \times b^m. We also use (am)n=am×n(a^m)^n = a^{m \times n}. This rule helps us raise a power to another power. Finally, we use am×an=am+na^m \times a^n = a^{m+n}.

182×6218^2 \times 6^2

=(2×32)2×(2×3)2= (2 \times 3^2)^2 \times (2 \times 3)^2

=(22×(32)2)×(22×32)= (2^2 \times (3^2)^2) \times (2^2 \times 3^2)

=(22×32×2)×(22×32)= (2^2 \times 3^{2 \times 2}) \times (2^2 \times 3^2)

=(22×34)×(22×32)= (2^2 \times 3^4) \times (2^2 \times 3^2)

=2(2+2)×3(4+2)= 2^{(2+2)} \times 3^{(4+2)}

24×36\boxed{2^4 \times 3^6}

Step 5 — Simplify the fifth number

The fifth number is 6246^{24}. We write 66 as 2×32 \times 3. We use the rule (a×b)m=am×bm(a \times b)^m = a^m \times b^m.

6246^{24}

=(2×3)24= (2 \times 3)^{24}

224×324\boxed{2^{24} \times 3^{24}}

Answer

Comparing all the simplified forms, we see that three numbers are the same.

The numbers that are the same are: 24×362^4 \times 3^6, 64×326^4 \times 3^2, and 182×6218^2 \times 6^2.

More questions in FIO

Q1

Express the following in exponential form:

(i) 6×6×6×66 \times 6 \times 6 \times 6

(ii) y×yy \times y

(iii) b×b×b×bb \times b \times b \times b

(iv) 5×5×7×7×75 \times 5 \times 7 \times 7 \times 7

(v) 2×2×a×a2 \times 2 \times a \times a

(vi) a×a×a×c×c×c×c×da \times a \times a \times c \times c \times c \times c \times d

Q2

Express each of the following as a product of powers of their prime factors in exponential form:

(i) 648

(ii) 405

(iii) 540

(iv) 3600

Q3

Write the numerical value of each of the following:

(i) 2×1032 \times 10^3

(ii) 72×237^2 \times 2^3

(iii) 3×443 \times 4^4

(iv) (3)2×(5)2(-3)^2 \times (-5)^2

(v) 32×1043^2 \times 10^4

(vi) (2)5×(10)6(-2)^5 \times (-10)^6

Q4

Find out the units digit in the value of 2224÷4322^{224} \div 4^{32}? [Hint: 4=224 = 2^2]

Q5

There are 5 bottles in a container. Every day, a new container is brought in. How many bottles would there be after 40 days?

Q6

Write the given number as the product of two or more powers in three different ways. The powers can be any integers.

(i) 64364^3 (ii) 1928192^8 (iii) 32532^{-5}

Q7

Examine each statement below and find out if it is 'Always True', 'Only Sometimes True', or 'Never True'. Explain your reasoning.

(i) Cube numbers are also square numbers.

(ii) Fourth powers are also square numbers.

(iii) The fifth power of a number is divisible by the cube of that number.

(iv) The product of two cube numbers is a cube number.

(v) q46q^{46} is both a 4th power and a 6th power (qq is a prime number).

Q8

Simplify and write these in the exponential form.

(i) 102×10510^{-2} \times 10^{-5}

(ii) 57÷545^7 \div 5^4

(iii) 97÷949^{-7} \div 9^4

(iv) (132)3(13^{-2})^{-3}

(v) m5n12(mn)9m^5n^{12}(mn)^9

Q9

If 122=14412^2 = 144 what is

(i) (1.2)2(1.2)^2

(ii) (0.12)2(0.12)^2

(iii) (0.012)2(0.012)^2

(iv) 1202120^2

Q10

Circle the numbers that are the same—

24×362^4 \times 3^6            64×326^4 \times 3^2            6106^{10}            182×6218^2 \times 6^2            6246^{24}

Q11

Identify the greater number in each of the following—

(i) 434^3 or 343^4

(ii) 282^8 or 828^2

(iii) 1002100^2 or 21002^{100}

Q12

A dairy plans to produce 8.5 billion packets of milk in a year. They want a unique ID (identifier) code for each packet. If they choose to use the digits 0–9, how many digits should the code consist of?

Q13

64 is a square number (828^2) and a cube number (434^3). Are there other numbers that are both squares and cubes? Is there a way to describe such numbers in general?

Q14

A digital locker has an alphanumeric (it can have both digits and letters) passcode of length 5. Some example codes are G89P0, 38098, BRJKW, and 003AZ. How many such codes are possible?

Q15

The worldwide population of sheep (2024) is about 10910^9, and that of goats is also about the same. What is the total population of sheep and goats?

(ii) 20920^9

(ii) 101110^{11}

(iii) 101010^{10}

(iv) 101810^{18}

(v) 2×1092 \times 10^9

(vi) 109+10910^9 + 10^9

Q16

Calculate and write the answer in scientific notation:

(i) If each person in the world had 30 pieces of clothing, find the total number of pieces of clothing.

(ii) There are about 100 million bee colonies in the world. Find the number of honeybees if each colony has about 50,000 bees.

(iii) The human body has about 38 trillion bacterial cells. Find the bacterial population residing in all humans in the world.

(iv) Total time spent eating in a lifetime in seconds.

Q17

What was the date 1 arab/1 billion seconds ago?

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