Number Play | A

Question 5

Make some more Collatz sequences like those above, starting with your favourite whole numbers. Do you always reach 11?

Do you believe the conjecture of Collatz that all such sequences will eventually reach 11? Why or why not?

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Solution
Understand the Question
  • A Collatz sequence is generated for any starting whole number nn using two simple rules:
    • If nn is even, divide it by 22: n2\dfrac{n}{2}
    • If nn is odd, multiply by 33 and add 11: 3n+13n + 1
  • We repeat the process on the resulting number until it reaches 11.
  • The Collatz Conjecture posits that every positive integer will eventually reach 11 under these rules.

(i) Make some more Collatz sequences like those above, starting with your favourite whole numbers. Do you always reach 11?

Step 1 · Collatz Sequence for 10

Starting with 1010:

  • 1010 is even     10÷2=5\implies 10 \div 2 = 5
  • 55 is odd     (3×5)+1=16\implies (3 \times 5) + 1 = 16
  • 1616 is even     16÷2=8\implies 16 \div 2 = 8
  • 88 is even     8÷2=4\implies 8 \div 2 = 4
  • 44 is even     4÷2=2\implies 4 \div 2 = 2
  • 22 is even     2÷2=1\implies 2 \div 2 = 1

10516842110 \to 5 \to 16 \to 8 \to 4 \to 2 \to 1

Step 2 · Collatz Sequence for 15

Starting with 1515:

  • 1515 is odd     (3×15)+1=46\implies (3 \times 15) + 1 = 46
  • 4646 is even     46÷2=23\implies 46 \div 2 = 23
  • 2323 is odd     (3×23)+1=70\implies (3 \times 23) + 1 = 70
  • 7070 is even     70÷2=35\implies 70 \div 2 = 35
  • 3535 is odd     (3×35)+1=106\implies (3 \times 35) + 1 = 106
  • 106106 is even     106÷2=53\implies 106 \div 2 = 53
  • 5353 is odd     (3×53)+1=160\implies (3 \times 53) + 1 = 160
  • 160160 is even     160÷2=80\implies 160 \div 2 = 80
  • 8080 is even     80÷2=40\implies 80 \div 2 = 40
  • 4040 is even     40÷2=20\implies 40 \div 2 = 20
  • 2020 is even     20÷2=10\implies 20 \div 2 = 10
  • 1010 is even     10÷2=5\implies 10 \div 2 = 5
  • 55 is odd     (3×5)+1=16\implies (3 \times 5) + 1 = 16
  • 1616 is even     16÷2=8\implies 16 \div 2 = 8
  • 88 is even     8÷2=4\implies 8 \div 2 = 4
  • 44 is even     4÷2=2\implies 4 \div 2 = 2
  • 22 is even     2÷2=1\implies 2 \div 2 = 1

15462370351065316080402010516842115 \to 46 \to 23 \to 70 \to 35 \to 106 \to 53 \to 160 \to 80 \to 40 \to 20 \to 10 \to 5 \to 16 \to 8 \to 4 \to 2 \to 1

Step 3 · Collatz Sequence for 19

Starting with 1919:

