Power Play (Exponents) | IT

Question 43

Calculate and write the answer using scientific notation:

(i) How many ants are there for every human in the world?

(ii) If a flock of starlings contains 10,000 birds, how many flocks could there be in the world?

(iii) If each tree had about 10410^4 leaves, find the total number of leaves on all the trees in the world.

(iv) If you stacked sheets of paper on top of each other, how many would you need to reach the Moon?

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Solution

We will use scientific notation to handle very large numbers easily by expressing them as a product of a number between 1 and 10 and a power of 10.

Step 1 — Ants per human

Let us find how many ants exist for each person. We need the total number of ants. We also need the total human population.

Let the estimated number of ants be NAN_A. Let the estimated human population be NHN_H. We are given NA=2×1016N_A = \mathbf{2 \times 10^{16}}. We are given NH=8×109N_H = \mathbf{8 \times 10^9}.

The number of ants per person is NA/NHN_A / N_H.

Ants per person=2×10168×109\text{Ants per person} = \frac{2 \times 10^{16}}{8 \times 10^9}

=(28)×(1016109)= \left(\frac{2}{8}\right) \times \left(\frac{10^{16}}{10^9}\right)

=0.25×10(169)= 0.25 \times 10^{(16-9)}

=0.25×107= 0.25 \times 10^7

To write this in standard scientific notation, we adjust the decimal. We move the decimal point one place to the right. This means we multiply by 10110^1 and divide by 10110^1.

=2.5×101×107= 2.5 \times 10^{-1} \times 10^7

=2.5×10(1+7)= 2.5 \times 10^{(-1+7)}

2.5×106 ants per person\boxed{2.5 \times 10^6 \text{ ants per person}}

Step 2 — Number of starling flocks

We want to find how many flocks of starlings there could be. We need the total number of starlings. We also need the number of birds in one flock.

Let the estimated number of starlings be NSN_S. Let the number of birds in a flock be NFN_F. We are given NS=3.1×1011N_S = \mathbf{3.1 \times 10^{11}}. We are given NF=10,000N_F = \mathbf{10,000}. We can write this as 10410^4.

The number of flocks is NS/NFN_S / N_F.

Number of flocks=3.1×1011104\text{Number of flocks} = \frac{3.1 \times 10^{11}}{10^4}

=3.1×10(114)= 3.1 \times 10^{(11-4)}

3.1×107 flocks\boxed{3.1 \times 10^7 \text{ flocks}}

Step 3 — Total leaves on trees

Let us calculate the total number of leaves. We need the total number of trees. We also need the number of leaves on each tree.

Let the estimated number of trees be NTN_T. Let the leaves per tree be LTL_T. We are given NT=3×1012N_T = \mathbf{3 \times 10^{12}}. We are given LT=104L_T = \mathbf{10^4}.

The total number of leaves is NT×LTN_T \times L_T.

Total leaves=(3×1012)×(104)\text{Total leaves} = (3 \times 10^{12}) \times (10^4)

=3×10(12+4)= 3 \times 10^{(12+4)}

3×1016 leaves\boxed{3 \times 10^{16} \text{ leaves}}

Step 4 — Sheets of paper to reach the Moon

We need to find how many sheets of paper would stack to the Moon. We need the distance to the Moon. We also need the thickness of one sheet of paper.

Let the distance to the Moon be DMD_M. Let the thickness of one sheet of paper be TPT_P. We are given DM=3.84×105 kmD_M = \mathbf{3.84 \times 10^5 \text{ km}}. We are given TP=0.01 cmT_P = \mathbf{0.01 \text{ cm}}.

First, we must make sure our units are the same. Let us convert the distance to the Moon into centimeters. We know that 1 km = 1000 m. We also know that 1 m = 100 cm. So, 1 km = 1000×1001000 \times 100 cm = 103×10210^3 \times 10^2 cm = 10510^5 cm.

DM=3.84×105 km×(105 cm/km)D_M = 3.84 \times 10^5 \text{ km} \times (10^5 \text{ cm/km})

=3.84×10(5+5) cm= 3.84 \times 10^{(5+5)} \text{ cm}

=3.84×1010 cm= 3.84 \times 10^{10} \text{ cm}

Now, we find the number of sheets. We divide the total distance by the thickness of one sheet.

