Pair of Linear Equations in Two Variables | Exercise 3.1

Question 5

  1. Half the perimeter of a rectangular garden, whose length is 4 m4\text{ m} more than its width, is 36 m36\text{ m}. Find the dimensions of the garden.
Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution

We will use a system of two linear equations to find the garden's dimensions.

Step 1 — Define variables and form equations

Let's call the length of the garden ll.

Let's call the width of the garden ww.

The problem says the length is 4 m4\text{ m} more than its width.

l=w+4(Equation 1)l = w + 4 \quad \text{(Equation 1)}

The problem says half the perimeter is 36 m36\text{ m}.

The perimeter of a rectangle is 2(l+w)2(l + w).

So, half the perimeter is l+wl + w.

l+w=36(Equation 2)l + w = 36 \quad \text{(Equation 2)}

Step 2 — Solve for the width

We have two equations.

Let's substitute Equation 1 into Equation 2.

This will help us find the value of ww.

(w+4)+w=36(w + 4) + w = 36

2w+4=362w + 4 = 36

2w=3642w = 36 - 4

2w=322w = 32

w=322w = \frac{32}{2}

w=16 m\boxed{w = 16 \text{ m}}

Step 3 — Solve for the length

We found the width ww is 16 m.

Now we can use Equation 1 to find the length ll.

l=w+4l = w + 4

l=16+4l = 16 + 4

l=20 m\boxed{l = 20 \text{ m}}

Answer

(i) The length of the garden is 20 m20 \text{ m}. (ii) The width of the garden is 16 m16 \text{ m}.

More questions in Exercise 3.1

Q1

Form the pair of linear equations in the following problems, and find their solutions graphically.

(i) 10 students of Class X took part in a Mathematics quiz. If the number of girls is 4 more than the number of boys, find the number of boys and girls who took part in the quiz.

(ii) 5 pencils and 7 pens together cost ₹ 50, whereas 7 pencils and 5 pens together cost ₹ 46. Find the cost of one pencil and that of one pen.

Q2
  1. On comparing the ratios a1a2\frac{a_1}{a_2}, b1b2\frac{b_1}{b_2} and c1c2\frac{c_1}{c_2}, find out whether the lines representing the following pairs of linear equations intersect at a point, are parallel or coincident:

(i) 5x4y+8=05x - 4y + 8 = 0 7x+6y9=07x + 6y - 9 = 0

(ii) 9x+3y+12=09x + 3y + 12 = 0 18x+6y+24=018x + 6y + 24 = 0

(iii) 6x3y+10=06x - 3y + 10 = 0 2xy+9=02x - y + 9 = 0

Q3
  1. On comparing the ratios a1a2\frac{a_1}{a_2}, b1b2\frac{b_1}{b_2} and c1c2\frac{c_1}{c_2}, find out whether the following pair of linear equations are consistent, or inconsistent.

(i) 3x+2y=53x + 2y = 5; 2x3y=72x - 3y = 7

(ii) 2x3y=82x - 3y = 8; 4x6y=94x - 6y = 9

(iii) 32x+53y=7\frac{3}{2}x + \frac{5}{3}y = 7; 9x10y=149x - 10y = 14

(iv) 5x3y=115x - 3y = 11; 10x+6y=22-10x + 6y = -22

(v) 43x+2y=8\frac{4}{3}x + 2y = 8; 2x+3y=122x + 3y = 12

Q4
  1. Which of the following pairs of linear equations are consistent/inconsistent? If consistent, obtain the solution graphically:

(i) x+y=5x + y = 5, 2x+2y=102x + 2y = 10

(ii) xy=8x - y = 8, 3x3y=163x - 3y = 16

(iii) 2x+y6=02x + y - 6 = 0, 4x2y4=04x - 2y - 4 = 0

(iv) 2x2y2=02x - 2y - 2 = 0, 4x4y5=04x - 4y - 5 = 0

Q5
  1. Half the perimeter of a rectangular garden, whose length is 4 m4\text{ m} more than its width, is 36 m36\text{ m}. Find the dimensions of the garden.
Q6
  1. Given the linear equation 2x+3y8=02x + 3y - 8 = 0, write another linear equation in two variables such that the geometrical representation of the pair so formed is:

(i) intersecting lines

(ii) parallel lines

(iii) coincident lines

Q7
  1. Draw the graphs of the equations xy+1=0x - y + 1 = 0 and 3x+2y12=03x + 2y - 12 = 0. Determine the coordinates of the vertices of the triangle formed by these lines and the xx-axis, and shade the triangular region.
← Back to Pair of Linear Equations in Two Variables