  • 1919 is odd     (3×19)+1=58\implies (3 \times 19) + 1 = 58
  • 5858 is even     58÷2=29\implies 58 \div 2 = 29
  • 2929 is odd     (3×29)+1=88\implies (3 \times 29) + 1 = 88
  • 8888 is even     88÷2=44\implies 88 \div 2 = 44
  • 4444 is even     44÷2=22\implies 44 \div 2 = 22
  • 2222 is even     22÷2=11\implies 22 \div 2 = 11
  • 1111 is odd     (3×11)+1=34\implies (3 \times 11) + 1 = 34
  • 3434 is even     34÷2=17\implies 34 \div 2 = 17
  • 1717 is odd     (3×17)+1=52\implies (3 \times 17) + 1 = 52
  • 5252 is even     52÷2=26\implies 52 \div 2 = 26
  • 2626 is even     26÷2=13\implies 26 \div 2 = 13
  • 1313 is odd     (3×13)+1=40\implies (3 \times 13) + 1 = 40
  • 4040 is even     40÷2=20\implies 40 \div 2 = 20
  • 2020 is even     20÷2=10\implies 20 \div 2 = 10
  • 1010 is even     10÷2=5\implies 10 \div 2 = 5
  • 55 is odd     (3×5)+1=16\implies (3 \times 5) + 1 = 16
  • 1616 is even     16÷2=8\implies 16 \div 2 = 8
  • 88 is even     8÷2=4\implies 8 \div 2 = 4
  • 44 is even     4÷2=2\implies 4 \div 2 = 2
  • 22 is even     2÷2=1\implies 2 \div 2 = 1

195829884422113417522613402010516842119 \to 58 \to 29 \to 88 \to 44 \to 22 \to 11 \to 34 \to 17 \to 52 \to 26 \to 13 \to 40 \to 20 \to 10 \to 5 \to 16 \to 8 \to 4 \to 2 \to 1

Answer

(i) Yes, all tested sequences always reach 11.

(ii) Do you believe the conjecture of Collatz that all such sequences will eventually reach 11? Why or why not?

Step 1 · Evaluate the Conjecture

  • Belief: Yes, it is reasonable to believe the conjecture is true based on extensive empirical evidence.
  • Reasoning:
    • Empirical Support: Billions of starting numbers have been tested by computers, and every single sequence eventually reaches 11. No counterexample has ever been found.
    • Pattern Behavior: Multiplying an odd number by 33 and adding 11 always yields an even number, which is then halved—often repeatedly—bringing the value back down.
  • Note: While it is strongly supported by observation, it remains an unproven conjecture because a formal mathematical proof for all infinitely many numbers has not yet been discovered.
Answer

(ii) Yes, the conjecture appears true because every tested number eventually reaches 11 with no counterexample found, though it remains mathematically unproven for all numbers.

Common Mistakes
  • Not Stopping at 1: Continuing after reaching 11 leads into the repeating loop 14211 \to 4 \to 2 \to 1.
  • Even/Odd Operation Swap: Accidentally dividing odd numbers or multiplying even numbers by 33.
  • Proof vs. Conjecture: Assuming that verifying many examples constitutes a formal mathematical proof.

More questions in A

Q1

Complete Table 2 with 5-digit numbers whose digits are ‘1’, ‘0’, ‘6’, ‘3’, and ‘9’ in some order. Only a coloured cell should have a number greater than all its neighbours.

The biggest number in the table is _________ . The smallest even number in the table is _________ . The smallest number greater than 50,00050,000 in the table is _________ . Once you have filled the table above, put commas appropriately after the thousands digit.

Q2

Will reversing and adding numbers repeatedly, starting with a 2-digit number, always give a palindrome? Explore and find out.*

Q3

Explore

Take different 4-digit numbers and try carrying out these steps. Find out what happens. Check with your friends what they got.

Q4

Explore

Carry out these same steps with a few 3-digit numbers. What number will start repeating?

Q5

Make some more Collatz sequences like those above, starting with your favourite whole numbers. Do you always reach 11?

Do you believe the conjecture of Collatz that all such sequences will eventually reach 11? Why or why not?

Q6

The first player says 1, 2 or 3. Then the two players take turns adding 1, 2, or 3 to the previous number said. The first player to reach 21 wins!

Play this game several times with your classmate. Are you starting to see the winning strategy? Which player can always win if they play correctly? What is the pattern of numbers that the winning player should say?

Q7

The first player says a number between 1 and 10. Then the two players take turns adding a number between 1 and 10 to the previous number said. The first player to reach 99 wins!

Play this game several times with your classmate. See if you can figure out the corresponding winning strategy in this case! Which player can always win? What is the pattern of numbers that the winning player should say this time?

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