Number of sheets=3.84×1010 cm0.01 cm\text{Number of sheets} = \frac{3.84 \times 10^{10} \text{ cm}}{0.01 \text{ cm}}

We can write 0.010.01 as 10210^{-2}.

=3.84×1010102= \frac{3.84 \times 10^{10}}{10^{-2}}

=3.84×10(10(2))= 3.84 \times 10^{(10 - (-2))}

=3.84×10(10+2)= 3.84 \times 10^{(10+2)}

3.84×1012 sheets\boxed{3.84 \times 10^{12} \text{ sheets}}

Answer

(i) There are 2.5×1062.5 \times 10^6 ants for every human in the world. (ii) There could be 3.1×1073.1 \times 10^7 flocks of starlings in the world. (iii) The total number of leaves on all the trees in the world is 3×10163 \times 10^{16}. (iv) You would need 3.84×10123.84 \times 10^{12} sheets of paper to reach the Moon.

More questions in IT

Q1

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Q2

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Q3

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Q4

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Q5

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Q6

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(i) 10v10v

(ii) 10+v10 + v

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Q7

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Q8

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Q11

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Q12

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Q13

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Q21

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Q22

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Q23

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Q26

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Q27

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Q28

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Q. Can you say which of the three distances is the smallest?

Q29

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Q30

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Q31

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Q32

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Q33

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Q34

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Q35

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Q36

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Q37

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Q38

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Q39

Context: Roxie tells Estu about a science-fiction novel she is reading where they build a ladder to reach the moon, "... I wonder if we actually had a ladder like that, how many steps would it have?".

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Q40

Context: Roxie tells Estu about a science-fiction novel she is reading where they build a ladder to reach the moon, "... I wonder if we actually had a ladder like that, how many steps would it have?".

Q. Would the number of steps be in thousands, lakhs, crores, or even more?

Q41

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Q42

With a global human population of about 8×1098 \times 10^9 and about 4×1054 \times 10^5 African elephants, can we say that there are nearly 20,000 people for every African elephant?

Q43

Calculate and write the answer using scientific notation:

(i) How many ants are there for every human in the world?

(ii) If a flock of starlings contains 10,000 birds, how many flocks could there be in the world?

(iii) If each tree had about 10410^4 leaves, find the total number of leaves on all the trees in the world.

(iv) If you stacked sheets of paper on top of each other, how many would you need to reach the Moon?

Q44

A different way to say your age!

"How old are you?" asked Estu. "I completed 13 years a few weeks ago!" said Roxie. "How old are you?" asked Estu again. "I'm 4840 days old today!" said Roxie. "How old are you?" asked Estu again. "I'm ______ hours old!" said Roxie.

Make an estimate before finding this number.

Estu: "I am 4070 days old today. Can you find out my date of birth?"

Q45

If you have lived for a million seconds, how old would you be?

Q46

10510^5 seconds 1.16\approx 1.16 days and 10610^6 seconds 11.57\approx 11.57 days. Think of some events or phenomena whose time is of the order of: (i) 10510^5 seconds (ii) 10610^6 seconds

Write them in scientific notation.

Q47

A fossil of Kelenken Guillermoi, a type of terror bird, is dated to 15 million years ago.

Q48

Plants on land started 47 crore/470 million years ago ( \approx _________________ seconds).

Q49

Calculate and write the answer using scientific notation:

(i) If one star is counted every second, how long would it take to count all the stars in the universe? Answer in terms of the number of seconds using scientific notation. (ii) If one could drink a glass of water (200 ml) every 10 seconds, how long would it take to finish the entire volume of water on Earth?

Q50

Context: Observe the names million (10610^6), billion (10910^9), trillion (101210^{12}), quadrillion (101510^{15}), quintillion (101810^{18}), sextillion (102110^{21}), septillion (102410^{24}), octillion (102710^{27}), nonillion (103010^{30}), decillion (103310^{33}).

Q. What does the first part of each name denote?

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