Finding Common Ground | IT

Question 4

Is the longest jump size for the numbers the same as their HCF? Explain why it is so.

Check your answer with HomiSolve it yourself, then let Homi check your steps and spot mistakes.
Solution
Understand the Question
  • Taking equal jumps of size ss from 00 on a number line lands on a number NN only if ss divides NN exactly (i.e., ss is a factor of NN).
  • To land on multiple numbers simultaneously with the same jump size, the jump size must divide all of them (i.e., it must be a common factor).
  • Therefore, the longest possible jump size is the greatest number that divides all of them, which by definition is the Highest Common Factor (HCF).

Step 1 · Understand Jump Size as a Factor

To land on a number starting from 00 with equal-sized jumps, the jump size must divide the number completely.Diagram 1

For example, consider the numbers 1212 and 1818:

  • Possible jump sizes to reach 1212 (factors of 1212): {1,2,3,4,6,12}\{1, 2, 3, 4, 6, 12\}
  • Possible jump sizes to reach 1818 (factors of 1818): {1,2,3,6,9,18}\{1, 2, 3, 6, 9, 18\}

To reach both 1212 and 1818, the jump size must be a common factor: Common factors={1,2,3,6}\text{Common factors} = \{1, 2, 3, 6\}

The longest jump size is the greatest common factor, which is 66.

Step 2 · Relate Longest Jump Size to HCF

By mathematical definition:

  • A factor divides a number exactly.
  • A common factor divides all given numbers.
  • The Highest Common Factor (HCF) is the largest common factor among them.

Since the jump size must be a common factor, the longest jump size is the highest common factor: Longest Jump Size=HCF\text{Longest Jump Size} = \text{HCF}

For 1212 and 1818: HCF(12,18)=6\text{HCF}(12, 18) = 6 This matches the longest jump size.

Answer

Yes, the longest jump size for the numbers is the same as their HCF.

Common Mistakes
  • Confusing HCF and LCM: HCF is the largest step size that divides the numbers, whereas LCM is the first destination number where steps of different sizes meet.
  • Considering Any Common Factor: While any common factor allows landing on all numbers, only the longest jump size corresponds to the HCF.

More questions in IT

Q1

Context: Sameeksha is building her new house. The main room of the house is 12 ft12\text{ ft} by 16 ft16\text{ ft}. She wants to cover the floor with square tiles of the same size, using as few tiles as possible, with the length of the tile being a whole number of feet. She needs tiles of size 4 ft4\text{ ft}.

Q. How many tiles of this size should she purchase?

What if Sameeksha did not insist on the length of the tile to be a whole number of feet and the length could be a fractional number of feet? Would the answer change?

Q2

Context: Lekhana bought 84 kg84\text{ kg} of rice from one farm and 108 kg108\text{ kg} from another. She wants to pack them in bags of equal weight (whole number of kg\text{kg}) using as few bags as possible. The common factors of 8484 and 108108 are 1,2,3,4,61, 2, 3, 4, 6, and 1212.

Q. Which weight should she choose to minimise the number of bags?

Q3

Do you remember the ‘Jump Jackpot’ game from Grade 6 (see the chapter ‘Prime Time’)? Grumpy places a treasure on a number and Jumpy chooses a jump size and tries to collect the treasure. In each case below, the two numbers upon which treasures are kept are given. Find the longest jump size (starting from 0) using which Jumpy can land on both the numbers having the treasure.

(a) 14 and 30

(b) 7 and 11

(c) 30 and 50

(d) 28 and 42

Q4

Is the longest jump size for the numbers the same as their HCF? Explain why it is so.

Q5

Can this process be simplified? Can it be made more reliable?

Q6

Can you see what is happening below?

Q7

Can you write the prime factorisation of 105105 and 3030 using these two figures?

Q8

Try finding the prime factorisation of 1200 using the method above. If we had used the earlier method, our calculation would have been as follows:

1200=40×30=5×8×5×6=1200 = 40 \times 30 = 5 \times 8 \times 5 \times 6 = \dots

Which calculation is easier to carry out?

Q9

Context: Consider the number 840 and its prime factorisation 2×2×2×3×5×72 \times 2 \times 2 \times 3 \times 5 \times 7.

Q. Is 2×2×7=282 \times 2 \times 7 = 28 a factor of 840?

Q10

Context: Consider the number 840 and its prime factorisation 2×2×2×3×5×72 \times 2 \times 2 \times 3 \times 5 \times 7.

Q. If yes, what should it be multiplied by to get 840?

Q11

Context: Consider the number 840 and its prime factorization 2×2×2×3×5×72 \times 2 \times 2 \times 3 \times 5 \times 7.

