Power Play (Exponents) | FIO

Question 16

Calculate and write the answer in scientific notation:

(i) If each person in the world had 30 pieces of clothing, find the total number of pieces of clothing.

(ii) There are about 100 million bee colonies in the world. Find the number of honeybees if each colony has about 50,000 bees.

(iii) The human body has about 38 trillion bacterial cells. Find the bacterial population residing in all humans in the world.

(iv) Total time spent eating in a lifetime in seconds.

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Solution

We will use scientific notation to express very large numbers in a compact way. Scientific notation writes a number as a product of a number between 1 and 10 and a power of 10.

Step 1 — Total clothing pieces

Let us find the total number of clothes. We multiply the world population by clothes per person. The world population is about 8×1098 \times 10^9 people. Each person has 30 pieces of clothing.

Total clothes=(World population)×(Clothes per person)\text{Total clothes} = (\text{World population}) \times (\text{Clothes per person})

=(8×109)×30= (8 \times 10^9) \times 30

=(8×30)×109= (8 \times 30) \times 10^9

=240×109= 240 \times 10^9

To write this in scientific notation, we change 240 to 2.4×1022.4 \times 10^2.

=(2.4×102)×109= (2.4 \times 10^2) \times 10^9

=2.4×10(2+9)= 2.4 \times 10^{(2+9)}

2.4×1011 pieces of clothing\boxed{2.4 \times 10^{11} \text{ pieces of clothing}}

Diagram 1

Step 2 — Total honeybees

We need to find the total number of honeybees. We multiply the number of bee colonies by bees per colony. There are 100 million bee colonies. One million is 10610^6. So, 100 million is 100×106=102×106=108100 \times 10^6 = 10^2 \times 10^6 = 10^8. Each colony has 50,000 bees. 50,000 is 5×1045 \times 10^4.

Total bees=(Number of colonies)×(Bees per colony)\text{Total bees} = (\text{Number of colonies}) \times (\text{Bees per colony})

=(1×108)×(5×104)= (1 \times 10^8) \times (5 \times 10^4)

=(1×5)×(108×104)= (1 \times 5) \times (10^8 \times 10^4)

=5×10(8+4)= 5 \times 10^{(8+4)}

5×1012 bees\boxed{5 \times 10^{12} \text{ bees}}

Diagram 2

Step 3 — Total bacterial population

Let us calculate the total bacterial cells. We multiply the world population by bacterial cells per human. The world population is 8×1098 \times 10^9. Each human body has 38 trillion bacterial cells. One trillion is 101210^{12}. So, 38 trillion is 38×101238 \times 10^{12}. We write 3838 as 3.8×1013.8 \times 10^1. So, 3.8×101×1012=3.8×10133.8 \times 10^1 \times 10^{12} = 3.8 \times 10^{13}.

Total bacteria=(World population)×(Bacterial cells per human)\text{Total bacteria} = (\text{World population}) \times (\text{Bacterial cells per human})

=(8×109)×(3.8×1013)= (8 \times 10^9) \times (3.8 \times 10^{13})

=(8×3.8)×(109×1013)= (8 \times 3.8) \times (10^9 \times 10^{13})

=30.4×10(9+13)= 30.4 \times 10^{(9+13)}

=30.4×1022= 30.4 \times 10^{22}

To write this in scientific notation, we change 30.4 to 3.04×1013.04 \times 10^1.

=(3.04×101)×1022= (3.04 \times 10^1) \times 10^{22}

=3.04×10(1+22)= 3.04 \times 10^{(1+22)}

3.04×1023 bacterial cells\boxed{3.04 \times 10^{23} \text{ bacterial cells}}

Diagram 3

Step 4 — Total eating time in a lifetime

We need to find the total time spent eating in seconds. First, we convert daily eating time to seconds. Average eating time per day is 1.5 hours. There are 60 minutes in an hour and 60 seconds in a minute.

Eating time per day in seconds=1.5 hours×60 minutes/hour×60 seconds/minute\text{Eating time per day in seconds} = 1.5 \text{ hours} \times 60 \text{ minutes/hour} \times 60 \text{ seconds/minute}

=1.5×3600= 1.5 \times 3600

=5400 seconds= 5400 \text{ seconds}

Next, we find the number of days in an average lifespan. Average lifespan is 70 years. There are 365 days in a year.

Number of days in lifespan=70 years×365 days/year\text{Number of days in lifespan} = 70 \text{ years} \times 365 \text{ days/year}

=25550 days= 25550 \text{ days}

Finally, we multiply daily eating time by the number of days in a lifespan.

