The World of Numbers | Exercise 3.3

Question 4

Find the product:

(i) 23×310\frac{2}{3} \times \frac{3}{10} (ii) 711×58\frac{7}{11} \times \frac{5}{8} (iii) 47×514-\frac{4}{7} \times \frac{5}{14}

Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution

To multiply fractions, we multiply their numerators and their denominators.

Step 1 — Multiply the first pair

Let's find the product for part (i). We multiply the top numbers together. We multiply the bottom numbers together. Then we simplify the fraction.

23×310\frac{2}{3} \times \frac{3}{10}

=2×33×10= \frac{2 \times 3}{3 \times 10}

=630= \frac{6}{30}

15\boxed{\frac{1}{5}}

Step 2 — Multiply the second pair

Now let's solve part (ii). We multiply the numerators. We multiply the denominators. We check if we can simplify the result.

711×58\frac{7}{11} \times \frac{5}{8}

=7×511×8= \frac{7 \times 5}{11 \times 8}

3588\boxed{\frac{35}{88}}

Step 3 — Multiply the third pair

Let's find the product for part (iii). We have a negative fraction here. A negative number times a positive number is negative. We multiply the numerators. We multiply the denominators. Then we simplify the fraction.

47×514-\frac{4}{7} \times \frac{5}{14}

=4×57×14= \frac{-4 \times 5}{7 \times 14}

=2098= \frac{-20}{98}

1049\boxed{-\frac{10}{49}}

Answer

(i) 15\frac{1}{5} (ii) 3588\frac{35}{88} (iii) 1049-\frac{10}{49}

More questions in Exercise 3.3

Q1

Prove that the following rational numbers are equal:

(i) 23\frac{2}{3} and 46\frac{4}{6} (ii) 54\frac{5}{4} and 108\frac{10}{8} (iii) 35-\frac{3}{5} and 610-\frac{6}{10} (iv) 93\frac{9}{3} and 33

Q2

Find the sum:

(i) 25+310\frac{2}{5} + \frac{3}{10} (ii) 712+58\frac{7}{12} + \frac{5}{8} (iii) 47+314-\frac{4}{7} + \frac{3}{14}

Q3

Find the difference:

(i) 5614\frac{5}{6} - \frac{1}{4} (ii) 11834\frac{11}{8} - \frac{3}{4} (iii) 79(23)-\frac{7}{9} - \left(-\frac{2}{3}\right)

Q4

Find the product:

(i) 23×310\frac{2}{3} \times \frac{3}{10} (ii) 711×58\frac{7}{11} \times \frac{5}{8} (iii) 47×514-\frac{4}{7} \times \frac{5}{14}

Q5

Find the quotient:

(i) 23÷310\frac{2}{3} \div \frac{3}{10} (ii) 711÷58\frac{7}{11} \div \frac{5}{8} (iii) 47÷514-\frac{4}{7} \div \frac{5}{14}

Q6

Show that:

(12+34)×83=12×83+34×83\left(\frac{1}{2} + \frac{3}{4}\right) \times \frac{8}{3} = \frac{1}{2} \times \frac{8}{3} + \frac{3}{4} \times \frac{8}{3}

Q7

Simplify the following using the distributive property:

79(6734)\frac{7}{9}\left(\frac{6}{7} - \frac{3}{4}\right)

Q8

Find the rational number xx such that:

56(x+35)=56x+12\frac{5}{6}\left(x + \frac{3}{5}\right) = \frac{5}{6}x + \frac{1}{2}

← Back to The World of Numbers