Power Play (Exponents) | IT

Question 46

10510^5 seconds 1.16\approx 1.16 days and 10610^6 seconds 11.57\approx 11.57 days. Think of some events or phenomena whose time is of the order of: (i) 10510^5 seconds (ii) 10610^6 seconds

Write them in scientific notation.

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Solution

We will understand the given time durations and find real-world events matching them.

Step 1 — Understanding time durations

We will convert the given time in seconds to days. This helps us understand its duration better. We know 60 seconds make 1 minute. Also, 60 minutes make 1 hour. And 24 hours make 1 day.

So, let us calculate seconds in one day: 1 day=24 hours×60 minutes/hour×60 seconds/minute1 \text{ day} = 24 \text{ hours} \times 60 \text{ minutes/hour} \times 60 \text{ seconds/minute} =86400 seconds= 86400 \text{ seconds}

The question gives these approximations: 10510^5 seconds 1.16\approx 1.16 days. 10610^6 seconds 11.57\approx 11.57 days. These help us find suitable events.

Step 2 — Events for 10510^5 seconds

We need an event lasting about 10510^5 seconds. This is about 100,000100,000 seconds, or 1.161.16 days. A very long train journey, lasting about 1.5 days, is a good example.

Let us calculate the duration of 1.5 days in seconds: 1.5 days=1.5×86400 seconds1.5 \text{ days} = 1.5 \times 86400 \text{ seconds} =129600 seconds= 129600 \text{ seconds}

1.296×105 seconds\boxed{1.296 \times 10^5 \text{ seconds}} This value is of the order of 10510^5 seconds. Another example is the time taken for a large project to complete its initial phase.

Step 3 — Events for 10610^6 seconds

We need an event lasting about 10610^6 seconds. This is about 1,000,0001,000,000 seconds, or 11.5711.57 days. A typical school term break fits this. A long holiday trip is also suitable.

Let us consider a holiday trip of 12 days. We will calculate its duration in seconds: 12 days=12×86400 seconds12 \text{ days} = 12 \times 86400 \text{ seconds} =1036800 seconds= 1036800 \text{ seconds}

1.0368×106 seconds\boxed{1.0368 \times 10^6 \text{ seconds}} This value is very close to 10610^6 seconds. Another example is the time for the Moon to complete about half of its phases.

Answer

(i) Events or phenomena whose time is of the order of 10510^5 seconds: A very long train journey (e.g., 1.5 days): 1.296×1051.296 \times 10^5 seconds. The time for a large project's initial phase (e.g., 1.5 days): 1.296×1051.296 \times 10^5 seconds.

(ii) Events or phenomena whose time is of the order of 10610^6 seconds: A typical school term break (e.g., 12 days): 1.0368×1061.0368 \times 10^6 seconds. A long holiday trip (e.g., 12 days): 1.0368×1061.0368 \times 10^6 seconds.

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Write them in scientific notation.

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