Total eating time in lifespan=(Eating time per day)×(Number of days in lifespan)\text{Total eating time in lifespan} = (\text{Eating time per day}) \times (\text{Number of days in lifespan})

=5400×25550= 5400 \times 25550

=137,970,000 seconds= 137,970,000 \text{ seconds}

To write this in scientific notation, we move the decimal point 8 places to the left.

1.3797×108 seconds\boxed{1.3797 \times 10^8 \text{ seconds}}

Diagram 4

Answer

(i) The total number of pieces of clothing is 2.4×10112.4 \times 10^{11}. (ii) The total number of honeybees is 5×10125 \times 10^{12}. (iii) The total bacterial population residing in all humans is 3.04×10233.04 \times 10^{23}. (iv) The total time spent eating in a lifetime is 1.3797×1081.3797 \times 10^8 seconds.

More questions in FIO

Q1

Express the following in exponential form:

(i) 6×6×6×66 \times 6 \times 6 \times 6

(ii) y×yy \times y

(iii) b×b×b×bb \times b \times b \times b

(iv) 5×5×7×7×75 \times 5 \times 7 \times 7 \times 7

(v) 2×2×a×a2 \times 2 \times a \times a

(vi) a×a×a×c×c×c×c×da \times a \times a \times c \times c \times c \times c \times d

Q2

Express each of the following as a product of powers of their prime factors in exponential form:

(i) 648

(ii) 405

(iii) 540

(iv) 3600

Q3

Write the numerical value of each of the following:

(i) 2×1032 \times 10^3

(ii) 72×237^2 \times 2^3

(iii) 3×443 \times 4^4

(iv) (3)2×(5)2(-3)^2 \times (-5)^2

(v) 32×1043^2 \times 10^4

(vi) (2)5×(10)6(-2)^5 \times (-10)^6

Q4

Find out the units digit in the value of 2224÷4322^{224} \div 4^{32}? [Hint: 4=224 = 2^2]

Q5

There are 5 bottles in a container. Every day, a new container is brought in. How many bottles would there be after 40 days?

Q6

Write the given number as the product of two or more powers in three different ways. The powers can be any integers.

(i) 64364^3 (ii) 1928192^8 (iii) 32532^{-5}

Q7

Examine each statement below and find out if it is 'Always True', 'Only Sometimes True', or 'Never True'. Explain your reasoning.

(i) Cube numbers are also square numbers.

(ii) Fourth powers are also square numbers.

(iii) The fifth power of a number is divisible by the cube of that number.

(iv) The product of two cube numbers is a cube number.

(v) q46q^{46} is both a 4th power and a 6th power (qq is a prime number).

Q8

Simplify and write these in the exponential form.

(i) 102×10510^{-2} \times 10^{-5}

(ii) 57÷545^7 \div 5^4

(iii) 97÷949^{-7} \div 9^4

(iv) (132)3(13^{-2})^{-3}

(v) m5n12(mn)9m^5n^{12}(mn)^9

Q9

If 122=14412^2 = 144 what is

(i) (1.2)2(1.2)^2

(ii) (0.12)2(0.12)^2

(iii) (0.012)2(0.012)^2

(iv) 1202120^2

Q10

Circle the numbers that are the same—

24×362^4 \times 3^6            64×326^4 \times 3^2            6106^{10}            182×6218^2 \times 6^2            6246^{24}

Q11

Identify the greater number in each of the following—

(i) 434^3 or 343^4

(ii) 282^8 or 828^2

(iii) 1002100^2 or 21002^{100}

Q12

A dairy plans to produce 8.5 billion packets of milk in a year. They want a unique ID (identifier) code for each packet. If they choose to use the digits 0–9, how many digits should the code consist of?

Q13

64 is a square number (828^2) and a cube number (434^3). Are there other numbers that are both squares and cubes? Is there a way to describe such numbers in general?

Q14

A digital locker has an alphanumeric (it can have both digits and letters) passcode of length 5. Some example codes are G89P0, 38098, BRJKW, and 003AZ. How many such codes are possible?

Q15

The worldwide population of sheep (2024) is about 10910^9, and that of goats is also about the same. What is the total population of sheep and goats?

(ii) 20920^9

(ii) 101110^{11}

(iii) 101010^{10}

(iv) 101810^{18}

(v) 2×1092 \times 10^9

(vi) 109+10910^9 + 10^9

Q16

Calculate and write the answer in scientific notation:

(i) If each person in the world had 30 pieces of clothing, find the total number of pieces of clothing.

(ii) There are about 100 million bee colonies in the world. Find the number of honeybees if each colony has about 50,000 bees.

(iii) The human body has about 38 trillion bacterial cells. Find the bacterial population residing in all humans in the world.

(iv) Total time spent eating in a lifetime in seconds.

Q17

What was the date 1 arab/1 billion seconds ago?

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