The World of Numbers | Exercise 3.3

Question 2

Find the sum:

(i) 25+310\frac{2}{5} + \frac{3}{10} (ii) 712+58\frac{7}{12} + \frac{5}{8} (iii) 47+314-\frac{4}{7} + \frac{3}{14}

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Solution

We will find the sum of fractions by first finding a common denominator.

Step 1 — Sum of 25+310\frac{2}{5} + \frac{3}{10}

First, let's find the Least Common Multiple (LCM) of the denominators. The denominators are 5 and 10. The LCM of 5 and 10 is 10. Now, we convert each fraction to have a denominator of 10.

25=2×25×2\frac{2}{5} = \frac{2 \times 2}{5 \times 2}

=410= \frac{4}{10}

Next, we add the fractions with the common denominator.

410+310=4+310\frac{4}{10} + \frac{3}{10} = \frac{4+3}{10}

710\boxed{\frac{7}{10}}

Diagram 1

Step 2 — Sum of 712+58\frac{7}{12} + \frac{5}{8}

Let's find the LCM of the denominators. The denominators are 12 and 8. The LCM of 12 and 8 is 24. We convert each fraction to have a denominator of 24.

712=7×212×2\frac{7}{12} = \frac{7 \times 2}{12 \times 2}

=1424= \frac{14}{24}

58=5×38×3\frac{5}{8} = \frac{5 \times 3}{8 \times 3}

=1524= \frac{15}{24}

Now, we add these new fractions.

1424+1524=14+1524\frac{14}{24} + \frac{15}{24} = \frac{14+15}{24}

2924\boxed{\frac{29}{24}}

Step 3 — Sum of 47+314-\frac{4}{7} + \frac{3}{14}

Again, we find the LCM of the denominators. The denominators are 7 and 14. The LCM of 7 and 14 is 14. We convert the first fraction to have a denominator of 14.

47=4×27×2-\frac{4}{7} = -\frac{4 \times 2}{7 \times 2}

=814= -\frac{8}{14}

Now, we add the fractions. Remember the negative sign.

814+314=8+314-\frac{8}{14} + \frac{3}{14} = \frac{-8+3}{14}

514\boxed{-\frac{5}{14}}

Answer

(i) 710\frac{7}{10} (ii) 2924\frac{29}{24} (iii) 514-\frac{5}{14}

More questions in Exercise 3.3

Q1

Prove that the following rational numbers are equal:

(i) 23\frac{2}{3} and 46\frac{4}{6} (ii) 54\frac{5}{4} and 108\frac{10}{8} (iii) 35-\frac{3}{5} and 610-\frac{6}{10} (iv) 93\frac{9}{3} and 33

Q2

Find the sum:

(i) 25+310\frac{2}{5} + \frac{3}{10} (ii) 712+58\frac{7}{12} + \frac{5}{8} (iii) 47+314-\frac{4}{7} + \frac{3}{14}

Q3

Find the difference:

(i) 5614\frac{5}{6} - \frac{1}{4} (ii) 11834\frac{11}{8} - \frac{3}{4} (iii) 79(23)-\frac{7}{9} - \left(-\frac{2}{3}\right)

Q4

Find the product:

(i) 23×310\frac{2}{3} \times \frac{3}{10} (ii) 711×58\frac{7}{11} \times \frac{5}{8} (iii) 47×514-\frac{4}{7} \times \frac{5}{14}

Q5

Find the quotient:

(i) 23÷310\frac{2}{3} \div \frac{3}{10} (ii) 711÷58\frac{7}{11} \div \frac{5}{8} (iii) 47÷514-\frac{4}{7} \div \frac{5}{14}

Q6

Show that:

(12+34)×83=12×83+34×83\left(\frac{1}{2} + \frac{3}{4}\right) \times \frac{8}{3} = \frac{1}{2} \times \frac{8}{3} + \frac{3}{4} \times \frac{8}{3}

Q7

Simplify the following using the distributive property:

79(6734)\frac{7}{9}\left(\frac{6}{7} - \frac{3}{4}\right)

Q8

Find the rational number xx such that:

56(x+35)=56x+12\frac{5}{6}\left(x + \frac{3}{5}\right) = \frac{5}{6}x + \frac{1}{2}

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