Similarly, is 2×7=142 \times 7 = 14 a factor of 840? Why or why not?

Is 2×2×22 \times 2 \times 2 a factor of 840? Why or why not?

Is 3×3×33 \times 3 \times 3 a factor of 840? Why or why not?

Can we use this idea to list down all the possible factors of a number using just its prime factors?

Q12

Context: The factors of 225 are found to be 1, 3, 5, 9, 15, 25, 45, 75, 225.

Q. Check that all the factors of 225 occur in this list.

Q13

Do you remember the ‘Idli-Vada’ game from Grade 6 (see chapter ‘Prime Time’)? Two numbers are chosen and whenever players come to their multiples, ‘idli’ or ‘vada’ should be called out depending on whose multiple the number is. If the number happens to be a common multiple, then ‘idli-vada’ should be called out. In each problem below, the two numbers corresponding to ‘idli’ and ‘vada’ are given. Find the first number for which ‘idli-vada’ will be called out:

(a) 4 and 6

(b) 7 and 11

(c) 14 and 30

(d) 15 and 55

Is the answer always the LCM of the two numbers? Explain.

Q14

Context: Consider the numbers 14 and 35, with prime factorisations 14=2×714 = 2 \times 7 and 35=5×735 = 5 \times 7.

Q. Is 2×3×5×72 \times 3 \times 5 \times 7 also a common multiple?

Q15

Find more such number pairs where the HCF is one of the two numbers. How can we describe such pairs of numbers?

Q16

Context: If nn is a number, then any multiple of nn can be written as a positive integer multiplied by nn. For example, if we take nn and 5n5n (short for 5×n5 \times n), then 5n5n is a multiple of nn, and nn is a factor of 5n5n. The HCF of nn and 5n=n5n = n.

Q. For number pairs satisfying this property (i.e., one of the numbers is the HCF),

(a) if mm is a number, what could be the other number?

(b) if 7k7k is a number, what could be the other number?

Q17

What happens to the HCF of two numbers if both numbers are doubled? Take some pairs of numbers and explore. Are you able to see why the HCF will also double?

Q18

Here are some more numbers where both numbers are multiples of the same number. Find their HCF:

(a) 18×1018 \times 10, 18×1518 \times 15

(b) 10×3810 \times 38, 10×2110 \times 21

(c) 5×135 \times 13, 5×205 \times 20

(d) 12×1612 \times 16, 12×2012 \times 20

Q19

In which of these cases is the HCF the same as the common multiplier, like problem (b) where the HCF is 10? Explore a few more examples of this type to understand when this happens.

Q20

Efficient Procedures for HCF and LCM

See the procedure on the right. Can you explain how it has been carried out?

Q21

How do we use this to find the HCF of 84 and 180? Explore.

[Hint: Observe that 84=2×2×3×784 = 2 \times 2 \times 3 \times 7, and 180=2×2×3×15180 = 2 \times 2 \times 3 \times 15 similar to prime factorisation]

Q22

Why are these the LCMs?

[Hint: Will the product of the factors marked as the LCM of 300 and 150 contain the prime factorisations of both 300 and 150? Is this the smallest such number?]

Q23

You can try this method for these pairs of numbers.

(a) 90 and 150

(b) 84 and 132

Q24

Property Involving both the HCF and the LCM

Which is greater — the LCM of two numbers or their product?

Q25

You could analyse the above statement using examples. Then try to reason or prove, why the LCM is never greater than the product of the numbers.

[Hint: Is the product also a common multiple of the two numbers?]

Q26

Explore whether the LCM is a factor of the product in the following cases. If yes, identify the number that the LCM should be multiplied by to get the product. Do you see any pattern? Use these numbers:

(a) 45, 105

(b) 275, 352

(c) 222, 370

Q27

Context: Consider the pairs of numbers: (a) 45, 105; (b) 275, 352; (c) 222, 370.

Q. Do you see that, in each case, the number by which the LCM is multiplied to get the product is actually the HCF?

Q28

Why does this happen? Can you give an explanation or proof?

[Hint: Consider the prime factorisation of the given numbers. Among their prime factors, some are common to both factorisations, and the rest occur in only one of them. Between the HCF and the LCM, see how the common and non-common prime factors get distributed. In the product, observe how these two kinds of prime factors occur. Compare them.]

Q29

Explore whether this property holds when 3 numbers are considered.

Q30

Context: The largest prime found so far has 4,10,24,320 digits! It was discovered on October 12, 2024.

Q. If I start writing this number, how long could it take me?

← Back to Finding Common Ground