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Question 13

Write the result obtained by— (a) adding 1 to every term in the generalised form. (b) doubling every term in the generalised form

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Solution

We will perform two operations on a given set of algebraic expressions.

Step 1 — Identifying the Generalised Form

Let us first write down the given generalised form. It is a set of numbers using a variable 'm'.

(m+3m4m+1m2mm+2m1m+4m3)\begin{pmatrix} m + 3 & m - 4 & m + 1 \\ m - 2 & m & m + 2 \\ m - 1 & m + 4 & m - 3 \end{pmatrix}

Step 2 — Adding 1 to Every Term

We need to add the number 1 to each term. This means we add 1 to every expression.

For the first term in Row 1: (m+3)+1(m + 3) + 1 =m+4= m + 4

For the second term in Row 1: (m4)+1(m - 4) + 1 =m3= m - 3

For the third term in Row 1: (m+1)+1(m + 1) + 1 =m+2= m + 2

For the first term in Row 2: (m2)+1(m - 2) + 1 =m1= m - 1

For the second term in Row 2: (m)+1(m) + 1 =m+1= m + 1

For the third term in Row 2: (m+2)+1(m + 2) + 1 =m+3= m + 3

For the first term in Row 3: (m1)+1(m - 1) + 1 =m= m

For the second term in Row 3: (m+4)+1(m + 4) + 1 =m+5= m + 5

For the third term in Row 3: (m3)+1(m - 3) + 1 =m2= m - 2

So, the new generalised form after adding 1 to each term is:

\begin{pmatrix} m + 4 & m - 3 & m + 2 \ m - 1 & m + 1 & m + 3 \ m & m + 5 & m - 2 \end{pmatrix} }$$

Step 3 — Doubling Every Term

Now, we need to double each term. This means we multiply every expression by 2.

For the first term in Row 1: 2×(m+3)2 \times (m + 3) =2m+6= 2m + 6

For the second term in Row 1: 2×(m4)2 \times (m - 4) =2m8= 2m - 8

For the third term in Row 1: 2×(m+1)2 \times (m + 1) =2m+2= 2m + 2

For the first term in Row 2: 2×(m2)2 \times (m - 2) =2m4= 2m - 4

For the second term in Row 2: 2×(m)2 \times (m) =2m= 2m

For the third term in Row 2: 2×(m+2)2 \times (m + 2) =2m+4= 2m + 4

For the first term in Row 3: 2×(m1)2 \times (m - 1) =2m2= 2m - 2

For the second term in Row 3: 2×(m+4)2 \times (m + 4) =2m+8= 2m + 8

For the third term in Row 3: 2×(m3)2 \times (m - 3) =2m6= 2m - 6

So, the new generalised form after doubling each term is:

\begin{pmatrix} 2m + 6 & 2m - 8 & 2m + 2 \ 2m - 4 & 2m & 2m + 4 \ 2m - 2 & 2m + 8 & 2m - 6 \end{pmatrix} }$$

Answer

(a) Adding 1 to every term: Row 1: m + 4, m - 3, m + 2 Row 2: m - 1, m + 1, m + 3 Row 3: m, m + 5, m - 2 (b) Doubling every term: Row 1: 2m + 6, 2m - 8, 2m + 2 Row 2: 2m - 4, 2m, 2m + 4 Row 3: 2m - 2, 2m + 8, 2m - 6

More questions in FIO

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Q5

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Q18

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Q20

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