Appendix 2: Mathematical Modelling | A2.2

Question 1

In each of the problems below, show the different stages of mathematical modelling for solving the problems.

  1. An ornithologist wants to estimate the number of parrots in a large field. She uses a net to catch some, and catches 32 parrots, which she rings and sets free. The following week she manages to net 40 parrots, of which 8 are ringed.

(i) What fraction of her second catch is ringed? (ii) Find an estimate of the total number of parrots in the field.

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Solution
Understand the Question
  • The capture-recapture method estimates an unknown total population (NN) using proportions.
  • Initial capture: 3232 parrots are caught, ringed, and released into the population.
  • Second capture: 4040 parrots are caught, out of which 88 are ringed.
  • Assuming the proportion of ringed parrots in the sample equals the proportion in the entire population:

Ringed in second catchTotal in second catch=Total ringed initiallyTotal population (N)\dfrac{\text{Ringed in second catch}}{\text{Total in second catch}} = \dfrac{\text{Total ringed initially}}{\text{Total population (} N \text{)}}

(i) What fraction of her second catch is ringed?

Step 1 · Calculate the Fraction of Ringed Parrots

From the second catch:

  • Number of ringed parrots =8= 8
  • Total parrots caught =40= 40Diagram 1
Fraction=Number of ringed parrotsTotal parrots caught=840=15\begin{aligned} \text{Fraction} &= \dfrac{\text{Number of ringed parrots}}{\text{Total parrots caught}} \\[0.6em] &= \dfrac{8}{40} \\[0.6em] &= \dfrac{1}{5} \end{aligned}
Answer

(i) 15\dfrac{1}{5}

(ii) Find an estimate of the total number of parrots in the field.

Step 1 · Estimate the Total Population

Let NN be the total estimated number of parrots in the field.

Assuming the proportion of ringed parrots in the sample equals that of the whole population:

Ringed in second catchTotal in second catch=Total ringed initiallyTotal population840=32N15=32NN=32×5N=160\begin{aligned} \dfrac{\text{Ringed in second catch}}{\text{Total in second catch}} &= \dfrac{\text{Total ringed initially}}{\text{Total population}} \\[0.6em] \dfrac{8}{40} &= \dfrac{32}{N} \\[0.6em] \dfrac{1}{5} &= \dfrac{32}{N} \\[0.6em] N &= 32 \times 5 \\[0.6em] N &= 160 \end{aligned}
Answer

(ii) 160160

Common Mistakes
  • Inverting the Proportion: Writing TotalRinged\dfrac{\text{Total}}{\text{Ringed}} on one side and RingedTotal\dfrac{\text{Ringed}}{\text{Total}} on the other. Always keep corresponding terms in the numerator and denominator consistent.
  • Direct Addition: Simply adding both catches (32+40=7232 + 40 = 72) instead of using the capture-recapture proportion to estimate the total population.

More questions in A2.2

Q1

In each of the problems below, show the different stages of mathematical modelling for solving the problems.

  1. An ornithologist wants to estimate the number of parrots in a large field. She uses a net to catch some, and catches 32 parrots, which she rings and sets free. The following week she manages to net 40 parrots, of which 8 are ringed.

(i) What fraction of her second catch is ringed? (ii) Find an estimate of the total number of parrots in the field.

Q2

In each of the problems below, show the different stages of mathematical modelling for solving the problems.

  1. Suppose the adjoining figure represents an aerial photograph of a forest with each dot representing a tree. Your purpose is to find the number of trees there are on this tract of land as part of an environmental census.
Q3
  1. A T.V. can be purchased for ₹ 24000 cash or for ₹ 8000 cashdown payment and six monthly instalments of ₹ 2800 each. Ali goes to market to buy a T.V., and he has ₹ 8000 with him. He has now two options. One is to buy TV under instalment scheme or to make cash payment by taking loan from some financial society. The society charges simple interest at the rate of 18% per annum simple interest. Which option is better for Ali?
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