Rational Numbers | IT

Question 17

Find whether 11561156 and 28002800 are perfect squares using prime factorisation.

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Solution
Understand the Question
  • A number is a perfect square if each of its prime factors occurs in pairs (i.e., every prime factor has an even exponent in its prime factorisation).
  • To determine if a given number is a perfect square, find its prime factorisation and check whether all prime factors can be grouped in pairs with no single factor left over.

Step 1 · Prime Factorisation of 1156

Dividing 11561156 successively by prime numbers:Diagram 1

1156÷2=578578÷2=289289÷17=1717÷17=1\begin{aligned} 1156 \div 2 &= 578 \\ 578 \div 2 &= 289 \\ 289 \div 17 &= 17 \\ 17 \div 17 &= 1 \end{aligned}

Prime factorisation: 1156=2×2×17×171156 = 2 \times 2 \times 17 \times 17 1156=22×1721156 = 2^2 \times 17^2

All prime factors occur in pairs (all exponents are even). Therefore, 11561156 is a perfect square.

Step 2 · Prime Factorisation of 2800

Dividing 28002800 successively by prime numbers:

2800÷2=14001400÷2=700700÷2=350350÷2=175175÷5=3535÷5=77÷7=1\begin{aligned} 2800 \div 2 &= 1400 \\ 1400 \div 2 &= 700 \\ 700 \div 2 &= 350 \\ 350 \div 2 &= 175 \\ 175 \div 5 &= 35 \\ 35 \div 5 &= 7 \\ 7 \div 7 &= 1 \end{aligned}

Prime factorisation: 2800=2×2×2×2×5×5×72800 = 2 \times 2 \times 2 \times 2 \times 5 \times 5 \times 7 2800=24×52×712800 = 2^4 \times 5^2 \times 7^1

The prime factor 77 does not occur in a pair (has an odd exponent of 11). Therefore, 28002800 is not a perfect square.

Answer

11561156 is a perfect square, and 28002800 is not a perfect square.

Common Mistakes
  • Unpaired Factor Rule: Overlooking that every prime factor must have an even power. Even though 242^4 and 525^2 are paired in 28002800, the single factor 717^1 prevents it from being a perfect square.
  • Recognising Prime Squares: Failing to recognise that 289=172289 = 17^2, leading to difficulty in completing the prime factorisation of 11561156.

More questions in IT

Q1

Context: Queen Ratnamanjuri left a puzzle in her will for her son Khoisnam and 99 relatives. They are in a room with 100 lockers, numbered 1 to 100.

  • Person 1 opens every locker.
  • Person 2 toggles every 2nd locker (closes if open, opens if closed).
  • Person 3 toggles every 3rd locker (3rd, 6th, 9th, \dots).
  • Person 4 toggles every 4th locker (4th, 8th, 12th, \dots). This continues until all 100 get their turn.

Q. Before the process begins, Khoisnam realises that he already knows which lockers will be open at the end. How did he figure out the answer?

Hint: Find out how many times each locker is toggled.

Q2

Does every number have an even number of factors?

Q3

Can you use this insight to find more numbers with an odd number of factors?

Q4

Context: In a room with 100 lockers, only lockers whose numbers are square numbers remain open.

Q. Write the locker numbers that remain open.

Q5

Find the squares of the first 30 natural numbers and fill in the table below.

Q6

Context: Patterns and Properties of Perfect Squares

Find the squares of the first 30 natural numbers and fill in the table below.

Q. What patterns do you notice? Share your observations and make conjectures.

Q7

If a number ends in 0, 1, 4, 5, 6 or 9, is it always a square?

Q8

Write 5 numbers such that you can determine by looking at their units digit that they are not squares.

Q9

Let us consider square numbers ending in 6: 16=4216 = 4^2, 36=6236 = 6^2, 196=142196 = 14^2, 256=162256 = 16^2, 576=242576 = 24^2, and 676=262676 = 26^2. Which of the following numbers have the digit 6 in the units place?

(i) 38238^2 (ii) 34234^2 (iii) 46246^2 (iv) 56256^2 (v) 74274^2 (vi) 82282^2

Q10

Find more such patterns by observing the numbers and their squares from the table you filled earlier.

Q11

If a number contains 3 zeros at the end, how many zeros will its square have at the end?

Q12

What do you notice about the number of zeros at the end of a number and the number of zeros at the end of its square? Will this always happen? Can we say that squares can only have an even number of zeros at the end?

Q13

What can you say about the parity of a number and its square?

Q14

Find how many numbers lie between two consecutive perfect squares. Do you notice a pattern?

Q15

How many square numbers are there between 1 and 100? How many are between 101 and 200? Using the table of squares you filled earlier, enter the values below, tabulating the number of squares in each block of 100. What is the largest square less than 1000?

Q16

Can you see any relation between triangular numbers and square numbers? Extend the pattern shown and draw the next term.

Q17

Find whether 11561156 and 28002800 are perfect squares using prime factorisation.

Q18

How many cubes of side 1 cm1\text{ cm} make a cube of side 2 cm2\text{ cm}?

Q19

How many cubes of side 1 cm1\text{ cm} will make a cube of side 3 cm3\text{ cm}?

Q20

Is 9 a cube?

Q21

Can you estimate the number of unit cubes in a cube with an edge length of 4 units?

Q22

Complete the table below.

Q23

What patterns do you notice in the table above?

Q24

We know that 0, 1, 4, 5, 6, 9 are the only last digits possible for squares. What are the possible last digits of cubes?

Q25

Similar to squares, can you find the number of cubes with 1 digit, 2 digits, and 3 digits? What do you observe?

Q26

Can a cube end with exactly two zeroes (00)? Explain.

Q27

The next two taxicab numbers after 1729 are 4104 and 13832. Find the two ways in which each of these can be expressed as the sum of two positive cubes.

Q28

Context: Look at the following pattern of consecutive odd numbers:

1=1=133+5=8=237+9+11=27=3313+15+17+19=64=4321+23+25+27+29=125=5331+33+35+37+39+41=216=63\begin{aligned} 1 &= 1 = 1^3 \\ 3 + 5 &= 8 = 2^3 \\ 7 + 9 + 11 &= 27 = 3^3 \\ 13 + 15 + 17 + 19 &= 64 = 4^3 \\ 21 + 23 + 25 + 27 + 29 &= 125 = 5^3 \\ 31 + 33 + 35 + 37 + 39 + 41 &= 216 = 6^3 \end{aligned}

Later in this series, we get the following set of consecutive numbers:

91+93+95+97+99+101+103+105+107+10991 + 93 + 95 + 97 + 99 + 101 + 103 + 105 + 107 + 109

Q. Can you tell what this sum is without doing the calculation?

Q29

Find the cube roots of these numbers:

(i) 643=\sqrt[3]{64} =

(ii) 5123=\sqrt[3]{512} =

(iii) 7293=\sqrt[3]{729} =

Q30

Compute successive differences over levels for perfect cubes until all the differences at a level are the same. What do you notice?

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