Question 12
A dairy plans to produce 8.5 billion packets of milk in a year. They want a unique ID (identifier) code for each packet. If they choose to use the digits 0–9, how many digits should the code consist of?
We need to find the smallest number of digits required to create a unique code for each milk packet.
Step 1 — Total number of packets
First, let us write the total number of milk packets in standard numerical form. One billion means . So, 8.5 billion is 8.5 multiplied by one billion.
We can also write this number using powers of 10. The number is equal to .
Step 2 — Codes possible with 'n' digits
We are using digits from 0 to 9. This means we have 10 different choices for each digit position in the code. If we have a code with one digit, we can make 10 unique codes (0, 1, 2, ..., 9). This is . If we have a code with two digits, we can make unique codes (00, 01, ..., 99). This is . So, if we have a code with 'n' digits, we can make unique codes. Let 'n' be the number of digits in the code. The total number of unique codes we can make is . We need enough unique codes for all packets. So, the number of possible codes must be greater than or equal to the number of packets.
Step 3 — Finding the minimum number of digits
We need to find the smallest whole number 'n' that satisfies the inequality . Let us try different whole number values for 'n'. If , the number of unique codes is .
This is 1 billion. We need billion codes. Since is less than , 9 digits are not enough.
Let us try the next whole number for 'n', which is 10. If , the number of unique codes is .
This is 10 billion. Since is greater than , 10 digits are enough.
So, the smallest number of digits needed is 10.
Answer
The code must consist of 10 digits.
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