Circles and Geometric Shapes | Exercise 5.2

Question 2

Show that if two such isosceles triangles (occurring in the previous question) have equal base length, they are congruent to each other.

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Solution

We will use the Side-Side-Side (SSS) congruence criterion to prove the triangles are congruent.

Step 1 — Identify the triangles

Let's consider two such isosceles triangles. These triangles are formed by two radii and a chord. Let the first triangle be OAB\triangle OAB. OO is the center of the circle. ABAB is the base (chord). Let the second triangle be OPQ\triangle OPQ. PQPQ is the base (chord).

Diagram 1

Step 2 — List known equalities

We know OAOA and OBOB are radii of the same circle. So, OA=OBOA = OB. We know OPOP and OQOQ are radii of the same circle. So, OP=OQOP = OQ. All radii of the same circle are equal in length. Therefore, OA=OPOA = OP. Also, OB=OQOB = OQ. The problem states that the base lengths are equal. So, AB=PQAB = PQ.

Step 3 — Apply SSS congruence criterion

Now, let's compare OAB\triangle OAB and OPQ\triangle OPQ. We have OA=OPOA = OP (radii of the same circle). We have OB=OQOB = OQ (radii of the same circle). We have AB=PQAB = PQ (given equal base length). By the SSS congruence criterion:

OABOPQ\triangle OAB \cong \triangle OPQ

Hence, if two such isosceles triangles have equal base length, they are congruent to each other.

Answer

The two isosceles triangles are congruent by the SSS criterion.

More questions in Exercise 5.2

Q1

Show that the triangle formed by a chord and the centre of the circle is isosceles.

Q2

Show that if two such isosceles triangles (occurring in the previous question) have equal base length, they are congruent to each other.

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